A dispenser holds 5652 cm3 of liquid soap and is now full. The radius of the dispenser is 7.5 cm. What is the difference between the height of the soap in the full dispenser and the height when 4239 cm3 of soap remains in the dispenser? Use 3.14 to approximate pi.

Answers

Answer 1

Answer: 30cm is the difference between the height of the soap in the full dispenser and height of the remaining soap.

The formula for cylindrical height is:

  Area
  --------   - r
2 * π * r

Cylindrical height of full dispenser.

  5652 5652
--------------------- - 7.5 = ------------ - 7.5 = 120 - 7.5 = 112.50
2 * 3.14 * 7.5 47.1

Cylindrical height of dispenser with lesser liquid soap

4239 4239
-------------------- - 7.5 = ------------ - 7.5 = 90 - 7.5 = 82.50
2 * 3.14 * 7.5 47.1

Cylindrical height of full soap      112.50
Cylindrical height of lesser soap     - 82.50
Difference in height of soap content 30.00

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Answers

1&g 2&f 3&b 4&h 5&c 6&d 7&e 8&a

Step-by-step explanation:

Yea what he said cause I kinda need points

Factorise 12pr + 2st - 3pt -8rs

Answers

if you have 12 pr's, and you take 3 away... you're left with 9 pr's....
12pr + 2st - 3pr -8rs
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Arnie's car used 100 cups of gasoline during a drive.He paid $3.12 per gallon of gas.How much did the gas cost?

Answers

There are 16 cups in a gallon. Divide 100 into 16 to get 6.25. You now just multiply 3.12 by 6.25 to get 19.5. Your answer is $19.50. Hope this helps!

32 pens to 40 brushes what is the ratio of pens to brushes written as a fraction in simplest form answers

Answers

The answer is 4 over 5 because 32 divided by 8 is 4 and 40 divided by 8 is 5

32/40 simplified is going to be 4/5 or it can be written as 4:5 or 4 to 5

Lines g,h, and i are all parallel and m------->1 =55*What is m<12?
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D.125*

Answers

It would be C:55,
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Jason has two bags with 6 tiles each. The tiles in each bag are shown below:1 2 3 4 5 6

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?

Answers

The probability of drawing a tile numbered 5 from the first bag and an odd tile from the second bag is ¹/₁₂

Given;

numbers of tiles in each bag, 1, 2, 3, 4, 5, 6

To find:

the probability of drawing a tile numbered 5 from the first bag and;

an odd tile from the second bag

The first draw: there is only one tile numbered 5

$The \ probability = (1)/(6)$

The second draw: there are 3 odd numbers (1, 3, 5)

$The \ probability = (3)/(6) = (1)/(2)$

The combined probabilities:

$The \ probability = (1)/(6) * (1)/(2) = (1)/(12)$

Therefore, the probability of drawing a tile numbered 5 from the first bag and an odd tile from the second bag is ¹/₁₂

To learn more about probability, please visit: brainly.com/question/24141156

To answer this question, you can use basic probability: The chance of getting tile number 5 from the first bag is 1/6 as it is for all other tiles in the same bag. The chance of getting an odd tile from the second bag is 3/6 as it is for getting an even tile. By multiplying the two, we get a total probability of 1/12.

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