PHYSICS HIGH SCHOOL

In a given circuit, the supplied voltage is 1.5 volts. One resistor is 3 ohms and the other is 2 ohms. Use Ohm's law to determine the current in the circuit.0.3 amps
1.5 amps
7.5 amps
3.3 amps

The purpose of a fuse or circuit breaker is _____.
to speed up the current
to slow down the current
to stop current that is flowing too fast
to stop current that is flowing too slow

Answers

Answer 1

Answer:

(1) The value of the current depends upon how they are connected.

When placed in series:

The resistance would be: 3+2=5ohms.

Ohm's law is given as:

$I=(V)/(R)$

⇒ $I=(1.5)/(5)=3 ampere$

When placed in parallel:

The resistance would be: $\frac{3{*}2}{3+2}=1.2 ohms$

Now, the current would be:

$I=(1.5)/(1.2)=1.25 ampere$

(2) The purpose of a fuse or circuit breaker is to stop current that is flowing too fast.

A fuse is wire that have low melting point when placed in a circuit. When current is moving too fast i.e. in case of over current, the heat produced melts this wire which further breaks the circuit. Similarly a circuit breaker is a switch which opens up in case of over flow of current.

Thus, a circuit breaker is then used to to stop current that is flowing too fast.

Answer 2

Answer:

No that other answer is not right they messed up and the right answer would be 0.3 I hope that this helps

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The primary reason a light bulb emits light is due to

Answers

Answer:

Resistance

Explanation:

Answer:

The correct answer is (C) resistance.

Explanation: i used the answer above and i got it right!

A car moves at 12 m/s for 30.0 seconds. It then accelerates at 1.5 m/s2 for 8.00 seconds. Finally, it continues on at this top speed for another 12.0 seconds. Calculate the net
displacement during the whole time interval.

Answers

Over the first 30.0 s, the undergoes a displacement of

(12 m/s) * (30.0 s) = 360 m

Over the next 8.00 s, the car accelerates from 12 m/s to a top speed of

12 m/s + (1.5 m/s²) * (8.00 s) = 24 m/s

and over this time interval, it is displaced an additional

(12 m/s) * (8.00 s) + 1/2 (1.5 m/s²) * (8.00 s)² = 144 m

For the last 12.0 s, the car moves at a constant speed of 24 m/s to cover a distance of

(24 m/s) * (12.0 s) = 288 m

So the car's net displacement is 360 m + 144 m + 288 m = 792 m. (The net displacement is the same as distance in this case because the car moves in only one direction.)

Explain why a light wave refracts when it travels through mediums such as air to water.

Answers

The simplest explanation is that the speed changes. That causes the wavefront to change direction and so refraction takes place.

How much force is needed to accelerate a 68 kilogram skier at a rate of 1.2m/sec

Answers

Let's use Newton's 2nd law of motion:

Force = (mass) x (acceleration)

Force = (68 kg) x (1.2 m/s²) = 81.6 newtons .

$f=m*a$

68*1.2=81.6

$f=81.6$

HELP NEEDED! Determine the mechanical energy of this object: a 1-kg ball rolls on the ground at 2 m/s. A. The ball is on the ground, so the mechanical energy is zero.
B. 2 J
C. 1 J
D. 4 J

Answers

The mechanical energy of an object is the sum of its potential and kinetic energy.

Because the ball is on the ground, its potential energy is 0.
Its kinetic energy is given by:

K.E = 1/2 mv²
K.E = 1/2 x 1 x 2²
K.E = 2 J

Mechanical energy = 2 + 0
Mechanical energy = 2 J

The answer is B.

I think it's 2 J. Hope I helped :)

cleopatra needle, an ovelisk given by the egyptian government to great britian in the 19th century, is 20+m tall and has a mass of about 189,000 kg. suppose the monument is lowered onto its side and dragged horizontally to a new location. an applied force of 760,000 N is excerted on the monument, so that its net acceleration is 0.11 m/s2. what is the weight, the net force, the frictional force and the coefficient of friction phycis

Answers

To solve this problem, we can use Newton's second law and the equations of motion. First, let's calculate the weight of the Cleopatra's Needle, which is the mass multiplied by the acceleration due to gravity (9.81 m/s²):

Weight = mass × acceleration due to gravity
Weight = 189,000 kg × 9.81 m/s² ≈ 1,854,090 N

Next, let's calculate the net force acting on the monument using Newton's second law (F = m × a), where F is the force, m is the mass, and a is the acceleration:

Net Force = mass × acceleration
Net Force = 189,000 kg × 0.11 m/s² ≈ 20,790 N

The net force applied is 760,000 N, so the frictional force can be calculated by subtracting the net force from the applied force:

Frictional Force = Applied Force - Net Force
Frictional Force = 760,000 N - 20,790 N ≈ 739,210 N

The coefficient of friction (μ) can be calculated using the formula for frictional force (Frictional Force = μ × Normal Force). Since the normal force is equal to the weight of the monument:

μ = Frictional Force / Weight
μ = 739,210 N / 1,854,090 N ≈ 0.3987

So, the coefficient of friction is approximately 0.3987.

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