What is the mole ratio of hydrogen to ammonia?N2 + 3H2 ---> 2NH3

1:1
1:2
3:2
5:4

Answers

Answer 1
Answer:

Answer: The mole ratio of hydrogen to ammonia is 3 : 2

Explanation:

Mole ratio is defined as the ratio of number of moles of the substances whose ratio is to be calculated.

In a chemical reaction, the stoichiometric coefficients represents the number of moles.

For the given chemical reaction of production of ammonia follows:

N_2+3H_2\rightarrow 2NH_3

By stoichiometry of the reaction:

1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

So, the mole ratio of hydrogen to ammonia in a given chemical reaction is 3 : 2

Answer 2
Answer:

The mole ratio of hydrogen to ammonia is 3:2.

The mole ratio of hydrogen to ammonia can be determined by examining the balanced chemical equation for the reaction:

N₂ + 3H₂ ⇒ 2NH₃

From the equation, we can see that 3 moles of hydrogen react with 1 mole of nitrogen to produce 2 moles of ammonia.

The coefficients in the balanced equation represent the mole ratio between the reactants and products. Here's a breakdown:

For every 1 mole of nitrogen, require 3 moles of hydrogen.

These 3 moles of hydrogen will react with 1 mole of nitrogen to produce 2 moles of ammonia.

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Four processes that change rock from one type to another.

Answers

Erosion
waethring
deposition
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A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature?A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.

Answers

The correct answer for the question that is being presented above is this one: "A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container." A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. The final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature is that A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.

Final answer:

By using the ideal gas law and molar mass calculations, the final volumes are found to be A. 65.0 L, B. 8.75 L, and C. 27.5 L.

Explanation:

To calculate the final volume when additional O2 is added or when some O2 is removed, we can use the concept of the molar mass and the ideal gas law that states that volume is directly proportional to the amount of gas, assuming pressure and temperature is constant.

The molar mass of O2 is approximately 32.00 g/mol.

A. 0.500 moles of O2 is added. This equals 0.500 * 32 g = 16 g. The total mass in the system is now 20.8 g. If the original 15.0 L represented 4.80 g, now 20.8 g would represent 15.0 L * 20.8/4.80 = 65.0 L.

B. 2.00 g of O2 is removed. So, the total mass in the system is now 2.80 g. If the original 15.0 L represented 4.80 g, now 2.80 g would represent 15.0 L * 2.80/4.80 = 8.75 L.

C. 4.00 g of O2 is added. So, the total mass in the system is now 8.80 g. If the original 15.0 L represented 4.80 g, now 8.80 g would represent 15.0 L * 8.80/4.80 = 27.5 L.

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Which information about a chemical reaction is provided by a potential energy diagram?

Answers

An energy profile of a reaction tells you whether it's endothermic or exothermic, the energy of the products and reactants, the activation energy needed for the forward (Ea) and reverse (Ea') reactions, the change in energy (∆E), and the energy of the activated complex.

How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? Show all of the work used to find your answer.Ca + Cl2 CaCl2

Answers

The balanced chemical reaction is:

Ca + Cl2 =  CaCl2

We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.

56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction

Answer:

31.36 L of chlorine gas will react with 56 g of calcium.

Explanation:

Ca + Cl_2\rightarrow CaCl_2

Mass of calcium = 56 g

Moles of calcium gas = (56 g)/(40 g/mol)=1.4 moles

According to reaction, 1 mole of calcium react with 1 mole of chlorine gas.

Then 1.4 mol of calcium wiull react with :

(1)/(1)* 1.4 = 1.4 mol chlorine gas

At standard temperature and pressure. 1 mol of gas occupies 22.4 L of volume.

Then 4.1 moles of chlorine gas will occupy :

22.4 L\tmes 4.1 =31.36 L

31.36 L of chlorine gas will react with 56 g of calcium.

Can someone tell me about kinetic, potential, and gravitational energy?

Answers

Answer:

the internet can teach you alot about all 3 things

Explanation:

Answer:

if you go on YT and search  kinetic, potential, and gravitational energy their will be a bill nye vid that is very informational on the topic at hand!!!

Explanation:

hope this helps!!

Select all that apply. A beta particle:

1.) is electromagnetic energy
2.) is an electron
3.) has zero charge
4.) is emitted from the nucleus
5.) has a +2 charge
6.)has a -1 charge

Answers

Answer: 2, 4, 6

Explanation: A beta particle is a high energy electron, emitted from the radioactive disintegration of an atomic nucleus. It has a -1 charge.