Can anyone do question 25 part c? :)
Can anyone do question 25 part c? :) - 1

Answers

Answer 1
Answer: \begin{cases}x^3\qquad\qquad\ \ \  when\ x\geq3\n5\qquad\qquad\quad \ when\  0\ \textless \ x\ \textless \ 3\nx^2-x+2\quad\ when\ x\leq0 \end{cases}\n\n\n (a)\n f(0)\iff x=0\implies f(x)=x^2-x+2\n\nf(0)=0^2-0+2=2\n\n(b)\n \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\n\n f(2)=5\quad\wedge\quad f(1)=5\n\n f(2)-f(1)=5-5=0

(c)\n \big\forall \limits_( n\in R)\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_( n\in R)\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \  f(x)=x^2-x+2\n\nf(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2

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1 point Solve the equation for x. Show your work on scratch paper or on a blank page in your workbook. 4x + 9 = 12 Give your answer in the form x = 1​

Answers

Answer: x = 3/4

Step-by-step explanation:

4x + 9 = 12

     - 9   - 9

4x = 3  Divide by 4 on both sides.

x = 3/4

Answer:

x = 3/4

Step-by-step explanation:

4x + 9 = 12

Step 1. subtract 9 from both sides

4x + 9 = 12

     - 9     - 9

4x = 3

Step 2. divide by 4 to isolate x

4x = 3

/4     /4

x = 3/4

Which of the following functions has the largest value when x = 3?c(x) = 3x2 + 5x + 22
j(x) = 12x
a(x) = 9x

All the functions are equal at x = 3.
c(x)
j(x)
a(x)

Answers

Answer:

  c(3) is the largest

Step-by-step explanation:

For positive values of x, j(x) > a(x), so the comparison is between c(x) and j(x).

Without evaluating the functions, you can subtract 5x from them to get ...

  c'(x) = c(x) -5x = 3x² +22

  j'(x) = j(x) -5x = 7x

Now the question is whether c'(3) is larger than j'(3). The latter is ...

  j'(3) = 7·3 = 21

Since c'(3) has an added constant of 22 and x² will be positive, we know that ...

  c(3) > j(3) > a(3)

The function with the largest value at x=3 is c(x).

_____

You can, of course, simply evaluate the functions:

  • c(3) = (3·3 +5)·3 +22 = 14·3 +22 = 42 +22 = 64
  • j(3) = 12·3 = 36
  • a(3) = 9·3 = 27

  c(3) > j(3) > a(3) . . . . . . . c(3) is the largest

Answer:

It’s D

Step-by-step explanation:

a(x)

Find an EQUATION for the tangent line to the graph at the specified value of x: y = xcos(3x) for x = pi

Answers

The line [ y = - pi ] is tangent to that function where x=pi .

What percent of your pre-retirement earnings do most financial advisors say you'll need to comfortably maintain your pre-retirement standard of living?60%
70%
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Answers

70%

probably could've just googled this lol

Answer: 70%

Step-by-step explanation:

I need help with this math question on my study guide!Sadly, I do not remember how to do this and I would greatly appreciate any help you can offer.

Answers

Sadly is right.  You must have practiced this stuff in middle school
until it was coming out of your ears.  Fortunately, you have a chance
to relearn it now.  You should do that ... it'll be important in any math
course you ever take.

'm' is the slope of the line on the graph.

The slope is

                (the change in 'y' between any two points on the line)
divided by
               (the change in 'x' between the same two points).

You can choose any two points on the line, and the slope is always the same.

To make it easy, look at the two points on this graph where the line crosses
the x-axis and the y-axis.

Going between these two points ...
-- the line goes up, from  y=0  to  y=4.  The change in 'y' is  4 .
-- the line goes to the right, from  x=-2  to  x=0.  The change in 'x' is  2 .

           'm' = the slope  =  (4)/(2)  =  2 .

The  "y-intercept"  is the place where the line crosses the y-axis.
On this graph, that's the point where  y=4 .

The equation of EVERY straight line on ANY graph is:

                 Y  =  (the slope) times 'x'  +  (the y-intercept) .

So the equation of THIS line on THIS graph is

                 Y = 2x + 4 .
 

Seperate the number 53 into 3 parts so that the second number is 3 less than the first number and the third number is twice the first number. Give the value of the second number.

Answers

Hello,

Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3

Proof: a+b+c=15.9+5.3+31.8=53

The second number is 5.3