MATHEMATICS HIGH SCHOOL

 bisects EOG. EOF = y + 30 and FOG = 3y – 50. Solve for y. 20
70
40
50

Answers

Answer 1
Answer:

Answer:  the correct option is (C) 40.

Step-by-step explanation:  As shown in the attached figure below, the line OF bisects the angle EOG, where

m\angle EOF=y+30,\n\nm\angle FOG=3y-50.

We are to find the value of y.

Since  OF is the bisector of the angle EOG, so it divides the angle EOG into two congruent angles.

Therefore, we get

m\angle EOF=m\angle FOG\n\n\Rightarrow y+30=3y-50\n\n\Rightarrow 3y-y=30+50\n\n\Rightarrow 2y=80\n\n\Rightarrow y=(80)/(2)\n\n\Rightarrow y=40.

Thus, the value of y is 40.

Option (C) is CORRECT.
Answer 2
Answer: since given it bisects EOF must be equal to FOG

y+30 = 3y-50

2y = 80

y = 40

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Answers

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