The Correct answer to this question for Penn Foster Students is: 2.5 W
At which landing site would the lander have the greatest amount of gravitational potential energy?
A. W
B. X
C. Y
D. Z
Answer:
B. X.
Explanation:
To determine which landing site would have the greatest amount of gravitational potential energy, we need to consider the height above the surface and the acceleration due to gravity at each site.
Gravitational potential energy is given by the formula:
Gravitational potential energy = mass x acceleration due to gravity x height
In this case, the mass of the lander is not provided, but since it is the same for all the sites, we can ignore it for the purpose of comparison. Therefore, we only need to consider the acceleration due to gravity and the height above the surface.
Looking at the table, we can see that at site X, the height above the surface is 16 meters, and the acceleration due to gravity is 3.7 meters per second squared. This means that at site X, the lander would have the highest amount of gravitational potential energy compared to the other sites.
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Answer:
The formula for acceleration due to gravity at the surface of a celestial body is:
a = (G * M) / r^2
Where:
G (the gravitational constant) is approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2.
M (the mass of Jupiter) is approximately 1.898 x 10^27 kilograms.
r (the mean radius of Jupiter) is approximately 71,492,000 meters.
Now, let's calculate it:
a = (6.67430 x 10^-11 m^3 kg^-1 s^-2 * 1.898 x 10^27 kg) / (71,492,000 meters)^2
a ≈ 24.79 m/s^2
So, the free-fall acceleration at the surface of Jupiter is approximately 24.79 m/s^2.
The free-fall acceleration on the surface of Jupiter (g) is calculated by using Newton's Universal Law of Gravitation (g = G * M / r^2), where G is the gravitational constant, M is the mass of Jupiter and r is the radius of Jupiter.
To calculate the acceleration due to gravity at the surface of Jupiter, we can use Newton's Universal Law of Gravitation. It states that the force of gravity is equal to the gravitational constant (G) times the mass of the body (in this case, Jupiter) divided by the radius of the body squared. The formula can be expressed as F = G * (M * m / r^2), where F is the force of gravity, G is the gravitational constant, M is the mass of the larger body (Jupiter), m is the mass of the smaller body (object in question), and r is the distance between the centers of the two bodies - which is the radius of Jupiter when the object is on its surface.
The formula to find the acceleration due to gravity (g) on the surface of Jupiter is found by setting the weight of an object (F = m*g) equal to the gravity force (F = G * (M * m / r^2)) leading to the cancellation of the mass of the object (m). That results in g = G * M / r^2. This means that the acceleration due to gravity on the surface of Jupiter depends on the mass of Jupiter and the radius of Jupiter, and not on the mass of the object.
#SPJ11
Answer:
The specific heat capacity of the substance = 455.38 J/kgK
Explanation:
Heat lost by the substance = Heat gained by water + heat gained by the aluminum calorimeter
Qs = Qw + Qc.................... equation 1
Where Qs = heat lost by the substance, Qw = heat gain by water, Qc = heat gain by the aluminum calorimeter.
Qs = c₁m₁(T₁-T₃)................ equation 2
Qw = c₂m₂(T₃-T₂)............. equation 3
Qc = c₃m₃(T₃-T₂)............. equation 4
Where c₁ = specific heat capacity of the substance, m₁ = mass of the substance, c₂ = specific heat capacity of water, m₂ = mass of water, c₃ = specific heat capacity of aluminium, m₃ = mass of the aluminum container, T₁ = Initial Temperature of the substance, T₂ = initial temperature of water, T₃ = Final equilibrium temperature.
Substituting equation 2, 3, 4 into equation 1
c₁m₁(T₁-T₃) = c₂m₂(T₃-T₂) + c₃m₃(T₃-T₂)................. equation 5
Making c₁ the subject of equation 5
c₁ = {c₂m₂(T₃-T₂) + c₃m₃(T₃-T₂)}/m₁(T₁-T₃)............... equation 6
Where c₂ = 4200 J/kgK, m₂ = 0.285 kg, m₁ = 0.125 kg, c₃ = 900 J/kgK, m₃= 0.150 kg, T₁ = 90.5°C, T₂ = 29.5°C, T₃ = 32.0°C
Substituting these values into Equation 6,
c₁ = {4200×0.285(32-29.5) + 900×0.150(32-29.5)}/0.125(90.5-32)
c₁ = {1197(2.5) + 135(2.5)}/7.3125
c₁ = {2992.5 + 337.5}/7.3125
c₁ = 3330/7.3125
c₁ = 455.38 J/kgK.
Therefore the specific heat capacity of the substance = 455.38 J/kgK