Mr. Galindo decided to take the family bowling. Which rational number represents the change in Mr. Galindo's bank account if he pays for three shoe rentals, three games of bowling and two large sodas?
Question 4 options:
$16.00
-$16.00
$-18.75
$18.75
Answer:
Step-by-step explanation:
Hello!
Alright, first, we will need to find the total of these items.
Shoe Rentals= $2.75
One Game of Bowling= $2.50
Large Soda: $1.50
The problem says he paid for three shoe rentals, three games of bowling, and two large sodas.
$2.75(3) + $2.50(3)+$1.50(2)=?
$8.25 + $7.50 + $3.00= $18.75
But it says which represents the change in his bank account after his purchase.
I believe your best answer here would be $-18.75
I hope this helps!
17.8
20.8
18.4
15.3
Given 4 consecutive odd numbers with a sum of 224, we can create an equation to solve for the first number (x). After calculating x = 53, we find the largest number to be 59.
This is a problem about consecutive odd integers, which are odd integers that follow each other successively. Let's denote the first odd integer as x, the second as x+2, the third as x+4, and the fourth as x+6. These are all odd because adding 2 to an odd number always results in the next odd number.
The question states that the sum of these four consecutive odd numbers is 224, so we can create the following equation: x + (x+2) + (x+4) + (x+6) = 224.
Simplify this equation to obtain 4x + 12 = 224. Then, solve for x by first subtracting 12 from both sides to get 4x = 212 and then dividing by 4 to get x = 53. Our highest odd number would be x+6 which equals 59.
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The four consecutive odd integers whose sum is 224 are 53, 55, 57, and 59. The largest of these integers is 59.
To find four constructive odd integers whose sum is 224, you first need to understand that consecutive odd integers follow a certain sequence, each increasing by 2 from the previous one. Let's label the first consecutive odd integer as 'n'. So, the four consecutive numbers will be: n, n + 2, n + 4, n + 6.
According to the problem, the sum of these four numbers equals 224:
n + (n+2) + (n+4) + (n+6) = 224.
Solve this equation to find the value of 'n'. You'll get n = 52. Hence, the numbers are 52, 54, 56, 58.
Since we are looking for odd numbers, let's start with 53 (the first odd number greater than 52) and proceed: 53, 55, 57, 59. And these four numbers do sum up to 224. Therefore, the largest number in this series is 59, our final answer.
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