If (-2, y) lies on the graph of y =4^x, then y =
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So, the point (-2, ¹/₁₆) lies on the graph of y = 4^x.
Your final answer is y = ¹/₁₆.
Related Questions
Simplify the expression. 12^–3 • 12^10 • 12^0A. 1 B. 1728^7 C. 12^7 D. 36^7
Solve the equation 4x-6= 34. Write a reason for each numbered step.
Please help! Math Homework! Slope Intercept form
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.
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Answer: angle 4 and angle 5
Answer:
4
5
Step-by-step explanation:
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Answer:
option H, 130°
Step-by-step explanation:
In order to find the measure of ∠ACD, first find the measure of ∠ACB
∠ACB + ∠ABC + ∠BAC = 180° (angle sum property of a triangle)
∠ACB + 95° + 35° = 180°
∠ACB + 130° = 180°
∠ACB = 180° - 130°
∠ACB = 50°
∠ACD + ∠ACB = 180° (linear pair)
∠ACD + 50° = 180°
∠ACD = 180° - 50°
∠ACD = 130°
therefore, option H is the correct option
hope it helps you!
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Answer:
x=6, 90 degree angle total?
Step-by-step explanation:
Hopefully this is a 90 degree angle, 90-60=30
30/5=6
x=6
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Answer:
140 x 180
Step-by-step explanation:
Final answer:
To find the measure of the unknown angle in a straight angle ABC, you can use the equation A = A + A. This equation is derived from the Pythagorean theorem, which relates the legs of a right triangle to the length of the hypotenuse.
Explanation:
To find the measure of the unknown angle in a straight angle ABC, you can use the equation A = A + A. This equation is derived from the Pythagorean theorem, which relates the legs of a right triangle to the length of the hypotenuse. In a straight angle, the two legs are equal, so the equation simplifies to A = 2A. Therefore, the measure of the unknown angle is twice the measure of one of the legs
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Step-by-step explanation:
These are all examples of p-series:
∑(1 / nᵖ), where p>0.
If p > 1, the series converges. If 0 < p ≤ 1, the series diverges.
First option:
∑(1/n⁵)
Here, p = 5. Since 5 > 1, the series converges.
Second option:
∑((√n+3)/n³)
∑((√n)/n³) + ∑(3/n³)
∑(1/n^2.5) + 3 ∑(1/n³)
In the first sum, p = 2.5. In the second sum, p = 3. Both are greater than 1, so the series converges.
Third option:
∑((n−4)/(n⁴√n))
∑(1/(n³√n)) − ∑(4/(n⁴√n))
∑(1/n^3.5) − 4 ∑(1/n^4.5)
In the first sum, p = 3.5. In the second sum, p = 4.5. Both are greater than 1, so the series converges.
Fourth option:
∑(1/∛n)
∑(1/n^⅓)
Here, p = ⅓. This is less than 1, so the series diverges.
Note: if a series is converging, then the limit is 0.
However, if the limit of a series is 0, it does not necessarily mean that series is converging.
Here, the limit of all 4 options is 0. However, the fourth option is a diverging series.