ricardo has 2 cases of video games with the same number of game in each cases . he give 4 games to his brothers . Ricardo has 10 games left. How many video games were in each case ?

Answers

Answer 1

Answer: 12 because you split the 4 from the two boxes.

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Jalen bought 24 juice packs for $7.20. Tia bought 6 juice packs for $2.70. Which statement describes the difference in the unit prices of Jalen's and Tia's juice packs

Answers

Answer:

$10

Step-by-step explanation:

Help please this needs to be done quickly

Answers

Answer:

there is no inequality

only size of the graph is different

Step-by-step explanation:

Answer:

x $\leq$ 2

Step-by-step explanation:

If the dot is closed, then you would use the "greater than or equal to" symbol. Next, you would use any letter you like as the variable and put it on the left side of the equation. Then, you need to find where the dot is (in this case 2) and put the 2 on the right side of the equation. And lastly, write it down, or type it down. There you go.

What is 18+6x=41+4x,x

Answers

Answer:

x=11.5

Step-by-step explanation:

18+6x=41+4x

Subtract 4x from each side

18+6x-4x=41+4x-4x

18+2x = 41

Subtract 18 from each side

18-18 +2x = 41-18

2x =23

2x/2 = 23/2

x =11.5

max found a jacket on sale for 35% Off its original price. what percent of the original price will max pay for the jacket

Answers

Say the price was $100 to level out everything. 35% is $35. $100-$35=$65. So, Max will pay 65% of the original price

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=5.Calculate (a)the common ratio. (b)the first term of this geometric sequence

Answers

1 step: $S_(5)=T_(1)+T_(2)+T_(3)+T_(4)+T_(5)$ , $S_(3)=T_(1)+T_(2)+T_(3)$ , then
$S_(5)-S_(3)=T_(4)+T_(5)=5$ .

2 step: $T_(n)=T_(1)*q^(n-1)$ , then
$T_(6)=T_(1)*q^(5)$
$T_(5)=T_(1)*q^(4)$
$T_(4)=T_(1)*q^(3)$
$T_(3)=T_(1)*q^(2)$
and $\left \{ {{T_(6)-T_(4)= (5)/(2) } \atop {T_(5)+T_(4)=5}} \right.$ will have form $\left \{ {{T_1*q^(5)-T_(1)*q^(3)= (5)/(2) } \atop {T_(1)*q^(4)+T_(1)*q^(3)=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^(3)*(q^(2)-1)= (5)/(2) } \atop {T_(1)*q^(3)*(q+1)=5} \right.$ and dividing first equation on second we obtain $(q^(2)-1)/(q+1)= ( (5)/(2) )/(5)$ . So, $((q-1)(q+1))/(q+1) = (1)/(2)$ and $q-1= (1)/(2)$ , $q= (3)/(2)$ - the common ratio.

4 step: Insert $q= (3)/(2)$ into equation $T_(1)*q^(3)*(q+1)=5$ and obtain $T_(1)* (27)/(8)*( (3)/(2)+1 ) =5$ , from where $T_(1)= (16)/(27)$ .

Simplify the expression 6x+12y+5+2y+8 what is the coefficient of y and what is the constant

Answers

we want to find the coeficient of the y terms when added together so find all the y terms

+12y and +2y
we add them together
12y+2y=(12+2)y=(14)y=14y
coeficient is 14

the constant is the number that is set already or the number that doesn't have it multiplied by a placeholder exg. 4 is a constnat but 4x is not so find the constants
+5 and +8
we add
5+8=13
the constant is 13

y coeficient=14
constant=14

6x+12y+5+2y+8
= 6x+ (12y+2y)+ (5+8) (combine like terms)
= 6x+ 14y+ 13

Coefficient of y: 14
Constant: 13

Hope this helps~

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