FIRST ANSWER IS BRAINIEST TAKE YOUR TIME I NEED RIGHT ANSWERS FIRST ANSWER IS BRAINIEST ANSWER TAKE YOUR TIME NEED RIGHT ANSWER FIRST ANSWER IS BRAINIEST TAKE YOUR TIME I NEED RIGHT ANSWERS FIRST ANSWER IS BRAINIEST ANSWER TAKE YOUR TIME NEED RIGHT ANSWERDrag the item from the item bank to its corresponding match.


A.Commensalism
B.Consumer
C.Decomposer
D.Host
E.Mutualism
F.Parasite
G.Predator
H.Prey
I.Producer
J.Symbiosis




1.This is an organism which feeds on, but usually does not kill, a larger organism.

2.This is an animal that lives by preying on other animals.

3.This is an interdependent relationship between two different species.

4.is an organism that relies on other organisms for its food and energy supply; also
called a heterotroph.

5.This is an organism that breaks down and gains nutrients from dead organisms.

6.This is an organism that supplies matter and energy, also known as an autotroph.

7.This is the interaction of two organisms where one is helped and the other is neither helped nor harmed.

8.This is the interaction of two organisms where both benefit.

9.An organism that harbors a parasite, mutual partner, or commensal partner, typically providing nourishment and shelter.

10.An animal that is killed and eaten by another animal.

Answers

Answer 1
Answer:

Answer:

1-F; 2-G; 3-J; 4-B; 5-C; 6-I; 7-A; 8-E; 9-D; 10-H.

Explanation:

1.This is an organism which feeds on, but usually does not kill, a larger organism. F. Parasite

2.This is an animal that lives by preying on other animals.G. Predator

3.This is an interdependent relationship between two different species.J. Symbiosis

4. is an organism that relies on other organisms for its food and energy supply; also called a heterotroph. B. Consumer  

5.This is an organism that breaks down and gains nutrients from dead organisms. C. Decomposer  

6.This is an organism that supplies matter and energy, also known as an autotroph. I. Producer  

7.This is the interaction of two organisms where one is helped and the other is neither helped nor harmed. A. Commensalism  

8.This is the interaction of two organisms where both benefit. E. Mutualism  

9. An organism that harbors a parasite, mutual partner, or commensal partner, typically providing nourishment and shelter.D. Host

10.An animal that is killed and eaten by another animal. H. Prey

Answer 2
Answer: A = 7
B = 4
C = 5
D = 9
E = 8
F = 1
G = 2
H = 10
I = 6
J = 3

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Your boss asks you to compare two sound waves and determine which has a higher frequency. Wave A has a period o 4/100 second and Wave B has a period of 1/7 second. What would you tell your boss? A. Wave A has the higher frequency. It's frequency is 4 Hz
B. Wave A has the higher frequency. It's frequency is 25 Hz
C. Wave B has the higher frequency. It's frequency is 42 Hz
D. Wave B has the higher frequency. It's frequency is 7 Hz

Answers

Wave A has a higher frequency and that frequency is 25 Hz. This can be determined by taking the time span and dividing it by the number of waves/second. 100 divided by 4 is 25. 7 divided by 1 is 7. 25 Hz is higher than 7 Hz.

Answer:

B

Explanation:

Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012W) pulses of light that last for an extremely short time (a few nanoseconds). These short pulses scramble the interior of a cell without causing it to explode, as long pulses would do. We can model a typical such cell as a disk 5.0μm in diameter, with the pulse lasting for 4.0 ns with an average power of 2.0×1012W. We shall assume that the energy is spread uniformly over the faces of 100 cells for each pulse. (a) How much energy is given to the cell during this pulse? (b) What is the intensity (in W/m2) delivered to the cell? (c) What are the maximum values of the electric and magnetic fields in the pulse?

Answers

Answer:

a. 80 J/cell b. 1.02 × 10²¹ W/m² c. 8.77 × 10¹¹ V/m d. 2.92 × 10³ T

Explanation:

a. We know that energy E = Pt where P = power and t = time

The total energy delivered to all the 100 cells is E = average power × time

average power = 2 × 10¹² W and time = 4 ns = 4 × 10⁻⁹ s

E = 2 × 10¹² W × 4 × 10⁻⁹ s = 8 × 10³ J

The energy per cell E₁ = E/100 = 8 × 10³ J/100 = 80 J/cell

b. Intensity, I = P/A where P = power per cell = 2 × 10¹² W/100 = 2 × 10¹⁰ W and A = area = πr². Since the cell is modeled as a disk of diameter d = 5.0μm, r = d/2 = 5.0 μm/2 = 2.5 μm = 2.5 × 10⁻⁶ m

I = P/A = P/πr² = 2 × 10¹⁰ W/π(2.5 × 10⁻⁶ m)² = 1.02 × 10²¹ W/m²

c. The intensity I = E²/2cμ₀ where E = maximum value of electric field, c = speed of light = 3 × 10⁸ m/s and μ₀ = 4π × 10⁻⁷ H/m

E = √(I2cμ₀) = √(2 × 1.02 × 10²¹ W/m² × 3 × 10⁸ m/s × 4π × 10⁻⁷ H/m) = 8.77 × 10¹¹ V/m

The maximum magnetic field B is gotten from E/B = c

B = E/c = 8.77 × 10¹¹ V/m/3 × 10⁸ m/s  = 2.92 × 10³ T

A carousel is spinning at a speed of 100 cm/s, with the outermost horse at a distance 5 m from the center.Calculate the inward force on the outermost horse, if it weighs 1.5 kg.

