Q: At noon the armadillo left the wild kingdom and headed north at 3 kilometers per hour . two hours later the raccoon left the same kingdom and headed south at 5 kilometers per hour . at what time will the animalse be 38 kilometera apart ?

Answers

Answer 1
Answer: Distance of armadillo = V * t = 3t
Distance of racoon = V * (t-2) =5*(t-2)
Distance of armadillo + distance of racoon = 38
3t + 5(t-2)=38
3t + t5 - 10 =38
8t=48
t=6
The anwser is: they will be 38 km apart after 6 hours, so it is 6p.m (12a.m+6 hours) 

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Answers

Answer:

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Step-by-step explanation:

Given that x is directly proportional to y so the expression will be x=k(³y)where k is the constant. First, you have to find the value of k :

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Answers

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Answers

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Answers

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Answers

Answer:

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Step-by-step explanation:

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:)

Answer:

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Step-by-step explanation:

hope i helped

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Answers

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We have then:

We set zero and clear the time:

Then, we evaluate the time obtained for the function of the height.

We have then:

Answer:

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the maximum height is:

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