Least common shape for a galaxy is

Answers

Answer 1
Answer: The least common shape for a galaxy is cluster.Galaxy, by definition, is an arrangement composing of stars, planets, gassesand everything more that can be seen in the space. There are three types ofgalaxies and they are elliptical, spiral and irregular. Spherical could beapplicable as elliptical if you got to choose only one on the choices above. Exampleof spiral galaxy is the Milky Way galaxy where our Solar system is currentlylocated according to the scientists. 
Answer 2
Answer:

Answer:

cluster

Explanation:


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Chọn phát biểu đúng. Trong công thức của chuyển động thẳng nhanh dần đều: A. v luôn luôn dương. B. a luôn dương.
C. a luôn cùng dấu với v. D. a luôn ngược dấu với v.

Answers

Answer:

B.

Explanation:

If anyone knows how to do any of these PLEASE help me....im am so confused rn and our teacher sucks at explaining this stuff......

Answers

take 68.2/60 = 1.137 hr
take 56.9/1.137 = 50.043 mi/hr

take 189/211 = 0.896

24.8/2 = 12.4 m
12.4/82.3 = 0.15s

Well, five answers for only five points is pretty slim.  But I've already got
a lot of points, and your plea for help sounds so desperate, that I think
I ought to jump in here and relieve some of your pain.

These aren't difficult problems.  The bummer is that whoever wrote them
got so interested in his dinosaur stories that he kind of hid the actual Math
and Physics under all kinds of stuff that doesn't matter.

1).     Speed  =  (distance covered) / (time to cover the distance)

                       =    (56.9 miles)  /  (68.2 minutes)

                       =      (56.9 / 68.2)  miles/minute

                       =          0.834  mile per minute.

BUT ... the question wants to know the speed in 'mph' ... miles per hour.

Well ... there are 60 minutes in an hour.  If 0.834 mile in covered in 1 minute,
then 60 times as much would be covered in 1 hour.

                    (0.834 mile/minute)  x  (60 minute/hour)  =  50.06 mile/hour

                     
            Rounded to no decimal places  =  50 mph


2).  Use the same formula:

         Speed  =  (distance covered) / (time to cover the distance)

                       =    (189 meters)  /  (211 seconds)

                       =      (189 / 211)  meters/seconds

                       =          0.8957 meters/second

     Round to 3 decimal places:      0.896  m/s


3).  The attacker jumped from 24.8 meters away.
       He already covered half of the distance.
       How far away is he now ?      1/2 of 24.8 m  =  12.4 m .
       He still has 12.4 meters left to go.

       He's moving at 82.3 meters per second.
       When will he arrive here ?

       Time  =  (distance)  /  (speed)

                  =      (12.4 meters)  /  (82.3 m/s)

                  =          (12.4 / 82.3)  seconds

                  =              0.1506 second

       Two decimal places:    0.15 second


4).    Distance  =  (speed) x (time)

                          =  ( 237 km/hr)  x (16.8 seconds) .

Do you see the problem here ?  We have the distance covered in an hour,
but we need to know how much distance is covered in only 16.8 seconds.
We really need to work out the speed in (meters per second).

OK.  237 km = 237,000 meters, so the speed is  237,000 meters/hour.

1 hour is 3,600 seconds. 
So the speed is only one 3600th of 237,000 meters in 1 second.

           (237,000 meters/hour) x (1 hour / 3600 seconds)  =  65.8333 m/s

           Distance  =  (speed)  x  (time)

                            =  (65.8333 meter/second)  x  (16.8 seconds)

                            =   (65.8333 x 16.8)  meters

                            =      1106 meters.     


5).  This is a nasty trick question.  The whole story is irrelevant,
and we don't even care how far Vinny dropped.

Anything that drops on Earth falls with the acceleration of gravity.
It doesn't matter how big or heavy or small or light it is.
Everything falls with the acceleration of gravity on Earth ...  about   9.8 m/s²  .

A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object?

Answers

The total work done is 957.56 joules. This is calculated as work is equal to 25N time 50 meters time cosine 40 degrees.

Answer:

Work being done on the object = 766.04J

Explanation:

Work done by a force  is calculated by finding dot product of force and displacement.

