Mr. Hoya brought 5 watermelons from his grocery store. The watermelons weighed 8.25 pounds, 9.25 pounds, 8.875 pounds, 9.625 pounds and 10.75 pounds. At the party, 153 people each ate a 0.25 pound serving of watermelon. Was the amount of leftover watermelon less than, greater than, or equal to 8.5 pounds? Explain how to solve the problem.
Answers
We have then:
We now look for the amount of watermelons that people ate.
We have then:
Therefore, the amount of watermelon remaining is:
We note that the amount of watermelon remaining is equal to 8.5 pounds.
Answer:
the amount of leftover watermelon is: equal to 8.5 pounds
The amount of leftover watermelon is equal to 8.5 pounds
Explanation:
1- getting the total weight of the watermelon:
The total weight of the watermelon will be the summation of the weights of the 5 watermelons he bought.
This means that:
Total weight = 8.25 + 9.25 + 8.875 + 9.625 + 10.75
Total weight = 46.75 pounds
2- getting the weight of the eaten watermelon:
We know that at the party, there were 153 people and each ate 0.25 of a pound of watermelon.
This means that:
amount eaten = 153 * 0.25
amount eaten = 38.25 pounds
3- getting the weight of the leftover:
weight of leftover = total weight - amount eaten
We have:
Total weight = 46.75 pounds
amount eaten = 38.25 pounds
Therefore:
weight of leftover = 46.75 - 38.25
weight of leftover = 8.5 pounds
Hope this helps :)
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Camden is making accessories for the soccer team. He uses 513.72 inches of fabric on headbands for 34 players and 2 coaches. He also uses 299.54 inches of fabric on wristbands for just the players. How much fabric was used on a headband and wristband for each player?
A painting, square in shape, is placed in a wooden frame with width of 10% of the length of the side of the paining. The painting was enlarged by 10%. By what percent is the new frame bigger than the original frame if the width of the frame remains the same?
Answers
Explanation:
let H = number of expensive high price stereo
systems
let L = number of less expensive low price
stereo systems
H +L = 50 =
3,000H + 80OL = 110,000
H = 50 - L (now replace)
3,000 (50 - L) + 800 L = 110,00
150,000 - 3,000L + 800L = 110,000
150,000 - 110,000 = 3,000L - 800L =
40,000 = 2,2OOL
L = 40,000 / 2,200 = 18.18 = 18 lower priced = =
stereo systems H = 50 - 18 = 32 higher priced stereo systems
=
=
(3,000 x 32) + (800 x 18) = 96,000 + 14,400 = 110,400
Even though the answer is not exact, if you had 33 high cost stereo systems, your inventory's cost = $112,600 which is $1,600 off
Part
How much time, in minutes, do water tank A and water tank B have to be drained in order for them to have the same amount of water?
Answers
Answer: In 20 minutes, tanks A and B will each have 120 gallons remaining in them.
Step-by-step explanation:
The equation, the amount at which they will be equal, represents the given starting amounts minus the gal/min times the unknown time in minutes, m.
220 - 5m = 180 - 3m Subtract 180 from both sides; add 5m to both sides.
220-180 -5m +5m = 180-180 +5m - 3m Combine like terms
40 = 2m Divide both sides by 2
20 = m
Check: Substitute 20 for m in the equation
220 - 5(20) = 180 - 3(20)
220 - 100 = 180 -60
120 = 120 True!
Answers
You could subtract 20 from 50 to see what you would get, and then just plug it in to double check.
Answers
so first split into two
now we can factorise each
now the inside of the bracket is the same so we can reconfigure like this
all i did was put the two outside terms together to make (r-s)
this is your answer
(r-s)(r+2t)
the object is 12 ft, what is the height of the object if the shadow is 18 ft?
Answers
Answer:
8 ft
Step-by-step explanation:
Use the direct variation equation, y = kx, where k is a constant.
Change the equation to fit the variables: L = kH
Plug in the given length of the shadow and the height of the object, then solve for k:
L = kH
27 = k(12)
2.25 = k
So, the equation is L = 2.25H
Then, plug in 18 as L, and solve for H:
L = 2.25H
18 = 2.25H
8 = H
So, when the shadow is 18 feet, the height of the object is 8 ft
Final answer:
Using the concept of direct variation, we find that the constant of variation is 2.25. Subsequent substitution in the equation reveals that the object's height when the shadow is 18ft is 8ft.
Explanation:
The question involves the concept of direct variation in mathematics. In direct variation, two quantities increase or decrease together to keep their ratio constant. This concept is given by the equation Y = kX, where Y and X are the quantities and k is a constant.
In our situation, the length of the shadow (L) varies directly with the object's height (H), i.e., L = kt. We are given that L=27ft when H=12ft, we can find the constant k by solving the equation 27ft = k * 12ft. This will get us k = 27ft/12ft = 2.25.
Now, we can determine the object's height if the shadow is 18ft. By substituting the values into the equation, we get 18ft = k * H. Substituting the value of k (2.25) will yield H = 18ft /2.25 = 8ft. Hence, the object's height when the shadow is 18ft is 8ft.
Learn more about Direct Variation here:
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B. Because 950 ÷ 40 = 24 R10, she has enough yarn for only 24 picture frames.
C. Because 950 ÷ 40 = 23 R30, she has enough yarn for only 23 picture frames.
D. Because 950 ÷ 40 = 23 R30, she has enough yarn for only 24 picture frames.
Answers
Answer:
C. Because 950 ÷ 40 = 23 R30, she has enough yarn for only 23 picture frames.
Step-by-step explanation:
950/40 = 23.75 = 23 r 30
Sara has enough for 23 frames.
Answer:
C. Because 950 ÷ 40 = 23 R30, she has enough yarn for only 23 picture frames.
Step-by-step explanation:
950/40 = 23.75 = 23 r 30
950/40 = 23.75 = 23 r 30Sara has enough for 23 frames.