23g of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.

Answers

Answer 1
Answer:

Answer: The mass of sodium chloride formed will be 58.5 g

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • For Sodium:

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium}=(23g)/(23g/mol)=1mol

  • For chlorine gas:

Given mass of chlorine gas = 35.5 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

\text{Moles of chlorine gas}=(35.5g)/(71g/mol)=0.5mol

The chemical reaction for the formation of sodium chloride follows the equation:

2Na+Cl_2\rightarrow 2NaCl

By stoichiometry of the reaction:

2 moles of sodium reacts with 1 mole of chlorine gas.

So, 1 mole of sodium will react with = (1)/(2)* 1=0.5mol of chlorine gas.

Thus, the formation of sodium chloride can be calculated by using any of the reactant.

By stoichiometry of the reaction:

2 moles of sodium produces 2 moles of sodium chloride.

So, 1 mole of sodium will react with = (2)/(2)* 1=1mol of sodium chloride.

Now, calculating the mass of sodium chloride by using equation 1, we get:

Moles of sodium chloride = 1 mole

Molar mass of sodium chloride = 58.5 g/mol

Putting values in equation 1, we get:

1mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\n\n\text{Mass of NaCl}=58.5g

Hence, the mass of sodium chloride formed will be 58.5 g

Answer 2
Answer: 58.5 is the final mass of the compound as long as any gases the reaction causes to be

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Answers

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Answers

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Read more on speed here: brainly.com/question/10545161

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