What influences the Earth's tides and climate?A. Moon
B. Mars
C. the Milky Way
D. Venus

Answers

Answer 1
Answer: The moon influences the Earth's tides.

None of the items on this list of choices influences the seasons.
Answer 2
Answer: the moon influences the tides and climate

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A bike moves. 50 m in 10 seconds calculate the speed of the bike

Answers

The speed of the bike is calculated by dividing the total distance travelled by the total time taken, which in this case is 50 meters divided by 10 seconds. This yields a speed of 5 meters per second.

This involves a concept from Physics called speed.

Speed is defined as the distance covered by an object divided by the time taken to cover that distance.

Since the bike moves 50 meters in 10 seconds, to calculate the speed:

Identify the distance covered which is 50 meters.

Identify the time taken which is 10 seconds.

Divide the distance by the time to get the speed = 50 m / 10 s = 5 m/s. So, the speed of the bike is 5 meters per second.

Learn more about speed here:

brainly.com/question/22610586

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Answer:

We know that

Speed = Distance/ Time

Explanation:

  • Distance is 50 m
  • Time is 10 seconds

Speed = 50/10

= 5 m/s

Two objects have mass 8 kg and 25 kg. Which one has more inertia?""

Answers

Answer:

the 25 kg one

Explanation:

The higher the weight the higher the inertia.
lets suppose we blow wind at both of these objects at a very high rate equally, u will notice after some time depending on the strength of wind the 8kg object will probably move earlier than the 25 kg one.

I'm really confused about waves and I can't identify the period, frequency, velocity etc in a word problem. Please give examples with units!!! I'm failing science rn!!

Answers

Period is defined as the time required to complete one cycle which is also related to frequency. Period is presented by an equation P = 1/f where p is the period, and f is the frequency. The unit is in second. Frequency is defined as the number of circular revolutions in a given time interval and it is in Hertz (Hz) = 1s^-1. Velocity s defined as the arc traveled at a given time with the equation v=l/t where v is the velocity, l is the length and t is time. The unit is in m/s.

I need help ASAP.The average time that it takes for the car to travel the first 0.25m is_____

The average time to travel just between 0.25m and 0.50m is_____

Given the time taken to travel the second 0.25m section, the velocity would be____m/s

Answers

1. Average time for the first 0.25 m: 2.23 s

Explanation:

The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:

t=(2.24s+2.21s+2.23s)/(3)=2.227 s=2.23 s

2. Average time to travel between 0.25 m and 0.50 m: 0.90 s

Explanation:

First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:

t1 = 3.16 s - 2.24 s = 0.92 s

t2 = 3.08 s - 2.21 s = 0.87 s

t3 = 3.15 s - 2.23 s =  0.92 s

So, the average time is

t=(0.92 s + 0.87 s + 0.92 s)/(3)=0.903 s=0.90 s

3. Velocity in the second 0.25 m section: 0.28 m/s

Explanation:

The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):

v=(d)/(t)=(0.25 m)/(0.90 s)=0.28 m/s

Answer:

1. 2.23

2. 0.90

3. 0.28

A crane has an arm length of 20m inclined at 30deg with the vertical. It carries a container of mass of 1 ton suspended from the top end of the arm. Find the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the weight of the arm. Hint: take the force and perpendicular distance from the point where the arm is fixed to the crane. Note: Express your answer in whole number. No unit is required for the final answer. Set your calculator in radians.

Answers

To find the torque produced by the gravitational force on the container, we need to calculate the force and perpendicular distance from the point where the arm is fixed to the crane.

First, let's calculate the force exerted by the gravitational force on the container. The weight of the container can be calculated using its mass and the acceleration due to gravity. Given that the mass of the container is 1000 kg (1 ton) and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the force as follows:

Force = mass * acceleration due to gravity
Force = 1000 kg * 9.8 m/s^2
Force = 9800 N

Next, we need to find the perpendicular distance from the point where the arm is fixed to the crane to the line of action of the gravitational force. This distance can be determined using trigonometry.

The perpendicular distance can be calculated using the formula:

Perpendicular distance = arm length * sin(angle)

Given that the arm length is 20 m and the angle with the vertical is 30 degrees, we can calculate the perpendicular distance as follows:

Perpendicular distance = 20 m * sin(30 degrees)
Perpendicular distance = 20 m * 0.5
Perpendicular distance = 10 m

Now, we can calculate the torque using the formula:

Torque = force * perpendicular distance

Substituting the values we calculated earlier:

Torque = 9800 N * 10 m
Torque = 98000 Nm

Therefore, the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane is 98000 Nm.

Speed / 16.0 m/s 12.0- 8.0 4.0 0 0 0.5 1.0 1.5 time / seconds 2.0 2.5 3.0 calculate the distance that the car travels in the first 0.5 seconds calculate the distance that the car travels in the first 0.5 seconds ​

Answers

Answer: 8 m

Explanation:

From the equation distance = velocity * time, we can find the distance from a velocity vs. time graph by finding the area under the curve, since we get that area from multiplying velocity and time together.

For the first 0.5 seconds, the velocity is 16 m/s and the change in time is 0.5.

16 * 0.5 = 8 m.

Learn more about the relationship between distance and velocity here: brainly.com/question/29409777