PHYSICS HIGH SCHOOL

The relationship between a cathode and an anode involvesA. protons.
B. diodes.
C. electrons.
D. neutrons.

Answers

Answer 1
Answer: Cathode andanode always go together in electrochemical reactions. An example of this isthe lead battery. The lead battery contains a chemical that is involved in thechemical reaction. The chemical reaction in the battery causes a buildup ofelectrons in the anode. And because the electron buildup in the anode is full,its only place to go is the cathode. The movement of the electrons from anodeto cathode is caused by the chemical reaction present in the battery. There willbe a movement until the chemical runs out. If the chemical runs out, theelectrons stop moving. The answer is c.
Answer 2
Answer:

THE ANSWER IS *ELECTRONS* I toojk the pen foster exam! <3 hope this helps

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Which of the following is an example of pure research? Creating new elements to study their properties Producing plastics that are heat-resistant to use in ovensDetermining how to reduce rusting on metal ships and cargo carriersFinding alternatives to gasoline to fuel transportation vehicles

Answers

Creating new elements in order to study their properties is definitely pure research.
It has no earthly [known] application, since the elements don't even exist, whereas
for each of the other choices, you've stated the desired application as the reason
for the search.

A 10-meter long ramp has a mechanical advantage of 5. What is the height of the ramp?

Answers

1.       If the ramp has a length of 10 and has a mechanical advantage (MA) of 5. Then we need to find the height of the ramp.
Formula:
MA = L / H
Since we already have the mechanical advantage and length, this time we need to find the height .
MA 5 = 10 / h
h = 10 / 5
h = 2 meters

Therefore, the ramp has a length of 10 meters, a height of 2 meters with a mechanical advantage of 5.



Answer:

height=2

Explanation:

MA= input/output

MA= 5

input = 10 (the ramp)

output=x (the height)

5=10/x

x=2

If We Start With 400 Atoms of a Radioactive Substance, How Many Would Remain After One Half-life ?

Answers

If it's half life, that means that half of the atoms have died out. Therefore, 200 atoms have died, so there are 200 atoms left (exactly one half of 400)
200, the half life of a radioactive substance is pretty simple to remember. It is literally cutting it in half, however, don't make the same mistake I did in this subject, the second half life does not reduce it to 0, it reduces it to 100. It just keeps half-lifing over and over again. For example: 400 atoms after one half life:200, after two: 100, after 3, 50, and so on.

What is the velocity of the dart just before the collision?

Answers

Answer: 1.38 m/s to the right.

Explanation: We can solve this problem using the principle of conservation of momentum. The momentum of an object is defined as the product of its mass and velocity, and the total momentum of a closed system is conserved, meaning that the total momentum before a collision is equal to the total momentum after the collision.Let the initial velocity of the dart be v, and let the final velocity of the dart and the block be vf. The momentum of the dart before the collision is given by p = mv, where m is the mass of the dart. The momentum of the dart and block after the collision is given by (m + M)vf, where M is the mass of the block.Using the principle of conservation of momentum, we have:p = (m + M)vfSubstituting the given values, we get:0.012 kg v = (0.012 kg + 0.2 kg) 0.78 m/sSimplifying, we get:v = (0.212 kg) (0.78 m/s) / 0.012 kgv ≈ 1.38 m/sTherefore, the velocity of the dart just before it hits the block is approximately 1.38 m/s to the right.

Let's assume you use green light (λ = 550 nm) to look at an electron. What is the uncertainty in determining the electron's velocity? Express your answer rounded up to the nearest hundredth.

Answers

By uncertainty principle

λ = h / p.         

Where λ = wavelength,  h = Planck's constant = 6.63 * 10⁻³⁴ Js

λ = wavelength = 550 nm = 550 * 10⁻⁹ m, Mass of electron = 9.1 * 10 ⁻³¹ kg

p = Momentum = mv

λ = h / mv

v = h / mλ

v = 6.63 * 10⁻³⁴ / (9.1 * 10⁻³¹ *  550 * 10⁻⁹)

v = 1 324 675.325 m/s

v ≈ 1.325 *10⁶  m/s

Why can't we breath under water?

Answers


We can certainly draw water into our lungs, even though
our brain screams "Don't do that !".

But our lungs can only separate oxygen out of air, not out of
water.  So if there's only water in our lungs, we pass out after
a short time because we're not getting any oxygen.
Our lungs are not designed breathe oxygen from water to be able to breathe under water.
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