CHEMISTRY HIGH SCHOOL

What is the volume of 0.30 M NaOH(aq) neededto completely neutralize 15.0 milliliters of
0.80 M HCl(aq)?
(1) 3.6 mL (3) 20. mL
(2) 5.6 mL (4) 40. mL

Answers

Answer 1
Answer:

Answer:  4) 40 ml

Solution :

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of NaOH solution = 0.30 M

V_1 = volume of NaOH solution = ?

M_2 = molarity of HCl solution = 0.80 M

V_2 = volume of HCl solution = 15 ml

Now put all the given values in the above law, we get the volume of NaOH solution.

(0.30M)* V_1=(0.80M)* (15ml)

V_1=40ml

Therefore, the volume of 0.30 M NaOH required to neutralize 15 ml of 0.80 M HCl is 40 ml.
Answer 2
Answer:

Final answer:

The volume of 0.30 M NaOH(aq) needed to neutralize 15.0 milliliters of 0.80 M HCl(aq) is 40 milliliters.

Explanation:

The volume of 0.30 M NaOH(aq) needed to neutralize 15.0 milliliters of 0.80 M HCl(aq) can be determined using the concept of stoichiometry and the balanced equation for the reaction between NaOH and HCl. The balanced equation is:

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl. Therefore, the number of moles of HCl in 15.0 milliliters of 0.80 M HCl solution can be calculated as:

Moles of HCl = Volume (in liters) × Molarity = 0.015 liters × 0.80 moles/liter = 0.012 moles

Since 1 mole of NaOH reacts with 1 mole of HCl, we need 0.012 moles of NaOH. The volume of 0.30 M NaOH solution can be determined by rearranging the equation:

Volume (in liters) = Moles / Molarity = 0.012 moles / 0.30 moles/liter = 0.04 liters = 40 milliliters

Therefore, the volume of 0.30 M NaOH(aq) needed to completely neutralize 15.0 milliliters of 0.80 M HCl(aq) is 40 milliliters.

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Answers

To solve this we use the equation, 

M1V1 = M2V2

where M1 is the concentration of the stocksolution, V1 is the volume of the stock solution, M2 is the concentration ofthe new solution and V2 is its volume.

3 M x V1 = 0.50 M x .400 L

V1 = 0.07 L or 66.67 mL of the 3M sodium hypochlorite solution


The correct answer is the second option given.

Answer:

V2 = 66.67mL

Explanation:

Hello! To calculate this we have to take into account the equation that relates two substances:

M1 * V1 = M2 * V2

We have the concentration and volume of a substance and the concentration of the second. We have to find out the volume.

M1 = 0.5M  

V1 = 400mL

M2 = 3M  

V2 = (M1 * V1) / M2

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Answers

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