The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 3.00 g of butane?

Answers

Answer 1

Answer: First, calculate the number of mols of C4H10 in 3.00 g of C4H10.

3.00g C4H10 / 58.1 g C4H10 = .0516 mol C4H10
There are 4 atoms of carbon per mol of C4H10
Multiply .0516 mol C4H10 by 4 (number of atoms of carbon)=.20654 mol Carbon.
To convert to atoms, multiply that by avogadro's number, 6.022 x 10^23
which equals 1.2438 x 10^23 atoms of Carbon

Answer 2

Answer:

Answer:

1.2433 *10^23 carbon atoms

Explanation:

First you need to calculate the grams of the empirical formula.

C4H10

Carbon = 12.01 g x 4

Hydrogen = 1.008 x 10

Sum those together to get = 58.12 g

Divide the 3.00g by the total g in the compound.

3.00/58.12 = 0.0516

Then times 0.0516 by the number of carbon atoms

0.0516 x 4 = .20646

Then multiple by Avogadro's number

.20646 x 6.022x10^23 = 1.2433x10^23

Rounded to 1.24x10^23 carbon atoms

0.087 g/mL

Explanation:

The density of a substance can be found by using the formula

$density = (mass)/(volume)$

From the question

mass of liquid = 2.6 g

volume = 30 mL

The density is

$density = (2.6)/(30) \n = 0.08666666...$

We have the final answer as

0.087 g/mL

Hope this helps you

In which laboratory process could a student use 0.10 M NaOH(aq) to determine the concentration of an aqueous solution of HBr?(1) chromatography
(2) decomposition of the solute
(3) evaporation of the solvent
(4) titration

Answers

Answer:

4) titration

Explanation:

Titration is a standard process used in a laboratory to determine the concentration of an unknown analyte. A titrant of known concentration is gradually added to a known volume of the analyte in the presence of a suitable indicator. The end of the titration is marked by a color change of the analyte.

The given example is that of an acid(HBr) - base(NaOH) titration which can be represented by the following equation:

NaOH + HBr → NaBr + H2O

Thus 1 mole of acid gets neutralized by 1 mole of the base to form 1 mole of the salt (NaBr)

Let M1 and V1 are the molarity and volume of the base (NaOH). Here, the molarity of NaOH is known = M1 = 0.10 M and the volume, V1 corresponds to the end point in the titration.

M2 and V2 are the molarity and volume of HBr. Here, V2 is known whereas M2 needs to be determined.

Based on the reaction stoichiometry:

moles of NaOH = moles of HBr

$M1*V1=M2*V2\n\nTherefore,\n\nM2 = (M1*V1)/(V2)$

(4) titration, the process of using an aqueous solution of known concentration to determine the concentration of another solution of unknown concentration, is your answer.

How do you find the volume occupied by 454 grams of copper if the density equals 8.92 g/mL?

Answers

V=M/P
M=454g
p=8.92
v=50.896860986
3 significant figures
v= 50.9

Final answer:

The volume occupied by 454 grams of copper, given a density of 8.92g/mL, can be calculated using the formula for density (Density = Mass / Volume). When rearranged to find volume (Volume = Mass / Density) and substituting the given values, the volume occupied is approximately 50.9 mL.

Explanation:

When calculating volume in chemistry, we use the formula for density, which is: Density = Mass / Volume. In this case, the given values are mass (454g) and density (8.92g/mL). If we rearrange the formula to solve the volume, we get: Volume = Mass / Density. So, if we substitute the given values into the equation, we obtain: Volume = 454g / 8.92g/mL. In performing the operation, we get approximately 50.9 mL. Hence 454 grams of copper occupy 50.9 mL of volume.

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Name at least three types of energy associated with a microwave

Answers

I'm pretty sure what you are trying to ask for is radiative energy, light energy, and electronic energy.
Radiative since the microwave is releasing radiation,
Light since there is light inside the microwave,
Electronic since it is plugged in and uses electricity.
You can also use sound, but I don't think every microwave makes sound.

According to the following balanced equation, 2 formula units of Iron (III) Oxide (Fe2O3) can be formed by reacting 4 atoms of iron (Fe) with 3 molecules of oxygen gas (O2). If 12 atoms of iron are reacted with 6 molecules of oxygen gas, which is the limiting reactant and how many atoms or molecules will be left over? 4Fe + 3O2 -> 2Fe2O3

Answers

Answer: The limiting reagent is Oxygen molecule and 4 atoms of Iron will be left over.

Explanation:

The given chemical equation is:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

By Stoichiometry of the reaction:

3 molecules of oxygen gas reacts with 4 atoms of iron.

So, 6 molecules of oxygen gas will react with = $(4)/(3)* 6=8$ atoms of iron.

As, the required atoms of iron is less than the given atoms of iron. Therefore, it is present in excess and is considered as an excess reagent.

Hence, the limiting reagent is Iron atom because it limits the formation of product.

Atoms left remaining at the end of the reaction will be = 12 - 8 = 4 atoms.

Thus, the limiting reagent is Oxygen molecule and 4 atoms of Iron will be left over.

you have to use Avogadro's number (6.02x10^23 molecules/mole) to find the number of moles each reactant starts off with.
moles of Fe and O₂:
12 atoms/(6.02x10^23 atoms/mole)=1.99x10^-23 mol Fe
6 molecules/(6.02x10^23 molecules/mole)=9.967x10^-24 mol O₂
Then you find the limiting reagent by finding how much product each given amount of reactant can make. Which ever one produces the least amount of product is the limiting reagent.
amount of Fe₂O₃ produced:
(1.99x10^-23 mol Fe)x(2mol/4mol)= 9.967x10^-24mol Fe₂O₃
(9.967x10^-24 mol O₂)x(2mol/3mol)= 6.645x10^-24 mol Fe₂O₃
since oxygen produces the leas amount of product, oxygen is the limiting reagent. since we know that oxygen is the limiting reagent we can use the amount of product formed with oxygen to find the amount of iron used.
6.645x10^-24 mol Fe₂O₃x(4mol/2mol)=1.329x10^-23 mol Fe consumed
find the amount left over by subtracting the original amount of Fe by the amount consumed in the reaction.
1.993x10^-23-1.329x10^-23= 6.645x10^-23mol Fe left
find the number of atoms by multiplying that by Avogadro's number.
(6.645x10^-23mol)x(6.02x10^23 atoms/mol)=4 atoms
therefore 4 atoms of Fe will be left over after the reaction happens.

I hope this helps.

Objects 1 and 2 float as shown in the beaker below. Object 1 barely floats while 2 floats above surface. The density of the liquid in the beaker is 3.2 g/cc. Which of the densities given below are possible values for the densities of the two objects?

Answers

Object 1 is have more density than Object 2.

What is density ?

A material's density is a measure of how much stuff of a material has in a unit volume.

It is essentially a measured to see how tightly matter is crammed together or how a matter is compact.

For instance wood floats in water as it has lower density, while an anchor sinks as it has a higher density.

Helium balloons float in air as air has higher density than helium.

A specific gravity which is a related term to density otherwise called as relative density of a material.

It is the ratio of the density of a material to the density of water.

If the specific gravity of an object is less than one will float in water, where as specific gravity greater than one means it will sink. Hence object 1 has more density.

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Objects 1 and 2 float as shown in the beaker below. Object 1 barely floats while 2 floats above surface. It means that Object 1 is denser than Object 2.

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