What is the percent by mass of chlorine in NaCl?

Answers

Answer 1
Answer:

The percent  by mass  of chlorine  in NaCl is 60.68 %  of chlorine

 calculation


mass %  of chlorine =mass  of chlorine /mass  of NaCl  x 100


from periodic table the  mass of cl= 35.5  g/mol  

                                       that of   of Na  = 23  g/mol

The mass of NaCl is therefore  = 35.5 g/mol + 23 g/mol  =58.5  g/mol


mass %  is therefore=  (35.5 / 58.5   x 100) =60.68 %

Answer 2
Answer:

In the given question, 60.66% is the percent by mass of chlorine in NaCl.

Mass is a physical property of matter that measures the amount of substance in an object. It is typically measured in grams (g) or kilograms (kg).

The molar mass of NaCl is 58.44 g/mol. The molar mass of chlorine is 35.45 g/mol. The formula of NaCl indicates that there is one chlorine atom for every sodium atom. Therefore, the mass of chlorine in NaCl is 35.45 g/mol.

To calculate the percent by mass of chlorine in NaCl, we need to divide the mass of chlorine by the total mass of NaCl and multiply by 100. This can be expressed as follows:

Percent by mass of chlorine = (mass of chlorine/mass of NaCl) × 100

Substituting the values, we get:

Percent by mass of chlorine = (35.45 g/mol/58.44 g/mol) × 100

= 60.66%

Therefore, the percent by mass of chlorine in NaCl is 60.66%.

Learn more about mass here:

brainly.com/question/11954533

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Answers

Answer

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Explanation:

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Which chemical equation describes an acid-base neutralization reaction?

Answers

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What is the percent composition by mass of nitrogen in (NH4)2CO3 (gram-formula mass = 96.0 g/mol)? (1) 14.6%
(2) 29.2%
(3) 58.4%
(4) 87.5%

Answers

The percentage composition by mass of nitrogen in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is \boxed{\left( 2 \right){\text{ 29}}{\text{.2 \% }}}.

Further explanation:

The most commonly applied concentration terms are as follows:

1. Molality

2. Mole fraction

3. Molarity

4. Parts per million

5. Mass percent

6. Volume percent

7. Percentage composition

The given compound is {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}. It contains two atoms of nitrogen, eight atoms of hydrogen, one atom of carbon and three atoms of oxygen.

The mass of nitrogen in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} can be calculated as follows:

{\text{Mass of N}} =\left( {{\text{Number of nitrogen atoms}}} \right)\left( {{\text{Molar mass of nitrogen}}} \right)              …… (1)

The number of N atoms in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is 2.

The molar mass of nitrogen is 14.01 g/mol.

Substitute these values in equation (1).

 \begin{aligned}{\text{Mass of nitrogen}} &= \left( {\text{2}} \right)\left( {{\text{14}}{\text{.01 g/mol}}} \right)\n&= 28.02{\text{ g/mol}}\n\end{aligned}

The formula to calculate the percentage composition of N in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is as follows:

{\text{\%  composition of N}} = \left( {\frac{{{\text{Mass of N}}}}{{{\text{Mass of }}{{\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)}_{\text{2}}}{\text{C}{{\text{O}}_{\text{3}}}}}} \right){\text{100 \% }}                                       …… (2)

The mass of N is 28.02 g/mol.

The mass of {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is 96.0 g/mol.

Substitute these values in equation (2).

\begin{aligned}{\text{\%  composition of N}} &= \left( {\frac{{{\text{28}}{\text{.02 g/mol}}}}{{{\text{96}}{\text{.0 g/mol}}}}} \right){\text{100 \% }}\n&= {\text{29}}{\text{.1875 \% }} \n &\approx {\text{2}}{\text{.92 \%}}\n\end{aligned}  

Therefore the percentage composition by mass of nitrogen in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is 29.2 %.

Learn more:

  1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603
  2. What is the concentration of alcohol in terms of molarity? brainly.com/question/9013318  

Answer details:

Grade: Senior School

Chapter: Concentration terms

Subject: Chemistry

Keywords: (NH4)2CO3, N, nitrogen, mass, 2.92 %, 96.0 g/mol, 28.02 g/mol, nitrogen, hydrogen, carbon, oxygen, mass of N, mass of (NH4)2CO3.

The % composition of nitrogen is 29.166% ~ 29.2%. Thus option 2 is correct.

The percent composition of nitrogen in ammonium carbonate can be calculated as:

% Composition = \rm (mass\;of\;element)/(mass\;of\lcompound)\;*\;100

Mass of nitrogen in the compound has been:

Number of Nitrogen atoms = 2

Mass of 1 nitrogen atom = 14 g/mol

Mass of 2 nitrogen atom = 28 g/mol

Mass of compound = 96 g/mol

% Composition of nitrogen = \rm (28)/(96)\;*\;100

% Composition of nitrogen = 29.166 %

The % composition of nitrogen is 29.166% ~ 29.2%. Thus option 2 is correct.

For more information about the percent composition, refer to the link:

brainly.com/question/17505281