(2) It has a mass of 0 and a charge of –1.
(3) It has a mass of 0 and a charge of 0.
(4) It has a mass of 4 and a charge of +2.
(2) H−Cl
(3) I−Br
(4) I−Cl
Among the presented bonds, the most polar is H-Cl.
Polarity is a separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment.
The higher the difference in electronegativity, the more polar the bond.
We will calculate the difference in electronegativity for each bond.
ΔEN = |EN(H)-EN(Br)| = |2.2-3.0| = 0.8
ΔEN = |EN(H)-EN(Cl)| = |2.2-3.2| = 1.0
ΔEN = |EN(I)-EN(Br)| = |2.7-3.0| = 0.3
ΔEN = |EN(I)-EN(Cl)| = |2.7-3.2| = 0.5
Among the presented bonds, the most polar is H-Cl.
Learn more about polarity here: brainly.com/question/8857494
(B) CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH
(C) CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH < CH₃CH₂CH₂OH
(D) HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃
(E) HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃
Answer:
83
Explanation:
eighty-three
Answer:
True
Explanation:
The complete question is:
"A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reactants. TRUE FALSE"
Collision Theory indicates that chemical reactions take place because molecules, atoms or ions collide with each other.
Furthermore, the molecules must collide effectively, that is, not all reagent collisions lead to product formation. Effective shock means that the reagent molecules have enough kinetic energy at the time of the shock for their bonds to break and product bonds to form. In addition, the molecules of the reagents must be properly oriented for the reaction to take place.
As the concentration increases, the number of shocks increases. In other words, by increasing the concentration of the reactants, the probability of collision between their molecules increases, and therefore the number of effective collisions.So the statement is true-
concentration of O₂ dissolved in H₂O can be written as ppm
ppm stands for parts per million - mg/kg
the amount of mg in 1 kg of solution
the mass of O₂ - 0.008 g
1000 mg equivalent to 1 g
therefore mass of O₂ in mg - 0.008 g x 1000 mg/g = 8 mg
the mass of water is 1000 g
1000 g is equivalent to 1 kg
mass of water in kg - 1000 g / 1000 g/kg = 1 kg
there's 8 mg of O₂ in 1 kg of water
therefore concentration of O₂ is - 8 mg/kg
also can be written as 8 ppm
answer is 8 ppm
Answer : The concentration of in parts per million is, 8 ppm
Solution : Given,
Mass of oxygen gas (solute) = 0.008 g
Mass of water (solvent) = 1000 g
First we have to calculate the mass of solution.
Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g
Now we have to calculate the concentration of in parts per million.
ppm : It is defined as the mass of solute present in one million parts by mass of the solution.
Now put all the given values in this expression, we get
Therefore, the concentration of in parts per million is, 8 ppm