Studies suggest that consumption of large amounts of red and processed meats, along with low intake of fiber and phytochemicals, may be responsible for which one of the following forms of cancer?A. Liver
B. Kidney
C. Colorectal
D. Stomach

Answers

Answer 1
Answer: C. Colorectal 

Studies suggest that consumption of large amounts of red and processed meats, along with low intake of fiber and phytochemicals, may be responsible for colorectal.




NOT:
A. Liver 
B. Kidney 
D. Stomach

Related Questions

Transferring or sharing electrons between atoms forms
Which chemical equation is correctly balanced?(1) H2(g) + O2(g)=> H2O(g)(2) N2(g) + H2(g) =>NH3(g)(3) 2NaCl(s)=>Na(s) + Cl2(g)(4) 2KCl(s) => 2K(s) + Cl2(g)
Calculate the value of ?E in joules for a system that loses 115 J of heat and has 150 J of work performed on it by the surroundings.
What role do acids and bases play in our digestion
What is the difference between a solid piece of armor and a liquid pool of armor metal?

Which statement best describes gamma radiation?(1) It has a mass of 1 and a charge of 1.
(2) It has a mass of 0 and a charge of –1.
(3) It has a mass of 0 and a charge of 0.
(4) It has a mass of 4 and a charge of +2.

Answers

The correct answer is option 3. The gamma radiation has no mass and no charge. This is produced from the release of pure energy from the nucleus. This is simply a stream of high frequency energy.

Which pair of atoms has the most polar bond?(1) H−Br
(2) H−Cl
(3) I−Br
(4) I−Cl

Answers

For the question given above, option 2 which is H-Cl pair of atoms has the most polar bond among the four of them. 

The larger the value of the electronegativity, the greater the atom’s strength to attract a bonding pair of electrons. Hydrogen has an electronegativity of 2.1, and chlorine has an electronegativity of 3.0. The electron pair that is bonding HCl together shifts toward the chlorine atom because it has a larger electronegativity value.

Among the presented bonds, the most polar is H-Cl.

What is polarity?

Polarity is a separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment.

The higher the difference in electronegativity, the more polar the bond.

We will calculate the difference in electronegativity for each bond.

  • (1) H−Br

ΔEN = |EN(H)-EN(Br)| = |2.2-3.0| = 0.8

  • (2) H−Cl

ΔEN = |EN(H)-EN(Cl)| = |2.2-3.2| = 1.0

  • (3) I−Br

ΔEN = |EN(I)-EN(Br)| = |2.7-3.0| = 0.3

  • (4) I−Cl

ΔEN = |EN(I)-EN(Cl)| = |2.7-3.2| = 0.5

Among the presented bonds, the most polar is H-Cl.

Learn more about polarity here: brainly.com/question/8857494

Pick the answer that most likely represents the substances’ relative solubilities in water.(A) CH₃CH₂CH₂CH₃ < CH₃CH₂CH₂OH < HOCH₂CH₂OH
(B) CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH
(C) CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH < CH₃CH₂CH₂OH
(D) HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃
(E) HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃

Answers

the naswer should be A

Answer:

83

Explanation:

eighty-three

A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reactants.

Answers

Answer:

True

Explanation:

The complete question is:

"A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reactants. TRUE FALSE"

Collision Theory indicates that chemical reactions take place because molecules, atoms or ions collide with each other.

Furthermore, the molecules must collide effectively, that is, not all reagent collisions lead to product formation. Effective shock means that the reagent molecules have enough kinetic energy at the time of the shock for their bonds to break and product bonds to form. In addition, the molecules of the reagents must be properly oriented for the reaction to take place.

As the concentration increases, the number of shocks increases. In other words, by increasing the concentration of the reactants, the probability of collision between their molecules increases, and therefore the number of effective collisions.So the statement is true-

The statement is true. Adding more of the reactants will increase the frequency of effective collisions between reactant given that the other reactant is supplied in excess. Adding more of the reactant will favor the forward reaction or the formation of more products.

What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. grams of H2O(l)?

Answers

concentration of O₂ dissolved in H₂O can be written as ppm

ppm stands for parts per million - mg/kg

the amount of mg in 1 kg of solution

the mass of O₂ - 0.008 g

1000 mg equivalent to 1 g

therefore mass of O₂ in mg - 0.008 g x 1000 mg/g = 8 mg

the mass of water is 1000 g

1000 g is equivalent to 1 kg

mass of water in kg - 1000 g / 1000 g/kg = 1 kg

there's 8 mg of O₂ in 1 kg of water

therefore concentration of O₂ is - 8 mg/kg

also can be written as 8 ppm

answer is 8 ppm

Answer : The concentration of O2(g) in parts per million is, 8 ppm

Solution : Given,

Mass of oxygen gas (solute) = 0.008 g

Mass of water (solvent) = 1000 g

First we have to calculate the mass of solution.

Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Now we have to calculate the concentration of O2(g) in parts per million.

ppm : It is defined as the mass of solute present in one million (10^6) parts by mass of the solution.

ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}* 10^6

Now put all the given values in this expression, we get

ppm=(0.008g)/(1000.008g)* 10^6=7.99=8ppm

Therefore, the concentration of O2(g) in parts per million is, 8 ppm

What is the molality of a solution containing 125 grams of iodine (I2) and 750 grams of CCl4? A. 1.2 m. . B. 6.57 m. . C. 0.657 m. . D. 0.12 m.

Answers

The answer is C. 0.657 m.

The molality is the number of moles of solute divided by kilograms of solvent. In a solution, solute the component which is present in lesser amount while solvent is present in greater amount. Thus, I2 is solute, and CCl4 is solvent.

So, first we need to calculate moles of I2:
Atomic mass of iodine: A(I) = 126.9
Molecular mass of iodine: Mr(I2) = 2*A(I) = 2 * 126.9 = 253.8
This means there are 253.8 g of iodine in 1 mole. So, 125 g of iodine will be in how many moles?
253.8 : 1 = 125 : x         ⇒      x = 125/253.8 = 0.493 moles

Now, let's convert amount of CCl4 in kilograms (1 kg = 1000 g):
750 g = 750/1000 kg = 0.75 kg

And now, it's only left to calculate molality of the solution:
numbers of moles of solute/kilograms of solvent = 0.493 moles/0.75 kg = 0.657 m