4 friends share 3 apples equally. What fraction of the apple does each friend get ?

Answers

Answer 1

Answer: 3 apples are to be divided up amongst 4 friends. 3/4 = 0.75 apples per person.

Answer 2

Answer: if you divide 3 by 4 then you will get .75
If you cut each apple into fourths u can gI've each person three slices .

Related Questions

The force of gravity on the moon is approximately one sixth that of earth. the direct variation equation for weight on earth compared to wait on the moon is e=6m, where the e weight on the earth and m= weight on the moon what would be the weight of a 180 pound man on the moon
What is an equation of the line that is perpendicular to y + 1 = -3(x - 5) and passes through the point (4, -6)?
What are the partial products of 434 × 310 to find the product
*** Solve 2x + y = 7 for y.
Physics students drop a ball from the top of a 100 foot high building and model its height as a function time with the equation h(t) = 100 - 16t^2. Determine, to the nearest tenth of a second, when the ball hits the ground.

The length of the sides of a triangular garden are 10m 11m 13m.Find the measure of the angle opposite the longest side to the nearest tenth of a degree

Answers

c^2=a^2+b^2-2abcosC
13^2=10^2+11^2-2×10×11×cos(°)
169=100+121-220cos(°)
220cos(°)=100+121-169
220cos(°)=52
cos(°)= 13/55
°=cos-1(13/55)
°=76.328°

Let f(x) = 8x3 − 22x2 − 4 and g(x) = 4x − 3. Find f of x over g of x . 2x2 − 4x − 3 − (13/4x-3)
2x2 − (4x − 3/13)
2x2 − 7x − 1
2x2 − 7x − 5 +(x-4/4x-3)

Answers

Answer:

Option 1 - $(2x^2-4x-3)(-13)/((4x-3))$

Step-by-step explanation:

Given : $f(x)=8x^3-22x^2-4$ and $g(x)=4x-3$

To find : f of x over g of x.

Solution :

$f(x)=8x^3-22x^2-4$ and $g(x)=4x-3$

f of x over g of x is $(f(x))/(g(x))$

Substitute the value in the formula,

$(f(x))/(g(x))=(8x^3-22x^2-4)/(4x-3)$

Now, We have to divide the numerator by denominator with the help of calculator.

Refer the attached figure below.

Here, Dividend is $f(x)=8x^3-22x^2-4$

Divisor is $g(x)=4x-3$

We get, Quotient is $2x^2-4x-3$

and Remainder is -13.

The form is $\text{Dividend}=\text{Quotient}* \text{Divisor}+\text{Remainder}$

i.e. $(8x^3-22x^2-4)=(2x^2-4x-3)*(4x-3)+(-13)$

or in mixed fraction it is written as $(2x^2-4x-3)(-13)/((4x-3))$

Therefore, Option 1 is correct.

I hope this helps you

Tile costs $28 per square meter. how much will it cost to cover the countertop with new tile? (48 square Feet)

Answers

You multiply 48 by28. You get 1344.So it would cost $1,344.00.

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right endpoint of each interval. Give three decimal places in your answer.

Answers

Hello,

Reminders:
$\sum_(i=1)^(n) i= (n(n+1))/(2)$
$\sum_(i=1)^(n) i^2= (n(n+1))/(2)$
$\sum_(i=1)^(n) i^3= (n^2(n+1)^2)/(4)$

$n=6\n x_(0)=0\n x_(n)=3\n \Delta= (x_n-x_0)/(n)=0.5\n$
$x_(i) =0+\Delta*i= (i)/(2)$

$\sum_(i=1)^(n)\ \Delta*f(x_(i))=\sum_(i=1)^(6)\ (i^3/8-6i)/(2)$
$$= (1)/(2)\sum_(i=1)^(6) ((i^3)/(8) -6i)=(1)/(16)*((6*7)^2)/(4)- (9*7)/(2)= -3.9575$

Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highway. The other building is x^3 + 2x^2 - 18 feet from the highway. What is the standard form of the polynomial representing the width of the highway between the two building?

Answers

Given:

Distance between two buildings = $3x^3- x^2 + 7x +100$ feet apart.

Distance between highway and one building = $2x^2 + 7x$ feet.

Distance between highway and second building = $x^3 + 2x^2 - 18$ feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

$W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)$

$W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18$

Combining like terms, we get

$W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)$

$W=2x^3-5x^2+0+118$

$W=2x^3-5x^2+118$

Therefore, the width point highway is $2x^3-5x^2+118$ .

The correct standard form of the polynomial equation that represents the width of the highway between the two buildings is: $2x^3-5x^2+118$ .

Given:

Distance between the building: $3x^3-x^2+7x+100$

Building 1 distance from highway: $2x^2+7x$

Building 2 distance from highway: $x^3+2x^2-18$

To find the Width of the highway between two building:

Add the distances of the buildings from the highway.

Let's call the width of the highway "w"

Distance between the two buildings:

= $(2x^2 + 7x) + (x^3 + 2x^2 - 18)$

$= x^3+ 4x^2+7x-18$

Width of the highway:

$w = 3x^3-x^2+7x+100 -(x^3+4x^2+7x-18)\n\n= 3x^3-x^2+7x+100 -x^3-4x^2-7x+18\n\n = 2x^3-5x^2+118$

The polynomial equation is $2x^3-5x^2+118$ .

Learn more about polynomial equation here;

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PLEASE HELP ME. I NEED TO ANSWER THIS ASAP. I WILL LOVE YOU FOREVER OMG. Okay so the question is - Keith is racing this little sister Pattie and has given her a 15 foot head start. She runs 5 ft/sec and he is chasing at 8ft/sec. For how long can Pattie stay ahead of Keith?

Answers

Keith runs (8 - 5) = 3 ft per sec faster than Pattie, so every second he gets 3 ft closer to her. If they do that for (15/3) = 5 seconds, he'll catch up to her.

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