Which statement is true about the following system of equations3x-1/2y=1
x+2y=7
A)y=x
B)y<x
C)it cannot be determined
D)y>x

Answers

Answer 1

Answer: $\left\{\begin{array}{ccc}(3x-1)/(2y)=1\nx+2y=7\end{array}\right\n\n\left\{\begin{array}{ccc}(3x-1)/(2y)=1\n2y=7-x\end{array}\right\n\nsubstitute:\n\n(3x-1)/(7-x)=1\iff3x-1=7-x\n\n3x+x=7+1\n4x=8\nx=2\n\n2y=7-2\n2y=5\ny=2.5\n\nAnswer:D)\ y > x$

Answer 2

Answer: You have to solve the system of equations for 'x' and 'y'. When you do that,
you discover that x=0.846 and y=3.076. So Y > X .

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Gary bought a car for $40,000. If V = 40,000(.85)t represents the value of the car after t years, how long will it take the car to be worth less than one-fourth of its purchase price? A) 4 years B) 6 years C) 8 years D) 9 years
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1344 is 240% of what number

What is 191x21=?????

Answers

191 times 21
191 times 21=191 times (20+1) correct?
therefor
use distributive property
remember that it is a(b+c)=ab+ac
therefor
191 times 21=191(20+1)=191 times 20+191 times 1=191 times 2 times 10+191=382 times 10+191=3820+191=4011
answer is 4011

191
×21
------
191
+382
---------
4011

answer= 4011
hope it helps

Use the zeros of the following quadratic to find the x-value of the vertex.y = x2 – 4x – 5
A.5
B.2
C.–2
D.–5

Answers

1. y = x^2 - 4x - 5
= x^2 - 4x + 4 - 4 - 5
= (x^2 - 4x + 4) -4 - 5
y = (x-2)^2 - 9 Here, the vertex is at (2, -9)

2. x = 2 (the vertical line that goes through the vertex)
3. The graph of this function is called a parabola. To graph a parabola, use
its vertex (in this case, (2, -9) ) and y-intercept (y = -5). The y-intercept is the constant in the given equation. Use the fact that the vertical line through the vertex is a line of symmetry. Plot the point corresponding to the y-intercept that lies on the other side of the vertical line x = 2.

4. The graph is translated 2 units to the right and 9 units down.

Answer:

The answer is B.) 2

(on e2020)

Lowest common multiple of 40 and 220

Answers

Answer:

440

Step-by-step explanation:

Prime factors of 40 = 2 x 2 x 2 x 5

Prime factors of 220 = 2 x 2 x 5 x 11

Common factors = 2² x 5

Prime factors of 40 (excluding common factors with 220) = 2

Prime factors of 220 (excluding common factors with 40) = 11

Multiply the common factors with remaining factors

2² x 5 x 2 x 11

= 440

- A company produces 7,200 gallons ofbottled water each day. The company puts
8 one-gallon bottles in each carton. How.
many cartons are needed to hold all the
one-gallon bottles produced in one day?
Write ur equation plssssss FASTTTSTSTSTSTSSTTSTSSTTS

Answers

Answer:

Number of gallons of water produced each cay by the company = 7200 gallons

Number of 1 gallon bottles put in a carton = 8

Number of cartons needed to hold all the 1 gallon bottles in a day = 7200/8

= 900

So 900 cartons are required to hold all the one gallon bottles produced by the company in a day. I hope the procedure is clear enough for you to understand. It is also important to carefully look at all the details that are provided in the question.

Answer:

900 cartons are needed

Step-by-step explanation:

7200/8=900

Lucas had $272 and Kelly had $804. Both of them spent the same amount of money. The ratio of Lucas' to Kelly's money than became 2:9. How much did they spend altogether?

Answers

$x-\ money\ spend\n\n(272-x)/(804-x)=(2)/(9)\ \ \ \ | cross\ multiplication\n\n9(272-x)=2(804-x)\n\n2448-9x=1608-2x\ \ \ | add\ 2x\n\n2448-7x=1608 \ \ \ | subtract\ 2448\n\n-7x=-840\ \ \ | divide\ by\ -7\n\nx=120\n\nThey\ spend\ together\ 240\$$