The width of a rectangle is 5 feet, and the diagonal is 8 feet. Which is the area of the rectangle? (Round to nearest hundredth.)

Answers

Answer 1
Answer: The \ formula \ for \ the \ area \ of \ a \ rectangle \ is: \n\nA=l\cdot w\n where \ l \ is \ the \ length, \ w \ is \ the \ width \n\n w = 5 \feet , \n diagonal: \ d= 8 \ feet \n \n apply \ the \ Pythagorean \ Theorem:

d^2=w^2+l^2 \n \nl^2=d^2-w^2\n\nl^2=8^2-5^2\n\nl^2=64-25\n\nl^2=39

l=√(39)\n\nl \approx 6.244998 \ feet\n\nA= 6.244998 * 5= 31.22499\approx 31.23 \ feet^2



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A 3 by 4 rectangle is inscribed in circle. What is the circumference of the circle?a. 2.5π
b. 3π
c. 5π
d. 4π
e. 10π

Answers

the diameter is the diagonal of the rectangle. Using the pythagorean theorem, you get the diameter being 5. The circumfrance is the diameter*(pi). So the answer is 5(pi). C

El ministerio de educación publicó los resultados obtenidos por los colegios en la última prueba icfes saber 11. En el colegio San estaban el promedio de los estudiantes en la prueba de razonamiento cualitativo fue de 75,8 ¿ que significa este resultado?

Answers

Answer:

El indicador mencionado en el enunciado indica que la suma de los resultados de las pruebas de razonamiento cualitativo de los estudiantes dividido por la población de los estudiantes arroja ese promedio.

El promedio indica el valor "central" del indicador, no estudia la dispersión de los resultados de las pruebas, es decir, como se distribuye la colección de indicadores.

Step-by-step explanation:

El indicador mencionado en el enunciado indica que la suma de los resultados de las pruebas de razonamiento cualitativo de los estudiantes dividido por la población de los estudiantes arroja ese promedio.

El promedio indica el valor "central" del indicador, no estudia la dispersión de los resultados de las pruebas, es decir, como se distribuye la colección de indicadores.  

Please help me, find the slope and y intercept and then write the linear equation from the x/y table

Answers

Answer:

Step-by-step explanation: table y is going up by 6 and table x is going up by 2 which I would put as a fraction. That would be 6/2 and you divide the fraction. 6 divided by 2 equals 3 so I think the y- intercept would be y = 3x

(I'm sorry if its wrong )

Find the GCF of each expression. Then factor the expression. 25b^2 - 20b

Answers

Hello!

The prime factors of these two numbres are :

25b^2 = 5^2* b^2\n 20b = 5* 2^2 * b

The GCF can be calculated by multiplying common primes factors :
5* b = 5b

So the GCF is 5b and the expression can be factored this way :
25b^2 - 20b = 5b* 5b - 4* 5b = 5b\left(5b-4\right)

Which expression is equivalent to (6x3+3x2+8)+(2x2−9x+10)?

Answers

The equivalent expression is 6x^3+5x^2-9x+18.

What is an algebraic expression?

An expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc.). Algebraic expressions include at least one variable and at least one operation.

For the given situation,

The expression is (6x^3+3x^2+8)+(2x^2-9x+10)

6x^(3)+3x^(2) +8 +2x^(2) -9x+10

Rearrange the expression in decreasing order of polynomial,

6x^(3)+3x^(2)+2x^(2) -9x+8+10

Now add the like terms,

6x^(3) +5x^(2) -9x+18

Hence we can conclude that the equivalent expression is 6x^(3) +5x^(2) -9x+18.

Learn more about algebraic expression here

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Answer:

Which expression is equivalent to (6x3+3x2+8)+(2x2−9x+10)?

Step-by-step explanation:  

6x3+3x2+8)+(2x2−9x+10)?

Emil's backpack weighs six and three eights pounds. He removes a book that weighs three fourth pound. Then he removes a book that weighs one half pound .How much does Emil's back pack weigh now

Answers

Answer:

Emil's back pack weigh now 5(1)/(8)\ pounds.

Step-by-step explanation:

Given:

Total Weight of backpack = 6(3)/(8)\ pounds

6(3)/(8)\ pounds can be Rewritten as (51)/(8)\ pounds

Weight of backpack =  (51)/(8)\ pounds

Weight of Book 1 = (3)/(4)\ pound

Weight of Book 2 = (1)/(2)\ pound

We need to find weight of back pack after removing books.

Solution:

Now we can say that;

weight of back pack after removing books can be calculated by Subtracting Weight of Book 1 and Weight of Book 2 from Total Weight of backpack.

framing in equation form we get;

weight of back pack after removing books = (51)/(8)-(3)/(4)-(1)/(2)

Now to solve the equation we will first make the denominator common using LCM.

weight of back pack after removing books =(51*1)/(8*1)-(3*2)/(4*2)-(1*4)/(2*4)=(51)/(8)-(6)/(8)-(4)/(8)

Now the denominators are common so we will solve the numerator.

weight of back pack after removing books = (51-6-4)/(8)=(41)/(8)\ pounds \ \ OR \ \ 5(1)/(8)\ pounds

Hence Emil's back pack weigh now 5(1)/(8)\ pounds.