Is 5mi bigger or 26,300 ft

Answers

Answer 1

Answer: 5 mi = 26400 ft.

5 mi is bigger by 100 ft.

~Evie

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Marty's cat weighs 10.4 pounds. this is 24.4 pounds less than the weight of his dog. write and solve a subtraction equation to find the weight of marty's dog.
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There is a school with 1,000 students and 1,000 lockers. On the first day of term the headteacher asks the first student to go along and open every single locker, he asks the second to go to every second locker and close it, the third to go to every third locker and close it if it is open or open it if it is closed, the fourth to go to the fourth locker and so on. The process is completed with the thousandth student. How many lockers are open at the end?

Answers

As many were opened during the time period. Jk, I don't know. This is a hard one

Hello,

answer: 31

I have make a programm in Qbasic

CONST Faux = 0
CONST Vrai = NOT (Faux)
CONST nb = 1000
DIM SHARED locker(nb) AS INTEGER
DIM i AS INTEGER, j AS INTEGER, answer AS INTEGER
'1 first student
FOR i = 1 TO nb: locker(i) = Vrai: NEXT i: ' CALL See
'2 2nd student
FOR i = 2 TO nb STEP 2: locker(i) = Faux: NEXT i: 'CALL See
FOR j = 3 TO nb
    FOR i = j TO nb STEP j
        locker(i) = NOT (locker(i))
    NEXT i
    'CALL See
NEXT j
answer = 0
FOR i = 1 TO nb
    IF locker(i) THEN answer = answer + 1
NEXT i
PRINT "answer="; answer
END

SUB See

SHARED locker() AS INTEGER
DIM i AS INTEGER
locker(0) = 0
FOR i = 1 TO nb
    PRINT locker(i);
    IF locker(i) THEN locker(0) = locker(0) + 1
NEXT i
PRINT locker(0)

END SUB

If f(x)= 2x, find f(-3)
please help, I'm so confused ;-;

Answers

Answer:

-6

Step-by-step explanation:

2 x -3 = -6

hope this helped

you began membership in a new health and fitness club which has access to a dietician and personal trainer. They help you develop a special eight-week diet and exercise program. The data in the following table represents your weight, w, as a function of time, t, over an eight-week period. Time (weeks) 0 1 2 3 4 5 6 7 8 Weight (lb) 150 144 143 141 140 137 137 132 129. If you lost 13 pounds in the first five weeks, what is the average rate of change of weight with respect to time over the first five weeks of the program?

Answers

Time (weeks) 0 1 2 3 4 5 6 7 8
Weight (lb) 150 144 143 141 140 137 137 132 129

Change in time (weeks) = 5 - 0 = 5 = -0.3846
Change in weight (lbs) 137 -150 -13

The average rate of change of weight with respect to time over the first five weeks of the program is -0.3846. It is a negative sign because the weight is decreasing.

Answer:

On e2020 the correct answer is D -2.6 pounds per week

Step-by-step explanation:

I just took the test.

Calculate the volume of the cylinder

Answers

Answer:

200 m³

Step-by-step explanation:

The volume of cylinder = π · r² · h

We Know

Area of circle = 25 m²

h = 8 m

We take

25 x 8 = 200 m³

So, the volume of the cylinder is 200 m³.

The area of a square is found by squaring one of its sides, (A = s2). A certain square has an area of z2 + 18z + 81. Factor the trinomial to find a side of the square.a. side = z + 27
b. side = z + 18
c. side = z + 9

Answers

A = s²
A = z² + 18 z + 81
z² + 18 z + 81 = z² + 9 z + 9 z + 81 = z ( z + 9 ) + 9 ( z + 9 ) =
= ( z + 9 ) ( z + 9 ) = ( z + 9 )²
Answer:
C ) side = z + 9

Answer:

option c is correct.

side = z+9

Step-by-step explanation:

Area of a square(A) is given by:

$A = s^2$

where,

s is the side of the square.

As per the statement:

A certain square has an area of $z^2 + 18z + 81.$

⇒ $A = z^2 + 18z + 81$

Substitute in [1] we have;

$z^2 + 18z + 81 = s^2$

Taking square root both sides we have;

$√(z^2 + 18z + 81) =s$

Using identity rule:

$(a+b)^2 =a^2+2ab+b^2$

then;

$√(z^2 + 2(1)(9)z + 9^2) =s$

⇒ $√((z+9)^2) =s$

Simplify:

$z+9 = s$

s = z+9

Therefore, a side of the square. is, z+9

Ben purchased lunch today at the school cafeteria for $2.75. Before today, Ben owed $9.15 on his lunch account. What is the status of his lunch account after today?