Given two sides with lengths 34 and 14, which of these lengths would NOT work for the third side of a triangle? 18, 34, 44, 22, 40
Answers
The third side can't be longer than (34 + 14) = 48, because the 34 and the 14
together could not reach from one end of it to the other.
The third side also can't be shorter than 20, because the 20 and the 14 together
could not reach from one end of the 34 to the other.
So 18 doesn't work. (18 + 14) = 32 ... they couldn't cover the 34 .
Related Questions
You borrowed $59,000 for 2 years at 11% which was compounded annually. What total will you pay back?
if usain bolt ran the 100 meter dash in 9.58 seconds. if he ran at a constaint rate how many meters did he run in 3 seconds
If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below.17 23 −17 −23
What is the smallest three-digit number that has a digit sum of 8?
Answers
Answers
Answer: The answer would be 3 +n +4 = 5
Step-by-step explanation:
Welcome
Answer:
see explanation
Step-by-step explanation:
let the number be n , then
+ 4 = 5
Answers
Answer:
To compute the length of the curve f(x)=47(4−x2) over the interval 0≤x≤2, we need to use the formula for the arc length of a function:
L=∫ab1+(f′(x))2dx
where a and b are the endpoints of the interval. First, we need to find the derivative of f(x), which we can do by using the chain rule and the power rule:
f′(x)=4dxd7(4−x2)
f′(x)=427(4−x2)1dxd(7(4−x2))
f′(x)=427(4−x2)1(−14x)
f′(x)=−7(4−x2)28x
Next, we need to plug in f′(x) into the formula and simplify:
L=∫021+(−7(4−x2)28x)2dx
L=∫021+7(4−x2)784x2dx
L=∫027(4−x2)7(4−x2)+784x2dx
L=∫024−x228−21x2dx
Now, we need to evaluate the integral, which we can do by using a trigonometric substitution. Let x=2sinu, then dx=2cosudu and u=arcsin(x/2). The limits of integration change as follows:
x=0⟹u=0
x=2⟹u=2π
The integral becomes:
L=∫02π4−(2sinu)228−21(2sinu)2(2cosu)du
L=∫02π4−4sin2u28−84sin2u(2cosu)du
L=∫02π1−sin2u7−21sin2u(2cosu)du
L=∫02πcos2u7−21sin2u(2cosu)du
L=∫02π27−21sin2udu
Using a trigonometric identity, we can write:
L=∫02π4127−1221cos(2u)du
Using another trigonometric substitution, let v=2u, then dv=2du and u=v/2. The limits of integration change as follows:
u=0⟹v=0
u=2π⟹v=π
The integral becomes:
L=∫0π4127−1221cosv(21)dv
L=6∫0π
B. False
Answers
Answers
Answer:
49 pi in^2 or approximately 153.86 in^2
Step-by-step explanation:
A = pi r ²
Let r = 7
A = pi 7 ²
A = 49 pi
If we approximate pi by 3.14
A is approximately 153.86 in^2
Answers
Answer:
0.3907.
Step-by-step explanation:
Using trigonometric identities, we can write cos 23° in terms of sin 23° as, cos(23°) = √(1 - sin²(23°)). Here, the value of sin 23° is equal to 0.3907.
Answer:
what does international employment mean ? explain its important in any four points