13.
For which of the following equations are x = 5 and x = –5 both solutions?

Answers

Answer 1
Answer: 10 on both sides then reduce which is negative 21

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What is the solution to the following equation? (5x-2)^2=10

Trying to figure out this for a long time. Please help!!!​

Answers

Answer:

One solution to this question could be that g(xl=x^2 and f(x)=sqrt{x+1}

Step-by-step explanation:

If g(x)=x^2, f(g(x))=f(x^2)=sqrt{x^2+1}

What is the length of BC in the right triangle below 21 and 72

Answers

Im guessing 21 and 72 are the side lengths for the triangle?

Alright, so since it's a right triangle you can use the Pythagorean theorem or a^2+b^2=c^2

Since i cant see the picture, im going to use some general math so i can figure out if those two sides are the legs or if one of them is the hypotenuse
Alright 
so im guessing the side we're trying to find is the hypotenuse

21^2+72^2=c^2
441+5184=c^2
5625=c^2
√5625=c
75=c

The answer is 75, hope i helped!

Answer:75

Step-by-step: just took the test

What radian measure is equivalent to 900°?
5n
10n
1/5n
9n

Answers

Answer: 5n

Sources: Just trust me

9n is the answer to this question

Consider the 1-to10^19 scale on which the disk of the Milky Way Galaxy fits on a football field. On this scale, how far is it from the sun to the alpa centauri (real distance:4.4 light-years) How big is the sun itself on this scale? Compare the sun's size on this scale to the actual size of a typical atom (about 10^-10 m in diameter).

Answers

Answer:

Sun is 0.4162708 cm away from alpha century.

Sun is 1.391016*10^(-10)m.

Sun is 1.391016 time the size of an atom at this scale.

Step-by-step explanation:

Light year is a measure of distance. It is the distance light travels in an year.

Light year = 9.4607*10^(12) km

So 4.4 light years = 4.4*9.4607*10^(12) km

                                41.62708*10^(12) km

Lets scale this down to the level of 1*10^(-19)

41.62708*10^(12)*1*10^(-19) km

=41.62708*10^(-7) km

Change the units to centimeters:

41.62708*10^(-7)*1*10^(5) cm

=41.62708*10^(-2) cm

=0.4162708 cm

Therefore on the new scale sun is 0.4162708 cm away from alpha century.

Diameter of the sun is 1.391016 million km

Lets change Sun's diameter to the new scale:

1.391016*10^(6) *10^(-19)km

=1.391016*10^(-13)km

Lets change kilometers in to meters:

1.391016*10^(-13)*10^(3)m

=1.391016*10^(-10)m

Therefore, sun is 1.391016*10^(-10)m

and an atom is 1*10^(-10)

Therefore the sun is 1.391016 time the size of an atom at this scale.



Final answer:

On a 1-to-10^19 scale, the distance from the Sun to the Alpha Centauri is about 44 cm. On this same scale, the Sun itself would have a diameter of about 150 picometers, which is larger than a typical atom.

Explanation:

The 1-to-10^19 scale means for every actual meter in space, we represent 10^19 meters on our model. The Alpha Centauri is 4.4 light-years away from the sun. Considering 1 light-year equals to approximately 9.46x10^15 meters, the real distance from the sun to Alpha Centauri is about 4.16x10^16 meters. So, on the scale, this is about 0.44 meters or 44 cm.

The Sun's real size, with a diameter of 1.5 million kilometers or 1.5x10^9 meters, is represented as 1.5x10^-10 meters or 150 picometers on the scale. This is much bigger than an actual atom, which has a diameter of 0.1 to 0.5 nanometers or 100 to 500 picometers. Hence, on this scale, the Sun would be larger than a typical atom.

Learn more about Scale Representation here:

brainly.com/question/38391112

#SPJ11

Can someone help me with this math homework please!

Answers

Answer:

1st, 2nd and 6th options

Step-by-step explanation:

Given

(2)/(3) - x + (1)/(6) = 6x ( multiply through by 6 to clear the fractions )

4 - 6x + 1 = 36x ← option 1 will have the same solution set

----------------------------------------------------------------------

Adding the 2 fractions on the left side gives

(4)/(6) +(1)/(6) - x = 6x , that is

(5)/(6) - x = 6x ← option 2 will have the same solution set

------------------------------------------------------------------------

From

4 - 6x + 1 = 36x ( add 6x to both sides )

5 = 42x ← option 6 will have the same solution set

In a trivia game, Levi answered 8 questions correctly out of 10 turns in the game. Then, he answered the next 3 questions correctly. He reasoned that because he added 3 the both the total questions and his correct responses, that the ratio of correct answer to total questions remained the same. Is he correct? Justify the answers

Answers

Answer:

He is not correct as the ratios are;

First ratio is 4:5,

Second ratio 11:13

Which are different values

Step-by-step explanation:

The number of correct questions Levi answered = 8 questions

The number of questions in the game = 10

The ratio of correctly answered questions to total number of questions in the first 10 question is given as follows

Correctly answered questions : Total number of questions = 8:10

Which can be simplified as 8:10 = 8/2:10/2 = 4:5

The number of correct questions Levi answered in the next three turns = 3 questions

The total number of questions attempted by Levi becomes 10 + 3 = 13 questions

The total number of correct answers given by Levi = 8 + 3 = 11 correct answers

The new ratio of correctly answered questions to total number of questions is therefore;

New correctly answered questions : Total number of questions = 11:13.

Therefore, the ratios do not remain the same as 4:5 ≠ 11:13.