X2+Y2=25 Is solving this problem considered a function?
How do I plot a graph using a smooth curve for this problem?

Answers

Answer 1
Answer: x^(2) + y^(2) =25 is equation of circle which have radius equal 5 and center in (0,0) point

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Which property explains why these two expressions are equal? 5(g + h) = 5g + 5h A) associative B) commutative C) distributive D) inverse

Answers

The property that explains why these two expressions are equal is the distributive property. Option C is correct.

Given that:

  • 5(g+ h) = 5g + 5h is an example of a distributive property

A distributive property takes the form of distributive law where each algebraic expression is an equal variable.

i.e.

5(g+h) = 5g + 5h

An associative property simply means a rearrangement of algebraic terms in the bracket which doesn't affect the solution of the algebraic expression.

e.g

x + (y+z) = (x+y) + z

So, option A is not correct.

A commutative property means the addition or multiplication of variables by just changing their order without the result being changed.

e.g.

x + y = y + x

So, option B is incorrect.

Learn more about distributive property here:

brainly.com/question/5637942?referrer=searchResults

distributive, duh

associative: a+(b+c)=(a+b)+c
commutative: a+b=b+a
distributive: a(b+c)=ab+ac
inverse: I think it is a times 1/a=1, doesn't matter

answer is C

For the function y = 4x – 11, what is the output when the input is 10?

Answers

= 4x - 11

x is the input, y is the output.

So if you want to know what input is needed to get an output of 10, set y to 10 and solve for x:

10 = 4x - 11

21 = 4x

x = 21/4

How do you make a parabola?

Answers

Make an equation where

Y =
(any number not zero) times X² + (any number at all) times X + (any number at all)

The graph of that equation is guaranteed to be a parabola.

A sequence is defined recursively by f(1)=16 and f(n)=f(n-1)+2n. Find f(4)

1) 32

2) 30

3) 28

4) 34

Answers

f(1)=16 \ \ \ and \ \ \ \ f(n)=f(n-1)+2n \n \nf(2)=f(1)+2\cdot2=16+4=20\n \nf(3)=f(2)+2\cdot3=20+6=26\n \nf(4)=f(3)+2\cdot4 =26+8=34

Ans.\ 4)

When e = 4, f = 2, and g = 8. If e varies jointly with f and g, what is the constant of variation?

Answers

Answer:

The\ constant\ of\ variation\ is\ (1)/(4).

Step-by-step explanation:

As given in the question

If e varies jointly with f and g.

i.e

e \propto fg

e = kfg

Where k is the constant of variation.

As

When e = 4, f = 2, and g = 8

Put in the above

4 = k × 2 × 8

4 = 16k

k = (4)/(16)

k = (1)/(4)

Therefore\ the\ constant\ of\ variation\ is\ (1)/(4).


in joint variation, the equation of variation holds the form 

e=k*fg, where k is the constant of variation. you can see how if either f or g increases, e increases as well, making e vary jointly with f and g. we are given the numbers e=4, f=2, and g=8, so when we input those into the general equations, 

4=k*2*8,
k=1/4

2. What is the sample space for the chance experiment described on this scenario card?

Answers

Answer:18 outcomes

Step-by-step explanation:

There are 18 outcomes on this scenario card. Students can list all of the outcomes or describe them. Here is the list

(the first number is the outcome from Spinner 1, and the second number is the outcome from Spinner 2).