Two lighthouses flash their lights every 20 seconds and 30 seconds respectively. Given that they flash together at 8 p.m, when will they next flash together?

Answers

Answer 1

Answer: The first one will flash at every 30 sec and the second one at 20 sec. The second one will go like 1- 4- 8 and then to 12. By the time the second one will reach first at 6 and then on 12. So, after every 1 minute they will flash together.

Related Questions

Give the domain of the following functions. Give your answer in interval notation. a) f(x)= 5x-2/x^2-5x+6 and b) square root of 5-2x
What is the domain and range of this function? {(1,3),(2,6),(3,9),(4,12)}
Find the zeros of x3 +2X^2-23x-60
How can 11,14,13 and 19 equal to 4
Radius = 11 cm.; Height = 10 cm.

HELP PLEASE!!!1.) True or False: "The sum of all the probabilities of outcomes of an event is equal to 100.

2.) If I roll a fair die 100 times, about how many times would I roll a 4?
A.) 25 times
B.) 67 times
C.) 17 times
D.) There is not enough information to answer.

Answers

Answer:

1. false

2. 17 times

Step-by-step explanation:

The sum of all the probabilities of outcomes of an event is equal to 1

2. A die has 1,2,3,4,5,6

P(4) = number of 4's/ total numbers

= 1/6

Multiply the number of roll's by the probability of getting a 4

100 *1/6 = 50/3 = 16 2/3

This is approximately 17

1.What is the correct reason for statement 2?Prove: 2(w + 6) + 4 = 2w + 16
Statements Reasons
1. 2(w + 6) + 4 1. Given
2. (2w + 12) + 4 2. ?
3. 2w + (12 + 4) 3. Associative Property
4. 2w + 16 4. Addition

2.What is the correct reason for statement 2?
Prove: 4 + 3x + (x ∙ 2) = 5x + 4
Statements Reasons
1. 4 + 3x + (x ∙ 2) 1. Given
2. 4 + 3x + 2x 2. ?
3. 4 + 5x 3. Addition
4. 5x + 4 4. Commutative Property

3.What is the correct reason for statement 3?
Prove: (11m) ∙ 4 + m = 45m
Statements Reasons
1. (11m) ∙ 4 + m 1. Given
2. 4 ∙ (11m) + m 2. Commutative Property
3. (4 ∙ 11) ∙ m + m 3. ?
4. 44m + m 4. Commutative Property
5. 45m 5. Addition

4.What is the correct reason for statement 5?
Prove: k + 4 + 6(1 + k) = 11k + 10
Statements Reasons
1. k + 4 + 6(1 + k) 1. Given
2. k + 4 + (6+ 6k) 2. Distributive Property
3. k + (4 + 6) + 6k 3. Associative Property
4. k + 10 + 6k 4. Addition
5. k + 6k + 10 5. ?
6. 7k + 10 6. Addition

5.Select the correct reasons for statements 1 and 3 to complete the proof.
Prove: 3x + 2 • x • 11 = 25x.
1. 3x + 2 • x • 11 = 3x + 2 • 11 • x 1. ?
2. 3x + 2 • x • 11 = 3x + 22x 2. Multiplication
3. 3x + 2 • x • 11 = 25x 3. ?

Answers

1. The reason for statement 2 is
Distributive Property

2. The reason for statement 2 is
Commutative Property

3. The reason for statement 3 is
Associative Property

4. The reason for statement 5 is
Commutative Property

5. The reason for statement 1 is
Associative Property
The reason for statement 3 is
Addition

State the correct reason for each statement

2(w + 6) + 4 = 2w + 16

1. 2(w + 6) + 4

2. (2w + 12) + 4

3. 2w + (12 + 4)

4. 2w + 16

Statements Reasons:

1. Given

2. distributive property

3. Associative Property

4. Addition

4 + 3x + (x ∙ 2) = 5x + 4

1. 4 + 3x + (x ∙ 2).

