How many ways can the letters of the word ORGANISM be arranged so the third letter is G?

Answers

Answer 1

Answer: $7!=5040$
..........

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Quadrilateral EFGH has coordinates E(a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of HG.A (2a, 0)
B (a, 2a)
C (a, a)
D (a, 0)

Answers

Midpoint of HG = ((0 + 2a)/2, (0 + 0)/2) = (2a/2, 0/2) = (a, 0)
option D is the correct answer.

Coordinates are: H ( 0, 0 ) and G ( 2 a, 0 ).
Coordinates of the midpoint are:
x = ( x 1 + x 2 ) / 2
y = ( y 1 + y 2 ) / 2
The midpoint of HG:
x = ( 0 + 2 a ) / 2 = 2 a / 2 = a
y = ( 0 + 0 ) / 2 = 0 / 2 = 0
Answer:
D ) ( a, 0 )

The ratio of the muffins Baker A baked to the number of muffins Baker B baked was 8 : 5. The ratio of the number of muffins Baker B baked to the number of muffins BAker C baked was 4 : 3. If Baker C baked 150 muffins, how many more muffins did Baker A bake than Baker C?

Answers

Answer:

170 muffins

Step-by-step explanation:

We start from the ratio between baker B and C

The ratio of cakes baked by both is 4:3.

We know baker C baker 150 muffins:

This mathematically means:

B:C = 4:3 = B:150

This means 4/3 = B/150

B = (4 * 150)/3 = 200

Baker B baked 200 cakes

We now move back to the first statement

The ratio between baker A and B is 8:5

Mathematically, this means:

A:B = 8:5 = A:200

8/5 = A/200

A = (8 * 200)/5 = 320

The number of cakes baker A baker pass baker C would be 320 - 150 = 170 muffins

Final answer:

To solve the problem, use the given ratios to calculate the quantity of muffins each baker baked. Then compare the quantities to find the difference. The result is that Baker A baked 170 more muffins than Baker C.

Explanation:

In this question, you're given two ratios involving three bakers: A, B, and C. First, let's figure out how many muffins Baker B baked. We know that for every 4 muffins Baker B baked, Baker C baked 3 muffins. This gives us the ratio 4 : 3 for Baker B to Baker C. Since we know that Baker C baked 150 muffins, we can set up a simple proportion: 4/3 = B/150. Solving this proportion, we find that Baker B baked 200 muffins.

Now let's tackle the ratio of muffins baked by Baker A to Baker B, which is given as 8 : 5. Again, we can set up a proportion: 8/5 = A/200. Solving this, we find that Baker A baked 320 muffins.

The question asks how many more muffins Baker A baked than Baker C. Given that Baker A baked 320 muffins and Baker C baked 150 muffins, the difference is 320 - 150, which gives us 170. So, Baker A baked 170 more muffins than Baker C.

Learn more about Ratio calculations here:

brainly.com/question/31549749

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I need help with my Math problems as I don't really understand it...

Answers

Answer: PAGE B ONLY

1: Multiply by 2 every time.

2. Take Away 3, then add 6 every time.

3. Multiply by 3 every time.

4. Multiply by 2 every time.

6. Multiply by 3 every time.

Step-by-step explanation:

You will get pretty big numbers that I can't calculate, so use a calculator with the rules I gave for you on each problem.

Good luck!

If 95% of the students are present in a school and the number of absent students is 25, find the total number of students in the school? (A) 500 (B) 400 (C) 600 (D) 450

Answers

Answer: Option A: 500.

Step-by-step explanation:

If 95% of the students are present in a school, then the number of absent students is 5% of the total number of students. We are given that the number of absent students is 25, so we can set up an equation:

0.05x = 25

Solving for x, we get:

x = 25 / 0.05 = 500

Therefore, the total number of students in the school is 500.

Therefore, the correct answer is Option A: 500.

Please let me know if there’s anything else I can help you with!

A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.

Answers

$Chair=x$

$Table=y$

$Desk=z$

$\begin{Bmatrix}x+y&=&40\ny+z&=&83\nx+z&=&77\end{matrix}$

keep the first row as normal, then in the other ones, we can isolate Y and X

$\begin{Bmatrix}x+y&=&40\ny&=&83-z\nx&=&77-z\end{matrix}$

now we can replace at first row...

$\begin{Bmatrix}(77-z)+(83-z)&=&40\ny&=&83-z\nx&=&77-z\end{matrix}$

$\begin{Bmatrix}160-2z&=&40\ny&=&83-z\nx&=&77-z\end{matrix}$

$\begin{Bmatrix}-2z&=&40-160\ny&=&83-z\nx&=&77-z\end{matrix}$

$\begin{Bmatrix}-2z&=&-120\ny&=&83-z\nx&=&77-z\end{matrix}$

$\begin{Bmatrix}z&=&60\ny&=&83-z\nx&=&77-z\end{matrix}$

now we can replace the Z to discovery the other value

$\begin{Bmatrix}z&=&60\ny&=&83-60\nx&=&77-60\end{matrix}$

$\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\nTable&=&23\nDesk&=&60\end{matrix}}}}$

A pool is being drained at a constant rate. The amount of water is a function of the number of minutes the pool has been draining, as shown in the table. Write an equation in slope-intercept form that represents the function. Then find the water in the pool after two and a half hours. Time (mi) 12--------20------50
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