A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?

Answers

Answer 1

Answer: In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
= 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
= 797 milligrams.
So the flea weighs 797 milligrams more than the ant.

Answer 2

Answer:

Answer:

797 milligrams

Step-by-step explanation:

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What is the definition of variable expression

Answers

In mathematics, a variable expression is an expression that contains operations, numbers, and variables.

For example, if I have 6 coins in my pocket in . addition to the number of coins that are in my jar at home, then then the total number of coins would be represented as X + 6.

X would represent the unknown amount of coins in my jar at home.

This would be a variable expression because it contains an operation "addition", a number "4", and a variable "X."

basically variable is a term that specifies unspecified numbers..
variable expression:
it is the algebraic expression in which both numbers and variables are comprised by means of arithmetic operations
example:
1) 2a + 3
2) 5/2 - x

luke can run a mile in 7 minutes. colleen can run a mile in 5 minutes. at this rate, how much longer would it take luke to run 11 miles than it would take colleen to run 11 miles?

Answers

Speed of a object is defined as the total distance covered in the total time taken. To run 11 miles Luke take 22 minutes longer than the colleen to run 11 miles.

Given information-

Luke can run a mile in 7 minutes.

Colleen can run a mile in 5 minutes.

What is speed?

Speed of a object is defined as the total distance covered in the total time taken. Speed is the ratio of the distance $d$ to the time taken $t$ . Thus,

$s=(d)/(t)$

As Luke can run 1 mile in 7 minutes. Thus the speed of the Luke is,

$s_l=(1)/(7)$

Thus the speed of the Luke is 1/7 miles per minute.

As Colleen can run 1 mile in 5 minutes. Thus the speed of the Colleen is,

$s_c=(1)/(5)$

Thus the speed of the Luke is 1/5 miles per minute.

The total time taken by the Luke to cover the 11 miles with the speed of 1/7 miles per minute is,

$(1)/(7) =(11)/(t)$

Solve for $t$

$t=11* 7}\nt=77$

Hence, the total time taken by Luke to run 11 miles is 77 minutes.

The total time taken by the Colleen to cover the 11 miles with the speed of 1/5 miles per minute is,

$(1)/(5) =(11)/(t)$

Solve for $t$

$t=11* 5}\nt=55$

Hence, the total time taken by Colleen to run 11 miles is 55 minutes.

Extra time taken by Luke to cover 11 miles than Colleen is,

$t=77-55=22$

Hence to run 11 miles Luke take 22 minutes longer than the colleen to run 11 miles.

Learn more about the speed here;

brainly.com/question/2292310

22 because 7 minutes per mile in 11 miles would be 77 minutes, and 5 minutes per mile in 11 miles would be 55 minutes. Therefore it takes Luke 22 more minutes than it takes Colleen to run the mile.

A group of related facts that use the same numbers is an

Answers

A group of related facts that use the same number is a fact family

Please Help Me !!!!!!

1. Polynomials Add or subtract

(4x2 + 15x – 3) – (–3x2 + 5) (1 point)

A.7x2 + 15x – 8

B.x2 + 12x + 2

C.x2 + 15x – 8

D.7x2 + 8 2.

2. Simplify the polynomial.

–3f2 + 4f – 3 + 8f2 + 7f + 1 (1 point)

A.5f2 – 11f + 2

B.11f2 + 11f + 2

C.5f2 + 11f – 2

D.–5f2 + 11f – 2

3. Add or subtract

(2x2 + 6x + 1) + (–7x2 + 2x – 3) (1 point)

A.5x2 – 4x – 2

B.–5x2 + 8x – 2

C.5x2 – 8x + 2

D.–9x2 – 8x + 2

4. Name the coefficients in the polynomial.

4x2 + 3x – 3 (1 point)

A.4, –3, –3

B.4, 3

C.4, 3, 3

D.–4, –3

5. How many terms are in the following polynomial?

6x4 + 3x3 – 2x2 + 15x – 14 (1 point) A. 5

B.4

C.3

D.2

6. In the expression –7x – 5x2 + 5, what is the coefficient of x? (1 point)

A.7

B.5

C.–5

D. -7

7. Write the expression using scientific notation.

(2.5 • 104)(4 • 103) (1 point)

A.10 • 107

B.10 • 108

C.1 • 108

D.10 • 1012

8. Write the expression using a single exponent.

22 • 28 (1 point)

A.410

B.210

C.416

D.216

Answers

Answer:

(1) A

(2) C

(3) B

(4) The coefficients are 4,3,-3.

