Which is greater 6km or 54,000 mm

Answers

Answer 1
Answer: 1 km = 1,000,000 millimeters
6 km = 6 * 1,000,000 millimeters = 6,000,000 mm

6,000,000 mm is greater than 54.000 mm

Therefore, 6 km is greater than 54,000 mm,
Answer 2
Answer: 1 km is 1,000,000 mm. So 6k is the equivalent of 6,000,000 mm.  So 6km > 54,000mm 

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Craig has a job waiting tables where he earns $3.15 per hour plus tips. Craig earned $79.48 in tips during his shift yesterday.If x represents the number of hours Craig worked yesterday, which of the following equations can be used to find the amount of money Craig earned yesterday?

A.
y = 3.15x + 79.48
B.
y = 79.48x + 3.15
C.
y = 79.48x - 3.15
D.
y = 3.15x - 79.48

Answers

Final answer:

The correct equation to determine the amount of money Craig earned yesterday is 'y = 3.15x + 79.48', where 'y' is the total money earned, '3.15' is the hourly wage, 'x' is the number of hours worked, and '79.48' is the total tips.

Explanation:

The subject of the question is a mathematical problem related to real-world applications of linear equations. In this problem, Craig earns a fixed number of dollars per hour, $3.15, plus a fixed amount of tips, $79.48. These two groups of money create his total earnings for the day. Therefore, the equation to represent this relationship should reflect this fact by multiplying the number of hours he works, represented by 'x', by his hourly wage, and then adding his total tips.

Therefore, the correct equation is: y = 3.15x + 79.48, where 'y' represents the total amount of money Craig earned yesterday. In this equation, '3.15x' represents Craig's earnings from his hourly wage, and '79.48' represents his tips.

Learn more about Linear Equations here:

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11 billion in scientific notation

Answers

11000000000
1.1 x 10^10

Billion has 9 zeros.
11,000,000,000 = 11 billion in standard form

11 to the 9th power would be your answer

ASAP What is 7 · 2 3/7 ?

Answers

7 * 2  (3)/(7) \n \n 7 *  (2 * 7 + 3)/(7) \n \n 7 *  (14+3)/(7)  \n \n 7 *  (17)/(7) \n \n  (119)/(7) \n \n 17 \n \n Answer: \fbox {17}
2 (3)/(7) = ((2\cdot7)+3)/(7) = (14+3)/(7) = (17)/(7)

7 \cdot (17)/(7) = \boxed{\bf{17}}

Solve by substitution to find x and y

4=-x-y
2x-y=10

Answers

Hello Jay

4=-x-y

2x-y=10

We need to solve 4=-x-y for x

Now add x to both sides

4+x=-x-y+x

x+4==-y

Add -4 to both sides

x+4-4=-y-4

x=-y-4

Now we need to substitute -y-4 for x in 2x-y=10

2x-y=10

2(-y-4)-y=10

To find the result of this factor we need to simplify

-3y-8=10

Add 8 to both sides so we can start finding the y value

-3y-8+8=10+8

-3y=18

Divide both sides by -3 so we can find the y value

-3y/-3=18/-3

y=-6

Now let's find the x value by substitute -6 for y in x=-y-4

x=-y-4

x=-(-6)-4

x=2

Answer: x=2 and y=-6


I hope that's help:0

Factor then solve.
1.81 - 4x²=0
2. 4s² + 9 = 12s

Answers

1.\n81-4x^2=0\n\n9^2-(2x)^2=0\n\n(9-2x)(9+2x)=0\iff9-2x=0\ \vee\ 9+2x=0\n\n-2x=-9\ \vee\ 2x=-9\n\nx=4.5\ \vee\ x=-4.5

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2.\n4s^2+9=12s\n\n4s^2-12s+9=0\n\n(2s)^2-2\cdot2s\cdot3+3^2=0\n\n(2s-3)^2=0\n\n(2s-3)(2s-3)=0\iff2s-3=0\n\n2s=3\n\ns=1.5
1.)\ \ \ 81 - 4x^2=0\n\n9^2-(2x)^2=0\ \ \ \ \ and\ \ \ \ \ a^2-b^2=(a-b)(a+b)\n\n(9-2x)(9+2x)=0\ \ \ \Leftrightarrow\ \ \ 9-2x=0\ \ \ or\ \ \ 9+2x=0 \n\n9-2x=0\ \ \ \Leftrightarrow\ \ \ -2x=-9\ \ \ \Leftrightarrow\ \ \ x=4.5\n\n9+2x=0 \ \ \ \Leftrightarrow\ \ \ 2x=-9\ \ \ \Leftrightarrow\ \ \ x=-4.5\n\n.......................................................................\n\n

2.)\ \ \ 4s^2+ 9 = 12s\n\n4s^2-12s+ 9 =0\n\n(2s)^2-2\cdot2s\cdot3+3^2=0\n\n(2s-3)^2=0\ \ \ \Leftrightarrow\ \ \ 2s-3=0\ \ \ \Leftrightarrow\ \ \ 2s=3\ \ \ \Leftrightarrow\ \ \ s=1.5

The Idol has a mass of 2 kg how many liters of sand messy place on the pedestal to keep the mass sensitive booby trap from activating density of Sandy's 3.00 g per centimeter

Answers

Two things you still need to do before you can get an answer: 1). Post the rest of the question... the part that tells the trip point of the booby trap. ... 2). Go through the part that you already posted and correct the silly mistakes that your dictation app made, so that the question makes sense. For example: "... sand messy place ..." and "... density of Sandy's ..." and "... g per centimeter." .