A 4.0-kilogram ball moving at 8.0 m/s to the right collides with a 1.0-kilogram ball at rest. After the collision, the 4.0-kilogram ball moves at 4.8 m/s to the right. What is the velocity of the 1-kilogram ball?

Answers

Answer 1

Answer: Use conservation of momentum. Check to see if your answer makes sense. A heavy ball moving right hits a stationary ball. Afterwards they should both be moving right and the lighter ball should be moving faster.

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In which space, outdoors or in your classroom, would it be easier to hear a musician? Explain

The waste products of a nuclear fission powerplant can best be described asa. Small in quantity and not very dangerous.
b. Large in quantity and not very dangerous.
c. Large in quantity and very dangerously radioactive. Eliminate
d. Small in quantity and very dangerously radioactive.

Answers

The answer is D. small in quantity and very dangerously radioactive.

a.

-> the products are stable atoms with a much lower atomic number. For example, Uranium 238 commonly breaks down into strontium and xenon, both of which are stable and non-radioactive.

They are also low in quantity because of the precision involved in breaking down a large atom via neutron capture means that few fission reactions take place.

Hope I helped :)

Source: I studied nuclear physics in year 11

A stone with a mass of 0.70 kg is attached to one end of a string 0.80 m long. The string will break if its tension exceeds 65.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. Find the maximum speed the stone can attain without breaking the string.

Answers

Answer:

The maximum speed the stone can attain without breaking the string is 8.62 m/s .

Explanation:

Given :

Mass of stone , m = 0.7 kg .

Length of string , l = 0.8 m .

It is also given that the stone will break if its tension exceeds 65.0 N.

Now , we know tension in the rope due to rotation is equal to the centripetal acceleration .

Therefore , the maximum speed the stone can attain without breaking the string is less than or equal to 65 N .

So , $(mv^2)/(r)=65$

Putting all value in above equation we get :

$(0.7* v^2)/(0.8)=65\n\nv= 8.62\ m/s$

Therefore , maximum speed the stone can attain without breaking the string is 8.62 m/s .

a ball is thrown upward at 25 m/s from the ground. what is the average velocity and average speed of the ball after 5 seconds?

Answers

When the ball reaches the highest point, its velocity will be zero. So final velocity is v=0m/s
Here, the time to reach highest point is equal to time to hit ground from highest point.
Consider upward motion, the acceleration of the ball is a=−g=−9.8m/s
2
(minus for motion opposite to gravity)
If t be the required time.
Using v=u+at,
0=25+(−9.8)t
⟹ t=2.5s
Thus the ball hits the ground after 2.5 seconds after reaching its highest point.

How does is the terminal velocity of a feather different from the terminal velocity of an egg?

Answers

if under vacuum the terminal velocity of the egg and feather would be the same because only the acceleration due to gravity is only force acting on it. but at normal condition, their terminal velocity are different because to wind resistance and shape factor that will contribute resistance of an object to go down.

Answer:

The terminal velocities will be the same in a vacuum and different for the egg and further.

Explanation:

Thinking process:

The terminal velocity is the maximum velocity that an object can attain after overcoming the resistance caused by the atmosphere or air. In other words, the velocity equation is given as:

$F_(net) = D -W$

where F is the net force,

D = Drag force

W = Weight of the object falling down.

The drag force increases by the increase with the square of the velocity like this:

$W = C_(d) \frac{\rhoV^(2)A } {2}$

The terminal velocity is given by the equation:

V = Sqrt (2W/CdpA)

In the absence of friction, like a vacuum, the velocities are the same.

In the atmosphere, there is drag, and the velocities are different.

Lightning often strikes water.
a. True
b. False

Answers

It is true.
..............

Where is the field of each charge the strongest ?(A. positive charge arrows pointed out)
(B.negative charge arrows pointed inward)

Answers

First we have to agree on what you mean by "strongest".

To me, "strongest" means the place where it exerts the greatest
force on another charge that happens to be passing by.

In both cases ... 'A' and 'B' ... that's going to be right smack on top
of the charge itself, or as close to it as you can get.

On drawings, it's the spot where the field 'lines' are closest together.

It makes no difference whether the original charges are positive or negative.

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