Answer:
The better buy is The denim shoppe!
Step-by-step explanation:
the denim shoppe price for 3 jeans is $56 and Jeans jam price of 3 jeans is $56.25! $56 < $56.25.
If Ava buys three pairs of jeans from Jeans Jam, it would cost her a total of $56.23. If Ava buys three pairs of jeans from The Denim Shoppe, it would cost her exactly $56. This means that The Denim Shoppe is a better buy...by 23 cents.
y - 5 = 2/3 ( x + 3)
That's your answer.
The equation of a line that passes through the point (5, -3) with a slope of 2/3, when expressed in point-slope form, is y + 3 = 2/3 * (x - 5).
In Mathematics, the equation of a line can be given in multiple forms, one of those is the point-slope form. The generic form of this equation is y - y1 = m(x - x1), where (x1, y1) are the coordinates of any point on the line and m represents the slope of the line.
Given the slope m = 2/3 and the point on the line (5, -3), the equation is y - (-3) = 2/3 * (x - 5). After simplifying, we have: y + 3 = 2/3 * (x - 5) as the equation of the line.
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Answer: y=-2x+5
Step-by-step explanation:
Y+2x=5
y-2x=5-2x
y=-2x+5
then graph
Answer:
y=-2 x +5
Step-by-step explanation:
Write in slope-intercept form, y=m x+b
YES!! :)
both 6 and 48 are divisible by 6, the greatest common factor.
so you divide both 6 and 48 by 6....
6÷6=1
48÷6=8
Your simplified fraction is now 1/8
You must score 86 points on the fourth test to have an average, or at least 90 points.
The average is calculated as the product of all values divided by all possible values. It can also be described as mean. The mean in statistics is the average value for the particular sample or collection of data. It is determined by dividing the total number of observations by the total number of observations.
Given:
In three math tests,
you score 91,95, and 88 points.
Let n be the score of the fourth test.
To find the average:
The average = (91 + 95 + 88 + n) / 4
90 = (91 + 95 + 88 + n) / 4
(91 + 95 + 88 + n) = 360
n = 360 - 274
n = 86
Therefore, the score of the fourth test is 86.
To learn more about the average;
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