An unknown substance turns blue litmus paper to red. Which additional test could be used to confirm the substance’s identity? It should turn phenolphthalein from colorless to pink because it is a base. It should turn phenolphthalein from pink to colorless because it is a base. It should turn methyl orange to orange because it is an acid. It should turn methyl orange to red because it is an acid.
Answers
The substance that turns blue litmus red should turn methyl orange to red because it is an acid.
What is an acid?
An acid is a substance that produces hydrogen ions as the only positive ions when dissolved in water.
Properties of acid include :
- acids turn blue litmus red
- are corrosive
- are sour in taste
Therefore, the substance that turns blue litmus red is an acid:
It should turn methyl orange to red because it is an acid.
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If the sum of the mass of the reactants is 12.5 what would be the sum of the products be? And explain how you know this
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Answers
THE ANSWER BOI:
27 g
HERE IS DA EXPLANATION FAM:
27 g
M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol
100 mL = 0.1 L solution
1.5 M = 1.5 mol/L
1.5 mol/L * 0.1 L = 0.15 mol C6H12O6
0.15 mol * 180 g/1 mol = 27 g C6H12O6
Final answer:
To find the needed grams of glucose for a 1.5 M solution in 100ml, you multiply the molarity by the molecular weight of glucose and the volume of the solution. The calculation is 1.5 mol/l * 180 g/mol * 0.1 l = 27 grams. Therefore, 27 grams of glucose is needed.
Explanation:
The problem in question requires you to make use of the formula M= mass (mol)/ Volume (L). To find the required grams of glucose, C6H12O6, for a 1.5 M solution in 100mL, you would multiply the molarity with the molecular weight of glucose - approximately 180g per mole - and the volume of the solution - 0.1L. Therefore, to solve the problem you would calculate it as: 1.5 mol/l X 180 g/mol x 0.1 l which equals 27g. Hence, you need 27 grams of glucose to make a 100ml, 1.5M solution.
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Answers
relative weight of Mg3N2 = (3x24)+(2x14) = 100 g/mole
mole of Mg3N2 = 10,3 g/100 g/mole = 0,103 mole
mole of NH3(g) = 2/1 x 0,103 mole = 0,206 mole
volume NH3(g) which collected at STP = mole NH3(g) x 22,4 litre/mole = 0,206 mole x 22,4 litre/mole = 4,6144 litre.
Answers
Answer: Protons
Explanation: When determining an element identity the most important Subatomic part to look at is the number of protons in the nucleus determines the identity of an atom .
2Na(s) + ZnF2(aq) + 2NaF(aq) + Zn(s)
O Fe(s) + CuCl2(aq) → FeCl2(aq) + Cu(s)
0 2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g)
Answers
Answer: will not occur.
Explanation:
A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution. Thus one element should be different from another element.
A general single displacement reaction can be represented as :
a)
Flourine is more reactive than chlorine and hence this reaction cannot occur.
b)
Sodium is more reactive than zinc and hence the reaction will occur.
c)
Iron is more reactive than copper and hence the reaction will occur.
d)
Magnesium is more reactive than hydrogen and hence the reaction will occur.
b. positive
c. negative
Answers
Answers
Final answer:
Using the combined gas law, we find that the new pressure of the gas sample, after it's compressed and heated, is approximately 353.8 kPa.
Explanation:
The subject of this question is gas laws, specifically the combined gas law which states that the ratio of the product of pressure and volume and the absolute temperature of a gas is constant. We apply this law to calculate the new pressure of the gas sample. Starting from the conditions of STP (Standard Temperature and Pressure, defined as 273.15 K and 1 atm i.e., 101.325 kPa), the volume of gas is decreased from 700.0 mL to 200.0 mL and the temperature is increased from 273.15 K to 30.0 degrees Celsius (or 303.15 K in absolute terms).
We set up the equation P1*V1/T1 = P2*V2/T2, where P1 = 101.325 kPa, V1 = 700.0 mL, T1 = 273.15 K, V2 = 200.0 mL, and T2 = 303.15 K. Plugging in these numbers and solving for P2 (the new pressure), we get P2 = P1*V1*T2 / (T1*V2) = 101.325 kPa * 700.0 mL * 303.15 K / (273.15 K * 200.0 mL) = approximately 353.8 kPa.
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