the sides of a triangle have lengths of x, x+5, and 25. if the longest side is 25, which of the following values of x would make the right triangle?

Answers

Answer 1

Answer: $x^2+5x-300=0 \n \n \Delta =b^2-4ac =5^2 -4*1* (- 300)= 25+1200=1225 \n \nx_(1)=(-b- √(\Delta ) )/(2a)=(-5- √(1225))/(2 )=(-5-35)/(2)=-(-40)/(2)=-20 \n\n \ side \ not \ can \ also \ be \ negative$

$x_(2)=(-b+ √(\Delta ) )/(2a)=(-5+ √(1225))/(2 )=(-5+35)/(2)=-(30)/(2)=15\n \nAnsewr : \ x= 15$

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Answers

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1: Plot the graph of the equation 2x-3y=6 and 2x+y=-10 and intercept the result.

Answers

To graph the equations, rewrite the equations written in standard form to slope-intercept form of the equation.

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There is 1 other part to this pls help asap

Answers

Answer:

Step-by-step explanation:

As show in the photo, x+87 is equivalent to 4x.

If you multiply a number by four and then subtract negative ten, the difference is negative eighteen. What
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Answers

Let's call the number ' Q '.

The question says that (4Q) - (-10) = -18

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4Q = -28

Divide each side by 4 :

Q = -7

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Answers

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