A cylinder has the circumfrence of 16 $\pi$ inches and its height is half the radius of the cylinder. What is the total surface area of the cylinder? Give your answer in terms of $\pi$ . Explain how you found your answer.

Answers

Answer 1

Answer: Circumference = 2 $\pi$ r
If the circumference of the base of the cylinder is 16 $\pi$ then
16 $\pi$ = 2 $\pi$ r
Divide by 2 on both sides.
8 $\pi$ = $\pi$ r
Divide by $\pi$ on both sides.
8=r

So our radius is 8. So the height of the cylinder is 8/2 = 4.

The surface area of a cylinder is
$SA=2\pi rh+2\pi r^2$

Just plug in r as 8 and h as 4.

$SA=2\pi (8)(4)+2\pi (8)^2$
$SA=2\pi 32+2\pi 64$
$SA=64\pi + 128\pi$
$SA=192\pi$

The surface area is ${\boxed{192\pi}$ .

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8% of 44 show work please and an answer ciz i domt understand

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Hey there!

These are the steps involved in answering the question:

Change 8% into a decimal. To do this, just move the decimal place, 2 places to the left.
You get 0.8

Now, multiply 0.8 by 44.
0.8 x 44 = 35.2

So, the final answer is: 35.2.

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