The football team has 30 more members than the basketball teams. If each group had 10 more members, the ratio of their membership would be 3:2. How many members are in each group? Write your answer as football x basketball yHELP PLEASE !

Answers

Answer 1

Answer: x = y + 30 (I)

$(x + 10)/(y + 10) = (3)/(2)$

2x + 20 = 3y + 30
2x - 3y = 10 (II)
______________________________
2(y+30) - 3y = 10
2y + 60 - 3y = 10
-y = -50
y = 50

x = y + 30
x = 50 + 30
x = 80

Football team has 80 members, basketball team has 50 members.

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The ________ sum of squares measures the variability of the sample treatment means around theoverall mean.
a. treatment
b. error
c. interaction
d. total

Answers

The TREATMENT sum of squares measures the variability of the sample treatment means around the overall mean.

The sum of squares is used to measure the variation about the mean, In ANOVA we have:

• Sum of square Error : measures the variation between each observation in a group and the mean of that group.

• Sum of square treatment : measures the variation between the mean of each group and the overall mean.

• Total Sum of Square : measures the variation between each observation and the overall sample mean.

Hence, Treatment sum of squares measures variation between sample treatment and overall sample mean.

Learn more : brainly.com/question/23638404

Answer:

treatment

Step-by-step explanation:

hope this helps, I did OSM 202 MC , as well.

To make 2 batches of nut bars, jayda needs to use 4 eggs. How many eggs are used in each batch of nut jars?

Answers

4/2=2
2 eggs are used in each batch

Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(-1, 1) and Q(5,9)

Answers

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$((x_1+x_2)/(2), (y_1+y_2)/(2))$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \nx_1=-1 \n y_1=1 \n \n Q(5,9) \n x_2=5 \n y_2=9 \n \n(x_1+x_2)/(2)=(-1+5)/(2)=(4)/(2)=2 \n (y_1+y_2)/(2)=(1+9)/(2)=(10)/(2)=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=√((x_2-x_1)^2+(y_2-y_1)^2)$

$(-1,1) \n x_1=-1 \n y_1=1 \n \n (2,5) \n x_2=2 \n y_2=5 \n \n d=√((2-(-1))^2+(5-1)^2)=√(3^2+4^2)=√(9+16)=√(25)=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \n\boxed{(x-2)^2+(y-5)^2=25}$

The distance from the center of a round table top to the edge of the table top is 4 ft. What is the area of the table top?

Answers

Center to the edge of a circle is the radius and Area of a circle = (pi)r^2 so A = (pi) 4^2 = 16 pi = about 50.27 square ft

Answer:

The correct answer is 50.24 sq. ft

Step-by-step explanation:

What is the area of the polygon below?

Answers

Answer:

9 units

Step-by-step explanation:

You can split the polygon into two right triangles and a rectangle. The two right triangles each equal to 1.5 and the rectangle is equal to 6 so 6+1.5+1.5=9

Using the completing-the-square method, find the vertex of the function f(x) = 5x2 + 10x + 8 and indicate whether it is a minimum or a maximum and at what point.a. maximum (1,8)
b. minimum (1,8)
c. maximum (-1,3)
d. minimum (-1,3)

Answers

Answer : d. minimum (-1,3)

$f(x) = 5x^2 + 10x + 8$

The vertex form of quadratic function is

$f(x) = a(x-h)^2 + k$ , where (h,k) is the vertex

To get vertex form we apply completing the square method

To apply completing the square method , there should be only x^2

So we factor out 5 from from first two terms

$f(x) = 5(x^2 + 2x) + 8$

Now we take the number before x (coefficient of x) and divide by 2

$(2)/(2)$ =1

Now square it

$(1)^2 =1$

Add and subtract 1 inside the parenthesis

$f(x) = 5(x^2 + 2x + 1 - 1) + 8$

Now we take out -1 by multiplying 5

$f(x) = 5(x^2 + 2x + 1) -5 + 8$

$f(x) = 5(x^2 + 2x + 1) + 3$

Now we factor x^2 +2x+1 as (x+1)(x+1)

$f(x) = 5(x+1)(x+1) + 3$

$f(x) = 5(x+1)^2 + 3$

h=-1 and k=3

So vertex is (-1,3)

When the value of 'a' is negative , then it is a maximum

When the value of 'a' is positive , then it is a minimum

$f(x) = 5x^2 + 10x + 8$ is in the form of $f(x) = ax^2 + bx + c$

The value of a is 5

5 is positive so it is a minimum

f(x) is minimum at point (-1,3)

The vertex form is a(x-h)²+k, where (h,k) are the coordinates of the vertex.

$f(x)= \n 5x^2+10x+8= \n5(x^2+2x)+8= \n5((x^2+2x+1)-1)+8= \n5((x+1)^2-1)+8= \n5(x+1)^2-5+8= \n5(x+1)^2+3$

The coordinates of the vertex are (-1,3).

The coefficient of x² is positive, so the parabola opens upwards and the vertex is the minimum of the function.

The answer is d.

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