Write an equation of a line that is parallel to y=-6x+4 and passes through(2,10).write an equation of line which is perpendicular to y=(-2/3)x-5 and passes through point (6,3).
write the equation of three lines so that the y-intercept of each is -3.

Answers

Answer 1

Answer: a)y=-6x+4
Slope and intercept a=-6 b=4
equation for new line:
y=cx+d
If new line is parallel c=a=-6 so
y=-6x+d
We substitude point (2,10)
10=-6*2+d /+12
d=22
so y=-6x+22
b)
y=- $(2)/(3)$ x-5
a=-2/3
b=-5
new line:
y=ex+f
If line is perpendicular e=- $(1)/(a)$
so e= $(3)/(2)$
we can write
y= $(3)/(2)x+f$
Substituting point (6,3)
3= $(3)/(2)*6+f$
f=3-9
f=-6
y= $(3)/(2)x-6$

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If the green spinner is spun and then the purple spinner is spun, creating a two-digit number, what is the probability that the resulting number will be 14 or less

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Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi. a. C = 11π; A = 44π
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d. C = 22π; A = 121π

Answers

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At a high school, students can choose between three art electives, four history electives, and five computer electives. Each student can choose two electives. Which expression represents the probability that a student chooses an art elective and a history elective?

Answers

Answer:

$(^3C_1* ^4C_1)/(^(12)C_2)$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1* ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^(12)C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=(^3C_1* ^4C_1)/(^(12)C_2)$

Which is the required expression.

Answer: Hello!

we have:

3 art electives

4 history electives

5 computer electives

which adds to a total of 12.

If the selection is random, each elective has the same probability.

The probability of selecting an art electives is the quotient between the number of art electives and the total number of electives:

3/12

suppose that this event is true, now we need to see the probability of choosing also a history elective;

We do the same process as before, we have 4 history electives and, because we already selected 1 in the previous step, we have a total of 11 electives:

the probability now is 4/11.

Now we want to calculate the joint probability of bot events is equal to the product of their probabilities; this is:

p= (3/12)*(4/12) = (4*3)/(11*12) = 12/(11*12) = 1/11

But there is also the case where the selection is in the other order (first history and second art) so the probability is equal to

2*1/11 = 2/11

How do I find w using this table?

Answers

try mixing the numbers and put it in order. you can figure out what w represents as u find the missing number

What is the average of 37, 22, 52, 17, 16, and 25

Answers

28.1666666666666.....

A company says its premium mixture of nuts contains 10% Brazil nuts, 20% cashews, 20% almonds, and 10% hazelnuts, and the rest are peanuts. You buy a large can and separate the various kinds of nuts. Upon weighing them, you find there are 112 grams of Brazil nuts, 183 grams of cashews, 207 grams of almonds, 71 grams of hazelnuts, and 446 grams of peanuts. You wonder whether your mix is significantly different from what the company advertises. a) Explain why the chi-square goodness-of-fit test is not an appropriate way to find out. b) What might you do instead of weighing the nuts in or- der to use a test