MATHEMATICS HIGH SCHOOL

Please help me solve for x:

t=pd/2x
please help me solve for x: t=pd/2x - 1

Answers

Answer 1
Answer:

Answer: x=(pd)/(2t)

Step-by-step explanation:

The given expression : t=(pd)/(2x)

To solve the above expression, we first multiply x on both the sides , we get

t* x=(pd)/(2x)*x\n\n\Rightarrpw\ tx=(pd)/(2)

Now, we divide t on both the sides , we get

x=(pd)/(2t)

Hence, the expression for x will be : x=(pd)/(2t)
Answer 2
Answer: t = pd/2x
multiply 2x from both sides
2xt = pd
divide 2t from both sides to isolate x
x = pd/2t

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Answers

We must simplify the expression. Simplify the like terms. 7d-4d=3d and 12-3=9. Put them together. Our answer is 3d+9.
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Which values are within the range of the piecewise-defined function?f(x) =
2 x + 2 x < - 3
X x = -3
- x - 2 X > -3
y = -6
y=-4
y=-3
y = 0
y = 1
y = 3

Answers

-6, -4, -3, and 0 are the values which are within the range of the piecewise-defined function.

Correct options: a) y = -6, b) y = -4, c) y = -3, d) y = 0

Here, we have, to determine which values are within the range of the piecewise-defined function, we need to evaluate the function for each given value of y.

Given piecewise-defined function:

f(x) =

2x, x < -3

x, x = -3

-x - 2, x > -3

Let's evaluate the function for each value of y:

a) y = -6

For y = -6, we need to find x such that f(x) = -6.

-6 is in the range of the function if there exists an x such that f(x) = -6.

For x < -3: f(x) = 2x

2x = -6

x = -3

For x = -3: f(x) = x

x = -3

For x > -3: f(x) = -x - 2

-x - 2 = -6

x = 4

Since there is a value of x (-3) that satisfies f(x) = -6, option a) y = -6 is correct.

b) y = -4

For y = -4, we need to find x such that f(x) = -4.

-4 is in the range of the function if there exists an x such that f(x) = -4.

For x < -3: f(x) = 2x

2x = -4

x = -2

For x = -3: f(x) = x

x = -3

For x > -3: f(x) = -x - 2

-x - 2 = -4

x = 2

Since there is a value of x (-3) that satisfies f(x) = -4, option b) y = -4 is correct.

c) y = -3

For y = -3, we need to find x such that f(x) = -3.

-3 is in the range of the function if there exists an x such that f(x) = -3.

For x < -3: f(x) = 2x

2x = -3

x = -1.5

For x = -3: f(x) = x

x = -3

For x > -3: f(x) = -x - 2

-x - 2 = -3

x = 1

Since there is a value of x (-3) that satisfies f(x) = -3, option c) y = -3 is correct.

d) y = 0

For y = 0, we need to find x such that f(x) = 0.

0 is in the range of the function if there exists an x such that f(x) = 0.

For x < -3: f(x) = 2x

2x = 0

x = 0

For x = -3: f(x) = x

x = -3

For x > -3: f(x) = -x - 2

-x - 2 = 0

x = -2

Since there is a value of x (-3) that satisfies f(x) = 0, option d) y = 0 is correct.

e) y = 1

For y = 1, we need to find x such that f(x) = 1.

1 is in the range of the function if there exists an x such that f(x) = 1.

For x < -3: f(x) = 2x

2x = 1

x = 0.5

For x = -3: f(x) = x

x = -3

For x > -3: f(x) = -x - 2

-x - 2 = 1

x = -3

Since there is no value of x that satisfies f(x) = 1, option e) y = 1 is incorrect.

f) y = 3

For y = 3, we need to find x such that f(x) = 3.

3 is in the range of the function if there exists an x such that f(x) = 3.

For x < -3: f(x) = 2x

2x = 3

x = 1.5

For x = -3: f(x) = x

x = -3

For x > -3: f(x) = -x - 2

-x - 2 = 3

x = -5

Since there is no value of x that satisfies f(x) = 3, option f) y = 3 is incorrect.

Correct options: a) y = -6, b) y = -4, c) y = -3, d) y = 0

The correct values within the range of the piecewise-defined function are -6, -4, -3, and 0.

To learn more on function click:

brainly.com/question/21145944

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Answer:

-6, -4, -3, 0

Step-by-step explanation:

I just did this question and got it right.

8x^2+4x
FACTOR AND SHOW STEP BY STEOP PLEASE

Answers

Step-by-step explanation:

Я не знаю нажаль ишмщмшмшмшмшмшмшмлмлищишиомомлмилмлмлмшмшмшмлмдили

Estimated: 253 times 46

Answers

I do believe the answer is 11,638 I did this in my head maybe u should try it.
250 x 45 = 11250

Because you round 253 down to 250 and 46 down to 45

Simonne used the following steps to simplify the given expression. 12 - 3(-2x + 4) Step 1: 12 + (–3)·(–2x) + (–3)·(4)
Step 2: 12 + 6x + (–12)
Step 3: 12 + (–12) + 6x
Step 4: 0 + 6x Step 5: 6x

What property of real numbers was used to transition from Step 3 to Step 4?
A. identity property of addition
B. inverse property of addition
C. associative property of addition
D. commutative property of addition

Answers

inverse property of addition
B: inverse property of addition

if k is a constant, determine and state the value of kids such that the polynomial k^2x^3-6kx+9 divisible by x-1

Answers

By the polynomial remainder theorem, k^2x^3-6kx+9 will be divisible by x-1 if the value of the polynomial at x=1 is 0.

k^2(1)^3-6k(1)+9=k^2-6k+9=(k-3)^2=0

which occurs for k=3.
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