(5) A

(6) D

(7) C

(8) B

Step-by-step explanation:

(1)

The given expression is

$(4x^2 + 15x - 3) - (-3x^2 + 5)$

Using distributive property.

$(4x^2 + 15x - 3) - (-3x^2) -( 5)$

$4x^2 + 15x - 3 + 3x^2 - 5$

On combining like terms.

$(4x^2+3x^2) + 15x +(- 3 - 5)$

$7x^2 + 15x-8$

Therefore, the correct option is A.

(2)

The given expression is

$-3f^2 + 4f - 3 + 8f^2 + 7f + 1$

On combining like terms.

$(-3f^2+ 8f^2) +( 4f + 7f )+(- 3 + 1)$

$5f^2 +11f -2$

Therefore, the correct option is C.

(3)

The given expression is

$(2x^2 + 6x + 1) + (-7x^2 + 2x - 3)$

Combined like terms.

$(2x^2-7x^2) + (6x+ 2x) + (1 - 3)$

$-5x^2 + 8x -2$

Therefore, the correct option is B.

(4)

The given expression is

$4x^2 + 3x - 3$

A number before variable terms are called coefficient of that term.

Therefore, the coefficients are 4,3,-3.

(5)

The given expression is

$6x^4 + 3x^3 - 2x^2 + 15x - 14$

It this polynomial, the number of terms is 5.

Therefore the correct option is A.

(6)

The given expression is

$-7x - 5x^2 + 5$

The coefficient to x is -7.

Therefore, the correct option is D.

(7)

The given expression is

$(2.5\cdot 10^4)(4\cdot 10^3)$

$(2.5\cdot 4)\cdot (10^4\cdot 10^3)$

Using product property of exponent.

$(10)\cdot 10^(4+3)$

$1\cdot 10^(1+4+3)$

$1\cdot 10^(8)$

Therefore, the correct option is C.

(8)

The given expression is

$2^2\cdot 2^8$

Using product property of exponent.

$2^(2+8)$

$2^(10)$

Therefore, the correct option is B.

$1.\n(4x^2+15x-3)-(-3x^2+5)\n=4x^2+15x-3+3x^2-5\n=7x^2+15x-8\leftarrow A.$

$2.\n-3f^2+4f-3+8f^2+7f+1\n=5f^2+11f-2\leftarrow C.$

$3.\n(2x^2+6x+1)+(-7x^2+2x-3)\n=2x^2+6x+1-7x^2+2x-3\n=-5x^2+8x-2\leftarrow B.$

$4.\n4x^2+3x-3\n\{4;\ 3;-3\}$

$5.\n6x^4+3x^3-2x^2+15x-14\n\{6;\ 3;-2;\ 15;-14\}\to5\leftarrow A.$

$6.\n-7x-5x^2+5\n\{-7\}\leftarrow D.$

$7.\n(2.5\cdot10^4)(4\cdot10^3)=2.5\cdot4\cdot10^(4+3)=10\cdot10^7\n=10^(1+7)=10^8=1\cdot10^8\leftarrow C.$

$8.\n2^2\cdot2^8=2^(2+8)=2^(10)\leftarrow B.$

How do i factor this trinomial?

Answers

$\text{Hey there!}$

$\text{The answer is: (3g + 2)(g + 2)}$

$\text{To make sure it comes back to the original problem}\bf{(3g^2+8g+4)}$ $\text{You would have to distribute the answer}$

$\text{3g(g)=}3g^2\n \text{3g(2)=6g}\n \text{2(g)=2g}\n \text{2(2)=4}$

$\text{After distributing combine your like terms:}$

$\text{In this particular answer we have: 1 term with TWO LIKE TERMS}$

$\text{6g+2g=8g(That's how we got the 8g in the original equation)}$

$\text{The}\bf{\ 3g^2}\text{ stays the same because there's nothing to go with it}$

$\text{The 4 also stays the same because nothing goes with it as well}$

$\boxed{\boxed{\text{Answer:(3x + 2 (x + 2)})}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

Andrew jogs for 3 miles each day on the weekdays and for 6.5 miles each day over the weekend. What is the average distance that Andrew covers everyday? mi

Answers

3 miles x 5 week days = 15 miles

6.5 miles x 2 days over the weekend= 13

13 miles + 15 miles = 28

28 miles/ 7 days of the week= 4 miles on average per day

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