How do you round money to the nearest cent?Like for ex.:$2.15 to the nearest cent

Answers

Answer 1
Answer:


To round money to the nearest cent you would see in the ones place what that number is and if it is at or higher than 5 it would round up to 2.20               

Did that help any I hope so:) if not tell me I will have another strategy


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Solve 2a + 21 = 8a - 9, step by step

Answers

2a + 21 = 8a - 9

Combine like terms. 

2a + 21 = 8a - 9
-2a          -2a

21 = 6a - 9 
+9          +9

30 = 6a
6a/6 = 30/6
a = 5

Answer: a = 5

What is the inverse of the function below? f(x)= x/4 -2

Answers

The inverse of function f(x) = x/4 - 2 is:

f^(-1)(x) = 4(x + 2).

Option C is the correct answer.

We have,

To find the inverse of the function f(x) = x/4 - 2, we can follow these steps:

Step 1: Replace f(x) with y: y = x/4 - 2.

Step 2: Swap the variables x and y: x = y/4 - 2.

Step 3: Solve the equation for y.

Let's start by isolating y:

x = y/4 - 2

x + 2 = y/4 (Adding 2 to both sides)

4(x + 2) = y (Multiplying both sides by 4)

So, the inversefunction is y = 4(x + 2).

However, it's common to write the inversefunction with the variable x instead of y.

Therefore,

The inverse of function f(x) = x/4 - 2 is:

f^(-1)(x) = 4(x + 2).

Learn more about functions here:

brainly.com/question/28533782

#SPJ2

f(x)=(x)/(4)-2\to y=(x)/(4)-2\n\n\text{Interchange the y and the x}\n\nx=(y)/(4)-2\n\n\text{Solve for y}\n\n(y)/(4)-2=x\qquad|+2\n\n(y)/(4)=x+2\qquad|\cdot4\n\ny=4(x+2)

Answer:\ C.\ f^(-1)(x)=4(x+2)

A line has a slope of -4/5. Which ordered pairs could be points on a line that is perpendicular to this line? Select two options.(–2, 0) and (2, 5)

(–4, 5) and (4, –5)

(–3, 4) and (2, 0)

(1, –1) and (6, –5)

(2, –1) and (10, 9)

Answers

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{4}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{5}{4}}\qquad \stackrel{negative~reciprocal}{+\cfrac{5}{4}\implies \cfrac{5}{4}}} \n\n[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{5}) \n\n\n slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-0}{2-(-2)}\implies \cfrac{5}{2+2}\implies \cfrac{5}{4} \n\n[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{9}) \n\n\n slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-(-1)}{10-2}\implies \cfrac{9+1}{8}\implies \cfrac{10}{8}\implies \cfrac{5}{4}

Answer: Im pretty sure it answer options 1 and 5

Step-by-step explanation: 1) (-2,0) and (2,5)      5) (2,-1) and (10,9)

its on edg.

2cos^2x+sinx=2 domain restriction 0,2pi

Answers

2\cos ^( 2 ){ x } +\sin { x } =2\n \n 2\left( 1-\sin ^( 2 ){ x }  \right) +\sin { x } =2\n \n 2-2\sin ^( 2 ){ x } +\sin { x } =2

\n \n 2\sin ^( 2 ){ x } -\sin { x } +2-2=0\n \n 2\sin ^( 2 ){ x } -\sin { x } =0\n \n \sin { x } \left( 2\sin { x } -1 \right) =0

\therefore \quad \sin { x } =0\n \n \therefore \quad x=0,\quad \pi ,\quad 2\pi

\therefore \quad 2\sin { x } -1=0\n \n 2\sin { x } =1\n \n \sin { x } =\frac { 1 }{ 2 } \n \n \therefore \quad x=\frac { \pi  }{ 6 } ,\quad \frac { 5\pi  }{ 6 }

the blue lake trail is 11 3/8 miles long. Gemma has hiked 2 1/2 miles each hour for 3 hours . how far is she from the end of the trail

Answers

It is very important to look at all the information's that are given in the question. Based on those given information's the answer to the question can be easily deduced.
Length of the blue lake trail = 11 3/8 miles
                                            = 91/8 miles
Distance hiked by Gemma per hour = 2 1/2 miles
                                                          = 5/2 miles
Then
Distance hiked by Gemma in 3 hours = (5/2) * 3 miles
                                                             = 15/2 miles
Then
Distance from the end of the trail = (91/8) - (15/2) miles
                                                    = (91 - 60)/8 miles
                                                    = 31/8 miles
                                                    = 3 7/8 miles
So it can be concluded from the above deduction that the distance that is still left for Gemma to cover the trail is 3 7/8 miles. I hope there is nothing complicated in the procedure for you to not understand. 

Find the slope of the line (in the image I provided).A) Slope = (1)/(6)

B) Slope = 6

C) Slope = -(1)/(6)

D) Slope = -6

Answers

Answer:

(D)

Step-by-step explanation:

Slope : ( y2 - y1 )/( x2 - x1)

slope : ( -2 - 4 )/( - 3 + 4)

slope: ( -6 )/( 1 )

slope : -6