MATHEMATICS HIGH SCHOOL

hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.

Answers

Answer 1

Answer:

Answer:

$2√(6)$

Step-by-step explanation:

Perimeter of equilateral triangle = 36 inches

Formula of perimeter of equilateral triangle = $3* side$

⇒ $36=3* side$

⇒ $(36)/(3) = side$

⇒ $12= side$

Thus each side of equilateral triangle is 12 inches

Formula of area of equilateral triangle = $(√(3))/(4) a^(2)$

Where a is the side .

So, area of the given equilateral triangle = $(√(3))/(4) * 12^(2)$

= $36√(3)$

Since hexagon can be divided into six small equilateral triangle .

So, area of each small equilateral triangle = $(36√(3))/(6)$

= $6√(3)$

So, The area of small equilateral triangle :

$(√(3))/(4)a^(2) =6√(3)$

Where a is the side of hexagon .

$(1)/(4)a^(2) =6$

$a^(2) =6* 4$

$a^(2) =24$

$a =√(24)$

$a =2√(6)$

Hence the length of a side of the regular hexagon is $2√(6)$

Answer 2

Answer: $Perimter\ of\ equilateral\ triangle\ =36\n a- \ side\ of\ triangle\n 36=3a\ |:3\n a=12\n\n Area\ of\ equilateral\ triangle:\n A=(a^2√(3))/(4)\n A=(12^2√(3))/(4)\n A=(144√(3))/(4)=36\sqrt3 \n\n Hegagon\ can\ be\ divided\ into\ 6\ equilateral\ small\ triangles.\nArea\ of\ one\ of\ them: A_s=(A)/(6)=(36\sqrt3)/(6)=6√(3)\n s-side\ of\ equilateral\ =\ side\ of\ small\ triangle\n A_s=(s^2√(3))/(4)=6√(3)\ |*4 \n s^2\sqrt3=24\sqrt3\ |\sqrt3\n s^2=24\n s=√(24)$ $√(24)=√(4*6)=2\sqrt6\n\n Side\ of\ hexagon\ equals\ 2\sqrt6\ inches$

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