Find the area of a regular hexagon with the given measurement48-inch perimeter
A = sq. in.

Answers

Answer 1
Answer:

Answer

Area of a regular hexagon is given by:

A = (3√(3))/(2)a^2            .....[1]

where,

A is the area of a regular hexagon

a is the side of the hexagon.

As per the statement:

Perimeter of a regular hexagon is 48 inch.

Perimeter(P) of a regular hexagon is given by:

P=6a

Substitute the given values we have;

48 = 6a

Divide both sides by 6 we have;

8 = a

or

a = 8 inch.

Substitute the value of a = 8 inches  in [1] we have;

A = (3√(3))/(2)(8)^2

A = 3√(3) \cdot 32 = 96√(3)

Therefore, the area of a regular hexagon isA = 96√(3) sq. in

Answer 2
Answer: Area = (3 √(3) )/(2) s^(2) \n \n (48)/(6) = 8=s \n \n Area =(3 √(3) )/(2) 64 \n \n Area =166.28

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A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal force n acting on the car when it is at the top of the arc. (Use any variable or symbol stated above along with the following as necessary: m and g.) n

What is the length of the altitude of the equilateral triangle below

Answers

The solution is, The length of the altitude of the equilateral triangle is 9.

What are trigonometric relations?

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

here, we have,

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

here, we have,

The given triangle is an equilateral triangle.

Here, a is a median which bisects the base. It also serves as an altitude, as it is an equilateral triangle.

As the triangle can be divided into two right angle triangle,

Using Sine.

Sine = Opposite / Hypotenuse

sin 60° = a / (6√3)                        

But sin60° = √3/2

so, we get,

√3/2 = a/(6√3)

Cross multiply

2*a = 6√3 * √3

2a = 6 * √(3*3)

2a = 6*3

a = 6*3/2

a = 3*3

  = 9

Hence, Option E. The solution is, The length of the altitude of the equilateral triangle is 9.

To learn more about trigonometric relations click :

brainly.com/question/14450671

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Using Sine.

Sine = Opposite / Hypotenuse

sin 60° = a / (6√3)                        But sin60° = √3/2

√3/2 = a/(6√3)

Cross multiply

2*a = 6√3 * √3

2a = 6 * √(3*3)

2a = 6*3

a = 6*3/2

a = 3*3 = 9

Option E.

Hope this helps.

You spin the spinner below once what is the probability that the arrow will land on 3

Answers

I saw the spinner. It has 8 numbers from 1 to 8.

probability that the arrow will land on 3.

1, 2, 3, 4, 5, 6, 7, 8

P(A) = the number of ways event A can occur
           the total number of possible outcomes 

P(3) = 1/8

There is only 1 number 3 out of 8 possible outcomes.

Answer:

0.125

Step-by-step explanation:

1/8 as a decimal is 0.125. I think this is the answer but I am not 100% positive.

One container holds 1 1/7 quarts of water and second container holds 5 3/4 quarts of water how many more harts of water does the second container hold then the first

Answers

Answer:

129/28 (4.6 approx.)

Step-by-step explanation:

The first hols 1 1/7 quarts, it is: 1 + 1/7

Using 7 as common denominator and summing:

1 + 1/7 = 7/7 + 1/7 = 8/7

The second holds 5 3/4 which is: 5 + 3/4. Using 4 as common denominator:

5 + 3/4 = 20/4 + 3/4 = 23/4

Now we need to know how much greater is 23/4 than 8/7. For comparing them we need to set them to a common denominator. The easiest way is use a number that is multiple of both, 4 and 7, lets us 28. We need to multiply the numerators by the number that, multiplied by denominators gives us 28. For the first is 4, and for the second 7.

8/7 = (8*4)/7*4=32/28

23/4= (23*7)/4*7 = 161/28

Now, we only have to subtract:

23/4 - 8/7 = 161/28 - 32/28 = 129/28

So, the second container has 129/28 more quarts of water (approx. 4.60) than the first.

Figure WXYZ ~ figure WꞌXꞌYꞌZꞌ.

What is the value of a?

Answers

8/2=16/a
cross multiplying
8a=32
a=32/8
a=4
Hey do you remember the answer possibly? I have the same question and I've tried but I don't think I'm doing it correctly. :(

Explain why 1.19 is the greatest amount of money it is possible to have without being able to make change for a dollar

Answers

Hello,

There are only 2 solutions for $1.19

In cents:
119=1*25+9*10+0*5+4*1
119=3*25+4*10+0*5+4*1

Thus
120=119+1=(1*25+9*10+0*5+4*1) +1 =1*25+9*10+0*5+5*1
but 1*25+7*10+0*5+5*1=100

120=119+1=(3*25+4*10+0*5+4*1)+1=3*25+4*10+0*5+5*1
but 3*25+2*10+0*5+5*1=100

So there are no solution for $1.20


Factor completely. n ^4 - 1

Answers

Answer: Hello there!

here we have the equation n^4 - 1

using the relation: (a^(2) - b^(2)) = (a+b)*(a-b)

we can write our equation as:

(n^(4) - 1) = ((n^(2) )^(2) -1^(2) ) = (n^(2) + 1)(n^(2) - 1) = (n^(2) + 1)(n + 1)(n-1)

and (n^2 + 1) has only complex roots, i and - i, then we can factorize this as (n -i)(n + i) = n*n + ni - ni (+i)*(-i) = (n^2 + 1)

then our equation is: (n^(2) + 1)(n + 1)(n-1) =  (n + i)(n - i)(n + 1)(n-1)

(n^4 - 1) = (n^2 - 1) (n^2 +1) = (n - 1) (n + 1) (n^2 + 1)