CHEMISTRY HIGH SCHOOL

How many particles are in 3 moles?

Answers

Answer 1
Answer:

\rm 1.81* 10^2^4 number of particles are present in 3 moles.

What are moles?

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

1 mol =

We know that 1 mol = 6.02* 10^2^3

so, 3 mol =

3 mol* (6.02* 10^2^3 )/(1 mol) = 1.81* 10^2^4 particles.

Thus, the number of particle is \rm 1.81* 10^2^4

Learn more about moles, here:

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Answer 2
Answer: We know that 1 mol= 6.02*10^23 particles.

3 mol* (6.02*10^23 particles/ 1 mol)= 1.81*10^24 particles.

The final answer is 1.81*10^24 particles~

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Answers

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Answers

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D

Explanation:

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Answers

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A gas contained in a steel tank has a pressure of 1.5 atm at a temperature of 320 k. what will be the gas pressure when the temperature changes to 450 k? a gas contained in a steel tank has a pressure of 1.5 atm at a temperature of 320 k. what will be the gas pressure when the temperature changes to 450 k? 1.5 atm 0.47 atm 0.94 atm 2.1 atm 1.1 atm

Answers

Using Gay-Lussac's Law, we have
P2 = ((T2)X(P1))/(T1)
where, P and T stands for pressure and temperature respectively, terms 1 and 2 indicates initial and final pressure/temperature respectively.

Given that, P1 = 1.5 atm, T1 = 320 K, T2 = 450 K,
∴P2 = ((450)X(1.5))/(320) = 2.1 atm

Final answer:

Using Gay-Lussac's Law, we calculate that when the temperature of a gas increases from 320 K to 450 K, the pressure of the gas will increase from 1.5 atm to 2.1 atm, assuming the volume and the amount of gas remain constant.

Explanation:

To answer the question, we need to use the concept in physics called Gay-Lussac's Law. This law states that the pressure of a given amount of gas held at a constant volume is directly proportional to the Kelvin temperature. It's also important to remember that when we're dealing with gases, temperatures have to be in Kelvin for our calculations to work.

Given that, we know that the initial pressure (P1) is 1.5 atm, the initial temperature (T1) is 320K, and the final temperature (T2) is 450K. We want to find the final pressure (P2). According to Gay-Lussac's law, this can be calculated using the following equation: P1/T1 = P2/T2.

Thus, P2 = P1 * T2 / T1 = 1.5 atm * 450K / 320K = 2.1 atm.

So, the gas pressure will be 2.1 atm when the temperature increases from 320 K to 450 K, assuming that the volume and the amount of gas remain constant.

Learn more about Gay-Lussac's Law here:

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Answers

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What is true of the rate of radioactive decay? A. The rate is constant. B. The rate is continuously accelerating. C. The rate is continuously decelerating. D. The rate is exponentially accelerating.

Answers

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Answer:

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