CHEMISTRY HIGH SCHOOL

What are bonds?
stocks
dividends
certificates of deposit
loans

Answers

Answer 1

Answer:

loans would be the answer

Answer 2

Answer:

Answer:

loans

Explanation:

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How many liters of oxygen at stp are needed to react with 5.2 * 10 to the 22nd power molecules of hydrogen sulfide?

Answers

For the reaction H2S + 2 O2 -> H2SO4

starting with 5.2 x 10^22 molecules of H2S we can calculate the number of moles H2S by dividing by 6.02 x 10^23

We have 0.086 moles H2S

1 mole of H2S reacts with 2 moles of O2 so we need 0.17 moles of O2

1 mole of all gases at stp occupy 22.4 liters of space

.17 x 22.4 = 3.08 liters of O2 needed to react with 5.2 x 10^22 molecules of H2S

What does it mean in terms of strength when the ph of an acid changes from 5 to 4?

Answers

If the pH of acid changes from 5 to 4, it means the level of acidity has increases. There is increased Hydrogen ion concentration.

Can someone pls help me I appreciate it

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Answer:

b, e, f

Explanation:

Liquid petrol does not ignite spontaneously in air

Answers

The statement "Liquid petrol does not ignite spontaneously in air" is true. It needs a light nenergy or a spark for the combustion reaction to occur. Without it, it would not ignite spontaneously in air

Write the balanced equation for the reaction given below: C2H6 + O2 --> CO2 + H2O. If 16.4 L of C2H6 reacts with 0.980 mol of O2, how many liters of carbon dioxide gas will be produced? What is the limiting reagent? How many oxygen atoms will be in this sample of carbon dioxide? How many moles of the excess reactant will be left over? How many grams of the excess reactant will be left over?

Answers

The balanced reaction: C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O

We first convert volume of C2H6 to no. of moles. We use the conditions at STP where 1 mol = 22.4 L thus,

Moles C2H6 = 16.4 L/ 22.4 L =0.7321 mol

In order to determine the limiting reagent, we look at the given amounts of the reactants.

0.7321 mol C2H6 (7/2 mol O2 / 1 mol C2H6) = 2.562 mol O2

From the given amounts of the reactants, we can say that O2 is the limiting reactant since we need 2.562 mol O2 to completely react the given amount of C2H6. The excess reagent is C2H6

To calculate for the amount of products and excess reactants:

0.980 mol O2 (2 mol CO2 / (7/2 mol O2)) = 0.56 mol CO2 (22.4 L / 1 mol ) =12.544 L CO2
0.980 mol O2 (1 mol C2H6 / (7/2 mol O2)) = 0.28 mol C2H6
Excess C2H6 = 0.7321 mol - 0.28 mol C2H6 = 0.4521 mol C2H6

We then use the molecular weight of C2H6 to convert the excess amount to grams.

0.4521 mol C2H6 (30.08 g C2H6 / 1 mol C2H6) = 13.60 g C2H6

Since the limiting reagent is O2 there will be no oxygen atoms that will be left after the reaction.

Which end of the H-F molecule will be partially positive?neither end
the fluorine end
both ends
the hydrogen end