What's the Discriminant of X^2-2X-15 ?

Answers

Answer 1

Answer: the discriminant is the secion inside the double parenthasees [()] below in the quadratic formulat which is
x= $\frac{-b+ \sqrt{[(b^(2)-4ac)]} }{2a}$

the determinant determines or tells whether the answer is real or imaginary
if it is negative, then it is imaginary, if positive, then it is real
so basically the discriminmant is $b^(2)-4ac$

so ax^2+bx+c
a=x^2-2x-15

a=1
b=-2
c=-15

subsitute
$-2^(2)-4(1)(-15)$ =4-4(1)(-15)=4+60=64
the discriminant is ( $-2^(2)-4(1)(-15)$ ) or 64

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Evaluate the expressions when a = 10, b = -2, and c = -5: (a) a * b (b) 10 * b² (c) -a * b² + (-c) (d) (a * c + a) / b

Which sequence of transformations carries ABCD onto HGFE

Answers

Answer:

The correct option is D.

Step-by-step explanation:

It is given that the after transformation figure ABCD onto HGFE. It means HGFE is image of ABCD after transformation.

From the figure it is noticed that A(2,-1) and H(-6,1).

Rotation of 90 degree clockwise about the origin followed by the reflection across the x-axis is expressed as

$(x,y)\rightarrow (y,-x)\rightarrow (y,x)$

Therefore the image of A(2,-1) is (-1,2), which are not the coordinates of H. Option A is incorrect.

Translation 3 unit up followed by the reflection across the y-axis is expressed as

$(x,y)\rightarrow (x,y+3)\rightarrow (-x,y+3)$

Therefore the image of A(2,-1) is (-2,2), which are not the coordinates of H. Option B is incorrect.

Reflection across the x-axis followed by rotation of 90 degree counterclockwise about the origin is expressed as

$(x,y)\rightarrow (x,-y)\rightarrow (y,x)$

Therefore the image of A(2,-1) is (-1,2), which are not the coordinates of H. Option C is incorrect.

Translation 8 unit left followed by reflection across the x-axis is expressed as

$(x,y)\rightarrow (x-8,y)\rightarrow (x-8,-y)$

Therefore the image of A(2,-1) is (-6,1), which are the coordinates of H. Option D is correct.

If you look closely at the options, the first 3 options will not produce an image that will be in Quadrant II with the vertices coinciding HGFE.
But if you look at the 4th option, translating the points 8 units to the left will produce an image in Quadrant III. Reflecting the image across the x-axis will produce triangle HGFE.

the radius and height of a cylinder are in the ratio 5:7.if it's volume is 4400cm cube, find the radius of the cylinder

Answers

V of cylinder= πr2h ...4400= 22/7×5X2×7x. . , x=8 . . . R = 5×8. . R=40

Which of the following representative fractions would indicate the largest scale map? Options: • 1:1 • 1:0 • 1:1,000,000 • 1:24,000

Answers

Final Answer:

The largest scale map is indicated by the representative fraction 1:1. Option A is correct.

Explanation:

In cartography, the representative fraction (RF) of a map indicates the scale of the map, specifically the ratio between a distance on the map and the corresponding distance on the Earth's surface. A larger RF value means a larger scale map, which represents smaller areas with more detail.

Now, let's compare the given options:

1. 1:1 - This RF means that one unit on the map represents one unit on the ground, essentially a one-to-one scale. It doesn't get any larger than this, so this is the largest scale possible.

2. 1:0 - This doesn't make sense in cartography because you cannot represent the Earth's surface with zero on one side of the ratio. It's an invalid option.

3. 1:1,000,000 - This RF indicates that one unit on the map represents one million units on the ground. This is a much smaller scale compared to 1:1, so it represents a much larger area with less detail.

4. 1:24,000 - This RF means that one unit on the map represents 24,000 units on the ground. While this is a larger scale than 1:1,000,000, it is still smaller than 1:1, which is the largest scale.

In summary, the largest scale map is represented by 1:1. Option A is the answer.

Learn more about fraction

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Answer:

The representative fraction (RF) of a map indicates the scale of the map. In a representative fraction, the first number represents a unit of measurement on the map, and the second number represents the corresponding unit of measurement in the real world.

Among the options provided, a larger scale map would have a smaller second number because it means that one unit of measurement on the map represents a smaller unit of measurement in the real world. So, the largest scale map in the given options is:

1:24,000

In this case, 1 unit on the map represents 24,000 units in the real world, indicating a very detailed and large-scale representation of the area.

Angle x is the largest angle in triangle xyz. Angle y is the smallest angle. How does the sum of the measures of angles y and z compare to the measure of angle x

Answers

Knowing that the angles of the triangle has a total of 180 degrees, so we can have the following:

x + y + z = 180
y + z = 180 - x
or
x = 180 - y - z

In this approach, we can't give the actual values since there are no values presented.

A dog weighs two pounds less than three times the weight of a cat. The dog also weighs twenty-two pounds more than a cat. Write and solve an equation to find the weights of the dog and the cat.

Answers

Let's use algebra to represent the weights of the dog and the cat.

Let D represent the weight of the dog in pounds.

Let C represent the weight of the cat in pounds.

According to the information given:

1. The dog weighs two pounds less than three times the weight of a cat, so we can write this as an equation: D = 3C - 2.

2. The dog also weighs twenty-two pounds more than a cat, so we can write this as another equation: D = C + 22.

Now, we have a system of two equations:

1. D = 3C - 2

2. D = C + 22

To solve for the weights of the dog and the cat, we can set these two equations equal to each other since they both equal D:

3C - 2 = C + 22

Now, let's solve for C (the weight of the cat):

3C - C = 22 + 2

This simplifies to:

2C = 24

Now, divide both sides by 2 to find the value of C (the weight of the cat):

C = 24 / 2

C = 12

So, the weight of the cat is 12 pounds.

Now, we can find the weight of the dog using either of the two original equations. Let's use the second equation:

D = C + 22

D = 12 + 22

D = 34

So, the weight of the dog is 34 pounds.

Therefore, the dog weighs 34 pounds, and the cat weighs 12 pounds.

-2094-67
Help!!!!!!!!!

Answers

Answer:

−2161

Step-by-step explanation:

Subtract 67 from -2094

If you want me to show work, let me know!

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