What is the major difference between a solution and an ordinary mixture?

Answers

Answer 1
Answer: An ordinary mixture can be separated without using chemicals, a solution cannot.
Answer 2
Answer: The major difference between a solution and an ordinary mixture is that solution is homogeneous and an ordinary mixture is heterogeneous.

Related Questions

For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, and 68.5 moles of H2S. Calculate the numerical value of the Keq of this system. K = Are the products or reactants favored? The equilibrium system N2O4(g) 2NO2(g) was established in a 1.00-liter vessel. Upon analysis, the following information was found: [NO2] = 0.500 M; [N2O4] = 0.0250 M. What is the value of Keq? 3.Which is the correct expression for Keq when the chemical reaction is as follows: N2 + 3H2 2NH3. 4.Reactions which do not continue to completion are called ______reactions.
The metalloid that has three valence electrons is?
Which of the following is a product formed when NaCl decomposes? A. Na2 B. Nac2 C. cl2
What is the pH of an aqueous 0.032 M pyridine, (C5H5N)? (Kb for pyridine = 1.7 x 10–9)
In which type of chemical reaction do two or more reactants combine to form one product, only?a. synthesis b. decomposition c. single replacement d. double replacement.

What is the pressure of 64 grams of O2 in a 1L container at a temperature of 10°C?

Answers

So PV=nRT
P=?

We know that:
-V=1L
-R=8.314kPa•L/mol•K
-T=10°C (we need to converse °C in K so 10+273) =283K
For n, we know that we have 64g of O2 and were looking for the quantity of mole in these 64g. 1 mole of O2 is 15.999g so 64g would be 4.0mol ((64g • 1mol)/15.999g) so n=4.0

P•1L= 4.0mol • 8.314kPa•L/mol•K • 283K
P • 1L = 9411
P = 9411/1L
P = 9411kPa

How many moles of h2o would be produced from 1.75 moles of o2 with unlimited c3h6

Answers

1.75 (moles O2) × 6 (moles H2O) ÷ 9 (moles O2) = 1.17 (moles H2O)

You have to convert moles of O2 into moles of H2O so it's the number of moles you start with (1.75 O2) × the number of moles from the element you want (6 H20), then ÷ by the number of moles that the element that you already have (9 O2).

When a mixture of iron powder and sulphur is heated it glows more brightly than that of iron filings and sulphur.Explain this observation

Answers

Answer:

I don't know

Explanation:

mixture of iron powder and sulphur heated it glows because sulphur and iron are more reactive metals that they shine and sulphur can react with water produce fire it's write

Which statement describes a chemical propertyof sodium?
(1) Sodium has a melting point of 371 K.
(2) Sodium has a molar mass of 23 grams.
(3) Sodium can conduct electricity in the liquid
phase.
(4) Sodium can combine with chlorine to produce
a salt.

Answers

Answer;

(4) Sodium can combine with chlorine to producea salt.

Explanation;

Sodium is an alkali metal (group 1 ) in the periodic table. It is a soft metal, reactive and with a low melting point. It has an atomic weight of 23 grams.

Sodium is a good conductor of electricity due to the presence of delocalized electrons in its metallic structure. It reacts vigorously with water to produce sodium hydroxide and hydrogen.

-When exposed to air, metallic sodium recently cut looses its silvery appearance and acquires an opaque grey color due to the formation of a sodium oxide coating.

(4) Sodium can combine with chlorine to produce a salt is the correct answer. The other three are just physical properties~

What is the half-life of sodium-25 if 1.00 gram of a 16.00-gram sample of sodium-25 remains unchanged after 237 seconds?(1) 47.4 s (3) 79.0 s
(2) 59.3 s (4) 118 s

Answers

Given,
1 gram remain out of 16 grams after 237 seconds.

So, 
1g -> 2g -> 4g -> 8g -> 16g
So, 4 half lives have taken palce.

So,
we divide 237 by 4 and we get our answer.

So,
234 / 4 = 59.25 ≈ 59.3

So, the answer is (2) 59.3 seconds

Final answer:

The half-life of sodium-25, when 1.00 gram of a 16.00-gram sample remains unchanged after 237 seconds, is approximately 59.3 seconds. This solution was found by calculating the number of times the sample halved and dividing the total time by this figure.

Explanation:

The question asks for the half-life of sodium-25 if 1.00 gram of a 16.00-gram sample remains unchanged after 237 seconds. In nuclear physics and nuclear chemistry, the half-life is the amount of time it takes for half of a sample of a radioactive substance to undergo decay.

Given that sodium-25 has gone from 16 grams to 1 gram, we can see that 1/16th of the original amount is left after 237 seconds. In other words, the quantity of sodium-25 has halved approximately 4 times. Therefore, the half-life will be the total time divided by the number of half-lives.

By dividing 237 seconds by 4, we get 59.25 seconds. So, the closest accurate answer is (2) 59.3s.

Learn more about Half-life here:

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What do elements and compounds have in common? And how do they differ?I will mark brainliest for the best answer.

WARNING: DON'T PUT LINKS I WILL REPORT YOU!

Answers

elements and compounds might appear different, yet they share many similarities, like being made up of atoms and having bonds linking their atoms together. Elements and compounds also share the qualities of being both pure and homogeneous substances. Substances can be categorised as either elements or compounds. Both of these are made up of atoms, the only difference is an element is made of one type of atom whereas compounds are made of two or more different types of atoms.