(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^

Answers

Answer 1

Answer: $(sin\theta+sec\theta)^2+(cos\theta+cosec\theta)^2=(1+sec\theta\ cosec\theta)^2\n\nL=sin^2\theta+2sin\theta\cdot(1)/(cos\thewta)+(1)/(cos^2\theta)+cos^2\theta+2cos\theta\cdot(1)/(sin\theta)+(1)/(sin^2\theta)\n\n=(sin^2\theta+cos^2\theta)+(2sin\theta)/(cos\theta)+(2cos\theta)/(sin\theta)+(1)/(cos^2\theta)+(1)/(sin^2\theta)$

$=1+(2sin^2\theta+2cos^2\theta)/(sin\theta\ cos\theta)+(sin^2\theta+cos^2\theta)/(sin^2\theta\ cos^2\theta)\n\n=1+(2(sin^2\theta+cos^2\theta))/(sin\theta\ cos\theta)+(1)/(sin^2\theta\ cos^2\theta)\n\n=1+(2)/(sin\theta\ cos\theta)+(1)/(sin^2\theta\ cos^2\theta)\n\n=1^2+2sec\theta\ cosec\theta+sec^2\theta\ cosec^2\theta\n\n=(1+sec\theta\ cosec\theta)^2=R$

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HELP ASAP ILL GIVE A THANKS AND BRAINLIEST Which combined inequality has the same solution set shown in the graph of x?

–3 x ≥ –1

–3 ≤ x > –1

Answers

Answer:

-3 < x ≤ -1

Step-by-step explanation:

we know that

The solution of the graph is equal to the interval

All real numbers greater than -3 and less than or equal to -1

so the combined inequality is equal to -3 < x ≤ -1!!!!

Which of the following demonstrates the commutative property across multiplication for 2× 10 × 7A. 10 ×7 × 2
B. 2 × (10 × 7)
C. (2 × 10) × 7
D. 2 + 10 × 7

Answers

Its A. Kelp dont you dare.

Hey there, commutative property is when you mix up the numbers but you will still the same answer. 2*10*7=140. 10*7*2=140. Therefore, the answer would be A. 10*7*2

Would the scale factor 7/2 enlarged, reduced, or preserve??

PLEASE HELP ME