2. 4 + 3x + 2x

3. 4 + 5x

4. 5x + 4

Statements Reasons:

1. Given

2. cummulative property

3. Addition

4. Commutative Property

(11m) ∙ 4 + m = 45m

1. (11m) ∙ 4 + m

2. 4 ∙ (11m) + m

3. (4 ∙ 11) ∙ m + m

4. 44m + m.

5. 45m

Statements Reasons:

1. Given

2. Commutative Property

3. associative

4. Commutative Property

5. Addition

k + 4 + 6(1 + k) = 11k + 10

1. k + 4 + 6(1 + k)

2. k + 4 + (6+ 6k)

3. k + (4 + 6) + 6k

4. k + 10 + 6k

5. k + 6k + 10

6. 7k + 10

Statements Reasons:

1. Given

Given 2. Distributive Property

Given 2. Distributive Property 3. Associative Property

Given 2. Distributive Property 3. Associative Property 4. Addition

Given 2. Distributive Property 3. Associative Property 4. Addition 5. cumulative

6. Addition

3x + 2 • x • 11 = 25x.

1. 3x + 2 • x • 11 = 3x + 2 • 11 • x

2. 3x + 2 • x • 11 = 3x + 22x

3. 3x + 2 • x • 11 = 25x

Reasons:

1. associative

1. associative2. Multiplication

1. associative2. Multiplication 3. addition

brainly.com/question/24730587

What is the solution to the system of equations below?y=-6x-10
and
y=-3x-21
(2, -22)
(2,48)
(-2, 2)
(-2, -20)

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

$y=-6x-10$

$y=-3x-21$

solving the system of the equations

Arrange the equation variables for elimination

$\begin{bmatrix}y+6x=-10\n y+3x=-21\end{bmatrix}$

$y+3x=-21$

$-$

$\underline{y+6x=-10}$

$-3x=-11$

$\begin{bmatrix}y+6x=-10\n -3x=-11\end{bmatrix}$

solve

$-3x=-11$

Divide both sides by -3

$(-3x)/(-3)=(-11)/(-3)$

$x=(11)/(3)$

$\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=(11)/(3)$

$y+6\cdot (11)/(3)=-10$

$y=-32$

Therefore, the solutions to the system of the equations are:

$y=-32,\:x=(11)/(3)$

But, it seems none of the options is true.

Answer:

A. (2, -22)

Step-by-step explanation:

I just took the test and i got a one hundred! I really hope it helped!!!!

The area of triangle B is 25 times greater than the area of triangle A.The perimeter of triangle B is how many times greater than the perimeter of triangle A?

Answers

The ratio of areas is the square of the ratio of perimeters;
The area of triangle B / The area of triangle A = 25 ;
The perimeter of triangle B / The perimeter of triangle A = $√(25) = 5 ;$
The perimeter of triangle B is 5many times greater than the perimeter oftriangle A!

The perimeter of triangle B is 5 times greater than that of A.
The ratio of areas in this example is 1:25.
The ratio of areas is the square of the ratio of perimeters.
$\sqrt1 : √(25) =1 : 5$

the area of a rectangle is 44ft(squared) and the length of the rectangle is 3ft less than double the width. find the dimension of the rectangle

Answers

look at factors of 44...

1 and 44
2 and 22
4 and 11

Using those, we can see that 4 by 11 works, because 4x2 equals 8, which is 3 less than eleven. Stick to the basics, they are your best weapons.

Each child ticket for a ride costs $3, while each adult ticket costs $5. The ride collected a total of $150, and 40 tickets were sold. How many of each type of ticket were sold?A. 150 child and 40 adult
B. 24 adult and 10 child
C. 30 child and 10 adult
D. 25 child and 15 adult

Answers

The way to go about this is to think logically about the answers
A) isn't possible as 40 tickets were sold and 150 plus 40 = 190
B) is similar to above only there was less than 40 tickets sold
C) very possible
D) very possible
next step:
C) (30 x 3) + (10 x 5) = 90 + 50 = $140 (by this we should assume that the answer is D)
D) (25 x 3) + (15 x 5) = 75 + 75 = $150 ( yay answer is D :) )

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