Answer:
The answer is A. 15, 30, 45, 60, 75
Step-by-step explanation:
i clicked D like the "expert" said and got it wrong
A) always
B) sometimes
C) never
the function is x^2-9, so all you have to do is replace x with a number. for example, 2.
so 2^2-9 is -5. the plot would be 2, -5. basically, plug in a number to be the x coord, and whatever number you get will be your y coord.
after you graph a few plots (doing the same thing above), draw a line through all of them.
if the line goes up towards the right top corner, it's increasing. if it goes down the right bottom corner, it's decreasing.
b. $16,058.71
c. $31,120.46
d. $32,987.69
Answer:
option A
Step-by-step explanation:
given,
Korey expects to average $1,000 of profit each month
first year profit from the comic book store = $1000 × 12
= $12,000
now for next four year profit will increase by 6%
Second year profit: $12,000 × 1.06
Third year profit: $12,000 × 1.06²
Fourth year profit: $12,000 × 1.06³
Fifth year profit: $12,000 × 1.06⁴
=$15,149.72
Profit of Korey expected after fifth year is equal to $15,149.72.
Hence the correct answer is option A
Answer:
A! Took the test on edge
Step-by-step explanation:
The answer is 510, Im glad I can help! Enjoy the test!
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nbarrera
Algebra Help Please! anyone! Will MEDAL!
Which argument is valid?
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A. If a polygon is a square, it has four right angles.
If a polygon is a rectangle, then it has four right angles.
If a polygon is a rectangle, then it is a square.
B. If a number is divisible by 12, then it is divisible by 6.
If a number is divisible by 6, then it is divisible by 2.
If a number is divisible by 12, then it is divisible by 2
C. If it is a dog, then it barks.
If it has a tail, then it is an animal.
If it is a dog, then it barks and has a tail.
D. If an animal can swim, then it has fins.
If an animal is a fish, then it has fins.
If an animal can swim, then it is a fish.
of the remaining children get off, leaving the bus only half full.
How many children were on the bus at the start?
Answer:
12
Step-by-step explanation:
If there are x children on the bus at the start, after the first stop, there are (x-3) remaining. After two stops, the number on the bus is ...
x/2 = x -3 -(1/3)(x -3)
Multiplying by 6, we have ...
3x = 6x -18 -2(x -3)
3x = 4x -12 . . . . simplify
12 = x . . . . . . . . add 12-3x
There were 12 children on the bus at the start.
_____
Check
After 3 got off at the first stop, there were 12-3 = 9 remaining. 1/3 of those, or 9/3=3 got off at the second stop, so 9 -3 = 6 remained. This is half the original number, as required.
Let X represent the number of children on the bus originally. The equation formed is 2/3*(X - 3) = X/2, and when we solve it, we find that X equals 12 which indicates that there were 12 children on the bus at the start.
Let's denote the number of children on the bus at the start as X. After the first stop, the number of children on the bus became X - 3, because 3 children got off. After the second stop, a third of the remaining children got off, so the number of children on the bus became 2/3*(X - 3). According to the problem, after all the stops, the bus was half full. Therefore, we can set up an equation: 2/3*(X - 3) = X/2.
To solve the equation, we can multiply all terms by 6 to clear out the fractions and obtain the equation: 4*(X - 3) = 3X. This simplifies to 4X - 12 = 3X which simplifies further to X = 12, meaning there were initially 12 children on the bus.
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