Chetan and his 5 siblings buy a present for their mother on Mother's Day. As the eldest brother, he pays 0.2 of the cost of the present. The rest of the siblings share the balance equally. Each sibling pays $9.50 less than Chetan. What is the cost of the present.

Answers

Answer 1

Answer: Let's say that X is what the other 5 siblings pay. X + $9.50 is what Chetan pays. X + $9.50 is 1/5 of the cost of the present. To solve this we have to do 0.8 divided by 5 (the remaining cost split between 5 people) which is 0.16. Now from this we can learn that $9.50 is 0.04 of the cost of the present. A simple way to solve this is do 1.00 divided by 0.04 and then multiply $9.50 by that amount. 1.00 divided by 0.04 is 25 so $9.50 times 25 is $237.5.
The present costs $237.5
As I read over this I may not be correct, however this is how I solved it as an advanced mathematics grade 8 student.

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can u pl explain the question

If r(x) = 2 – x2 and w(x) = x – 2, what is the range of (w.r) (x)?

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For this case we have by definition that:

$(f * g) (x) = f (x) * g (x)$

In this case we must find $(w* r) (x)$ , so:

$(w * r) (x) = w (x) * r (x) = (x-2) (2-x ^ 2) =$

We must apply distributive property that states that:

$(a + b) (c + d) = ac + ad + bc + bd$

So:

$(x-2) (2-x ^ 2) = 2x-x ^ 3-4 + 2x ^ 2 = -x ^ 3 + 2x ^ 2 + 2x-4$

The range is the set of all "y" values

Valid That is to say: (-∞,∞)

Answer:

(-∞,∞)

Can anyone please help me with 1,2,&,3 ?

Answers

Okay, lets start with number 1.

$(x+3)^(3)$ is also equal to (x+3)(x+3)(x+3)

If you take the first two ones and multiple them out it ends up with $x^(2) + 3x +3x + 9$ or also know as $x^(2) + 6x + 9$

You see to multiply them you take the first number in the first group of parenthesis and use the distributive property on the second equation, then you do the same this but with the second number in the first equation.

So once you have $(x^(2) + 6x + 9)$ you multiply it with your remaining (x + 3) using the distributive property to get $x^3 + 9x^2 + 27x + 27$

I hope this helps you get the answers for the other two.

(x+3)^3 = x^3+9x^2+27x+27

(x+2)(x-2)(x^2+4) = x^4-16

(x-2)^2+1 = x^2-4x+5

The quotient of 8 and twice a number z

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2z divided by 8
Z= 16

Find the answer to the nearest tenth. The length of the base of a triangle is 3 times the length of its altitude. Find the length of the base if the area of the triangle is 54 m^2.

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area=1/2bh h=altitude b=legnth of base b is 3 times h b=3h divide by 3 b/3=h area=1/2bh subsitute b/3 for h 54=1/2(b)(b/3) multiply bothsides by 2/1 108=b(b/3) 108=(b^2)/3 multipy both sides by 3 324=b^2 square root boh sides 18=b legnth of base=18

Question 3(Score for Question 3: _of 6 points)
3. In a game, if you roll a 6 on a 6-sided number cube, you lose a turn.
(a) What is the probability that you roll a 6? Explain your reasoning.
(b) What is the probability that you either roll a 6 or do not roll a 6? Explain your reasoning.
(c) What is the probability that you don't roll a 6? Explain your reasoning.
Answer.

Answers

Answer:

(a) What is the probability that you roll a 6?

1/6

(b) What is the probability that you either roll a 6 or do not roll a 6?

5/6

Step-by-step explanation:

(a) What is the probability that you roll a 6?

In a 6- sided cube, a 6 occurs only once. That is only one face is labelled 6. Therefore, the probability that you roll a 6 is;

(number of faces labelled 6)/(totals number of sides) = 1/6

(b) What is the probability that you either roll a 6 or do not roll a 6?

The probability of rolling a 6 was found to be, 1/6.

On the other hand, the probability of not rolling a 6 is;

(number of faces not labelled 6)/(totals number of sides) = 5/6

Therefore, the probability that you either roll a 6 or do not roll a 6 is;

1/6 + 5/6 = 1

These two events are mutually exclusive and exhaustive.

The probability of not rolling a 6 is;

(number of faces not labelled 6)/(totals number of sides) = 5/6

We have 5 faces not labelled 6 out of 6 possible faces or outcomes

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EMERGENCY!!WHAT IS 1 EQUAL TO??