A force is applied to a 30-kg object, resulting in an acceleration of 15 m/s. What is the force being applied to the object?
Answers
The sum of all forces applied to the object = (30) x (15)
= 450 newtons, in the direction of the acceleration.
F=a*m
a=
m=30kg
F=
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Why are the very first stars thought to have been much more massive than the sun? (a the clouds that made them were much more massive than todays star-forming clouds. (b the temperatures of the clouds that made them were higher because the clouds consisted entirely of hydrogen and helium. (c star-forming clouds were much denser early in time?
Process of changing a liquid into a gas
shelly starts from rest on her bicycle at the top of a hill. After 6.0s she has reached a final velocity of 14m/s. what is shellys acceleration.
What is the moment of the couple formed by the two forces applied to the corners b and d of a rectangular plate, given that p = 88-n? Resolve each force into horizontal and vertical components, and add the moments of the resulting couples?
Answers
Horiz recoil mom of gun (M x v) = horiz. mon acquired by shell (m x Vh)
1.22^6kg x 5.0 m/s = 7502kg x Vh
Vh = 1.22^6 x 5 / 7502 .. .. Vh = 813 m/s
Barrel velocity V .. .. cos20 = Vh / V .. ..V = 813 /cos20 .. .. ►V = 865 m/s
2) Using the standard range equation .. R = u² sin2θ /g
R = 865² x sin40 / 9.80 .. .. ►R = 49077 m .. (49 km)
c. vertically along the direction that the wave travels.
d. perpendicular to the path of travel.
Answers
As a longitudinal wave travels through a medium, it displaces the particles parallel to the direction which the wave travels.
What is longitudinal wave?
This type of waves are vibrations that takes place in the same direction i.e parallel to the wave motion. They are usually mechanical and examples include sound waves which requires a medium.
A longitudinal wave is a form of wave in which the displacement of the medium and the medium's vibration are both parallel to the direction of the wave.
A longitudinal wave moves the particles parallel to its direction of passage as it passes through a material.
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Answer:
A- Parallel to tge direction which the wave travels
Explanation:
Answers
Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h
= 222 MJ/h
But 1 hour = 3600seconds
222 MJ/h = 222 MJ/3600s = 0.061667 MW J/s = Watts
Power input = 0.061667 MW = 61 667 W
From Efficiency = Power Output / Power Input
28% = Power Output / 61667
Power Output = 0.28 * 61667
Power Output = 17266.76 W
Power Output = 17 267 W
Rate of heat Rejection = Power input - Power output
= 61667 - 17267 = 44400 W
Rate of heat Rejection = 44 400 W.
C- Copyright.
Answers
The reaction of zinc withhydrochloric acid. Zn + 2HCl → H2 + ZnCl2. In here, zinc, an element, willreplace the halogen chlorine in the compound hydrochloric acid to form ahydrogen gas and zinc chloride molecule.
Answers
Answer:
r= 3.2 cm
Explanation:
Given that
I= 8.7 A
B= 5.4 x 10⁻⁵ T
μo=1.25664 x 10⁻⁶
We know that magnetic filed in wire at a distance r given as
By putting the values
r=0.032 m
r= 3.2 cm
Final answer:
The distance from a long straight wire at which the magnetic field equals the strength of Earth’s field, given a current of 8.7 A and Earth's field of 5.4 × 10−5 T, can be calculated using the formula for the magnetic field around a current-carrying wire. Substituting the given values, the answer is approximately 37.22 cm.
Explanation:
To solve this physics problem, we will use the formula for the magnetic field produced by a current carrying long, straight wire. The formula is: B = μI / (2πr), where 'B' is the magnetic field strength, 'μ' is the permeability of free space, 'I' is the current, and 'r' is the radial distance away from the wire.
In this case, Earth’s magnetic field, 'B', is given as 5.4 × 10−5 T, the current, 'I', is given as 8.7 A, and the permeability of free space, 'μ', is given as 1.25664 × 10−6 T · m/A. We need to find 'r', the distance away from the wire, and we want this answer in centimeters.
So, rearrange the formula to solve for 'r': r = μI / (2πB).
Substitute our known values into the equation: r = (1.25664 × 10−6 T · m/A × 8.7 A) / (2π × 5.4 × 10^-5 T). After calculating, we need to convert from meters to centimeters by multiplying by 100. The final answer is approximately 37.22 cm.
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The volts have decreased.
The power has increased.
Answers
If energy input remains constant and voltage remains the same in a circuit, but the current decreases, the power has increased. It is presented in the equation P = VI where P is power, V is voltage and I is current.