A) 3 x 10-3 N
B) 3 x 10-2 N
C) 3 x 10-1 N
D) 3 x 10 N

Answers

The speed is 100/100=1 meter per second, so acceleration is 1^2/5=.2.  Then, the net force is 0.2*1.5 kg = 0.3 N, or 3*10^-1 N.

a balloon is ascending at 3.0 m/s at a height of 20.0 m above ground when a package is released. the time taken, in the absence of air resistance, for the package to reach the ground is:

Answers

Answer:

Approximately 2.35\; {\rm s}, assuming that g = 9.81\; {\rm m\cdot s^(-2)}.

Explanation:

Under the assumptions, the package would start with an initial upward velocity of u = 3.0\; {\rm m\cdot s^(-1)} and accelerate downward at a constant a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)} (negative because acceleration points downward.)

Right before landing, the package would be 20.0\; {\rm m} below where it was released. Hence, the displacement of the package at that moment would be x = (-20.0)\; {\rm m} (negative since this position is below the initial position.)

The duration of the motion can be found in the following steps:

  • Apply the SUVAT equation v^(2) - u^(2) = 2\, a\, x to find velocity v right before landing.
  • Divide the change in velocity (v - u) by acceleration to find the duration of the motion.

Rearrange the SUVAT equation v^(2) - u^(2) = 2\, a\, x to find v, the velocity of the package right before reaching the ground. Notice that because the package would be travelling downward, the value of v\! should be negative.

\begin{aligned} v &= -\sqrt{u^(2) + 2\, a\, x} \n &= -\sqrt{(3.0)^(2) + 2\, (-9.81)\, (-20.0)}\; {\rm m} \n &\approx (-20.035)\; {\rm m}\end{aligned}.

Subtract the initial velocity from the new value to find the change in velocity. Divide this change in velocity by acceleration (rate of change in velocity) to find the duration of the motion:

\begin{aligned}t &= (v - u)/(a) \n &\approx ((-20.035) - (3.0))/((-9.81))\; {\rm s} \n &\approx 2.35\; {\rm s}\end{aligned}.

Explain why it’s hurt more carrying a heavy bag with a string of wire

Answers

Explanation:

Carrying a heavy bag with a string of wire can cause more pain compared to carrying a bag without a string of wire due to a few reasons.

Firstly, the presence of the string of wire adds additional pressure and strain on your hand, making it harder to grip and carry the bag comfortably. The wire can dig into your skin and cause discomfort or even pain. Imagine holding a bag with a smooth handle versus holding a bag with a sharp wire cutting into your hand - the latter would definitely be more painful.

Secondly, the wire can create friction against your skin. As you carry the bag and walk, the movement can cause the wire to rub against your hand, resulting in irritation and potentially even blisters. This friction can also cause the wire to dig deeper into your skin, intensifying the pain.

Lastly, the weight distribution of the bag can be affected by the presence of the wire. When you carry a heavy bag, it is ideal for the weight to be evenly distributed to minimize strain on specific areas of your body. However, the wire can create an uneven distribution of weight within the bag. This can lead to increased pressure and discomfort on certain parts of your hand, making it more painful to carry the bag.

In summary, carrying a heavy bag with a string of wire can hurt more due to the additional pressure and strain on your hand, the friction caused by the wire rubbing against your skin, and the uneven weight distribution within the bag. It is important to consider these factors when carrying heavy objects to minimize discomfort and potential injury.

Two aluminized optical flats 15 cm in diameter are separated by a gap of 0.04 mm, forming a capacitor. what is the capacitance in picofarads

Answers

Answer: 3978 pF

Explanation:

Capacitance can be defined as ability to store charge. It is the ratio of charge  over electric potential.

C =\epsilon_o (A)/(d)

where, A is the area of the plates and d is the distance between plates forming the capacitor.

diameter of the plates, di = 15 cm =0.15 m

radius of the plate, r = di/2 = 0.075 m

Area of the plates, A = πr² = 0.018 m²

Distance between the plates, d = 0.04 mm = 0.00004 m

Permittivity, ∈₀ = 8.84 × 10⁻¹² F/m

Capacitance, C = 8.84 * 10^(-12) F/m * (0.018 m^2)/(0.00004 m) = 3978 * 10^(-12) F = 3978 pF