            W = F . s

             F = 25 N

              s = 50 m

               θ = 40.0°

W = F . s = Fs cosθ = 25 x 40 x cos 40 = 766.04J

Work being done on the object = 766.04J

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm3. If the combustion of this mixture releases 950. J of energy, to what volume will the gases expand against a constant pressure of 650. torr if all the energy of combustion is converted into work to push back the piston

Answers

The given system is a constant pressure systemwhere the work done is the product of the pressure and the volume change.

  • The volume to which the gas expands to is approximately 11 liters

Reasons:

Given parameters;

The original volume, V₁ = 40 cm³

The energy released, E = 950 J

Constant pressure applied, P = 650 torr.

Condition: All energy is converted to work to push back the piston

Required:

The volume to which the gas will expand

Solution;

The work done, W = Energy releases, E = 950 J

Work done at constant pressure, W = P·(V₂ - V₁)

Where;

V₂ - The volume to which the gas will expand

Converting the volume to from cm³ to m³ gives;

V₁ = 40 cm³ = 0.00004 m³

Converting the pressure given in torr to Pascals gives;

650 torr. = 86659.54 Pa.

Therefore, we get;

950 J = 86659.54 Pa. × (V₂ - 0.00004 m³)

V_2 = (950 \, J)/(86659.54 \, Pa) + 0.00004 \, m^3 = (2888)/(263445)  \ m^3 + 0.00004 \, m^3 = (2683)/(243855)  \, m^3

Converting to liters gives;

V_2 =(2683)/(243855)  \, m^3 * (1,000 \, l )/(m^3)  \approx 11.00244\, l \approx 11 \, l

  • The volume to which the gas expands, V₂ ≈ 11 liters.

Learn more here:

brainly.com/question/2139620

Answer:

The volume needed to expand the gas is = 11 Lit = 11000 cm^(3)

Explanation:

Given :

Initial volume V_(1)  = 40 cm^(3) = 0.04 Lit.

Energy W = 950 J = 9.38 Lit × atm.   ⇒ ( 1 Lit×atm. = 101.325 J )

Pressure P = 650 torr = 0.855 atm. ⇒ ( 1 torr = 0.00132 atm )

In this example we have to be aware of unit conversion system.

From the laws of thermodynamics,

 W = P \Delta V  

Here in this example, all the energy of combustion is converted into work to push back the piston

W = P (V_(2) - V_(1) )

V_(2) - 0.04 = 10.96

V_(2) = 11 Lit = 11000 cm^(3)

5) A speeding car sees a deer and slams on his breaks. He changes his speed from 30 m/s to zero with anacceleration of-3 m/s/s. How long does it take the car to stop?

Answers

Answer:

space without opposite should be served

An electron travels with speed 6.0 106m/s between the two parallel charged plates shown in the figure. The plates are separated by 1.0 cm and are charged by a200 V battery.What magnetic field strength will allow the electron to pass between the plates without being deflected?

Answers

The magnetic field strength will allow the electron to pass between the plates without being deflected is 0.0033 T.

Electric field strength

The electric field strength of the electron is calculated as follows;

E = V/d

E = 200/(0.01)

E = 20,000 V/m

Magnetic field strength

The magnetic field strength is related to electric field in the following formula;

qvB = qE

vB = E

B = E/v

B = (20,000)/(6 x 10⁶)

B = 0.0033 T

Thus, the magnetic field strength will allow the electron to pass between the plates without being deflected is 0.0033 T.

Learn more about magnetic field here: brainly.com/question/7802337

Answer:

3.3 mT

Explanation:

First of all, we need to find the strength of the electric field between the two parallel plates.

We have:

\Delta V=200 V (potential difference between the two plates)

d=1.0 cm=0.01 m (distance between the plates)

So, the electric field is given by

E=(\Delta V)/(d)=(200 V)/(0.01 m)=2\cdot 10^4 V/m

Now we want the electron to pass between the plates without being deflected; this means that the electric force and the magnetic force on the electron must be equal:

F_E = F_B\nqE=qvB

where

q is the electron charge

E is the electric field strength

v is the electron's speed

B is the magnetic field strength

In this case, we know the speed of the electron: v=6.0\cdot 10^6 m/s, so we can solve the formula to find B, the magnetic field strength:

B=(E)/(v)=(2\cdot 10^4 V/m)/(6.0\cdot 10^6 m/s)=0.0033 T=3.3 mT